[ZJOI2009]取石子游戏
思路:
博弈+dp,详见yyb博客
代码:
#pragma GCC optimize(2)
#pragma GCC optimize(3)
#pragma GCC optimize(4)
#include<bits/stdc++.h>
using namespace std;
#define y1 y11
#define fi first
#define se second
#define pi acos(-1.0)
#define LL long long
#define ll long long
//#define mp make_pair
#define pb push_back
#define ls rt<<1, l, m
#define rs rt<<1|1, m+1, r
#define ULL unsigned LL
#define pll pair<LL, LL>
#define pli pair<LL, int>
#define pii pair<int, int>
#define piii pair<pii, int>
#define pdd pair<double, double>
#define mem(a, b) memset(a, b, sizeof(a))
#define debug(x) cerr << #x << " = " << x << "
";
#define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//head
const int N = 1e3 + 10;
int L[N][N], R[N][N], T, n, a[N];
int main() {
scanf("%d", &T);
while(T--) {
scanf("%d", &n);
for (int i = 1; i <= n; ++i) scanf("%d", &a[i]);
for (int i = n; i >= 1; --i) {
L[i][i] = R[i][i] = a[i];
for (int j = i+1; j <= n; ++j) {
int l = L[i][j-1], r = R[i][j-1], x = a[j];
if(x == r) L[i][j] = 0;
else if(x < r && x < l) L[i][j] = x;
else if(l <= x && x < r) L[i][j] = x+1;
else if(r < x && x < l) L[i][j] = x-1;
else L[i][j] = x;
l = L[i+1][j], r = R[i+1][j], x = a[i];
if(x == l) R[i][j] = 0;
else if(x < r && x < l) R[i][j] = x;
else if(l < x && x < r) R[i][j] = x-1;
else if(r <= x && x < l) R[i][j] = x+1;
else R[i][j] = x;
}
}
if(n == 1) printf("1
");
else if(a[1] == L[2][n]) printf("0
");
else printf("1
");
}
return 0;
}