地址:https://leetcode-cn.com/problems/maximize-sum-of-array-after-k-negations/
1 ''' 2 3 示例 1: 4 5 输入:A = [4,2,3], K = 1 6 输出:5 7 解释:选择索引 (1,) ,然后 A 变为 [4,-2,3]。 8 示例 2: 9 10 输入:A = [3,-1,0,2], K = 3 11 输出:6 12 解释:选择索引 (1, 2, 2) ,然后 A 变为 [3,1,0,2]。 13 示例 3: 14 15 输入:A = [2,-3,-1,5,-4], K = 2 16 输出:13 17 解释:选择索引 (1, 4) ,然后 A 变为 [2,3,-1,5,4]。 18 19 20 21 22 ''' 23 24 25 class Solution: 26 def largestSumAfterKNegations(self, nums: List[int], k: int) -> int: 27 newSort = sorted(nums) 28 for i in range(k): 29 newSort[0] = -newSort[0] 30 newSort = sorted(newSort) 31 return sum(newSort)
来源:力扣(LeetCode)
链接:
https://leetcode-cn.com/problems/maximize-sum-of-array-after-k-negations