112. Path Sum

1. 问题描述

 Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,
     5
    / 
   4   8
  /   /  
 11  13   4
 /        
7   2       1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.    

Tags: Tree Depth-first Search

Similar Problems: (M) Path Sum II (H) Binary Tree Maximum Path Sum (M) Sum Root to Leaf Numbers

2. 解题思路
3. 代码

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution 
{
public:
    bool hasPathSum(TreeNode* root, int sum) 
    {
        if (!root)
        {
            return false;
        }
        if (root->left == NULL && root->right == NULL && root->val == sum)
        {
            return true;
        }
        else
        {
            return hasPathSum(root->left, sum-root->val) || hasPathSum(root->right, sum-root->val);
        }
    }
};

4. 反思