lambda隐藏函数的嵌套

# 隐藏函数嵌套
f = (lambda a,b :a if a>b else b)(1000, 2000008)
print((lambda a,g:a if a > g else g)(2000,f))

# lambda 推导式
l = [lambda x:x**i for i in range(4)]
print(l[1](4))