Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and left the other as original.
Example:
Input: s = "abcdefg", k = 2 Output: "bacdfeg"
Restrictions:
- The string consists of lower English letters only.
- Length of the given string and k will in the range [1, 10000]
class Solution { public String reverseStr(String s, int k) { int n = s.length(); StringBuilder sb = new StringBuilder(); for(int i = 0; i < n; ) { if(n - i < k) { sb.append(rev(s.substring(i, n))); return sb.toString(); } else if(n - i >= k && n - i < 2*k) { sb.append(rev(s.substring(i, i+k))).append(s.substring(i+k)); return sb.toString(); } else { sb.append(rev(s.substring(i, i+k))).append(s.substring(i+k, i+2*k)); i+=2*k; } } return sb.toString(); } public String rev(String s) { return new StringBuilder(s).reverse().toString(); } }