• 1457. Pseudo-Palindromic Paths in a Binary Tree


    Given a binary tree where node values are digits from 1 to 9. A path in the binary tree is said to be pseudo-palindromic if at least one permutation of the node values in the path is a palindrome.

    Return the number of pseudo-palindromic paths going from the root node to leaf nodes.

    Example 1:

    Input: root = [2,3,1,3,1,null,1]
    Output: 2 
    Explanation: The figure above represents the given binary tree. There are three paths going from the root node to leaf nodes: the red path [2,3,3], the green path [2,1,1], and the path [2,3,1]. Among these paths only red path and green path are pseudo-palindromic paths since the red path [2,3,3] can be rearranged in [3,2,3] (palindrome) and the green path [2,1,1] can be rearranged in [1,2,1] (palindrome).
    

    Example 2:

    Input: root = [2,1,1,1,3,null,null,null,null,null,1]
    Output: 1 
    Explanation: The figure above represents the given binary tree. There are three paths going from the root node to leaf nodes: the green path [2,1,1], the path [2,1,3,1], and the path [2,1]. Among these paths only the green path is pseudo-palindromic since [2,1,1] can be rearranged in [1,2,1] (palindrome).
    

    Example 3:

    Input: root = [9]
    Output: 1
    

    Constraints:

    • The given binary tree will have between 1 and 10^5 nodes.
    • Node values are digits from 1 to 9.
    
    
    class Solution {
        public int pseudoPalindromicPaths (TreeNode root) {
            return search(root, new HashSet<>());
        }
        public int search(TreeNode tn, HashSet<Integer> set) {
            if (tn == null) {
                return 0;
            }
            
            if (set.contains(tn.val)) {
                set.remove(tn.val);
            } else {
                set.add(tn.val);
            }
            
            int res = 0;
            if (tn.left == null && tn.right == null && set.size() <= 1) {
                res++;
            }
            
            res += search(tn.left, new HashSet(set)) + search(tn.right, new HashSet(set));
            return res;
        }
    }
    
    
    
     

    https://leetcode.com/problems/pseudo-palindromic-paths-in-a-binary-tree/discuss/648332/Java-O(N)-DFS-HashSet-Bitwise

    class Solution {
        int count = 0;
        public int pseudoPalindromicPaths (TreeNode root) {
            dfs(root, new HashSet<>());
            return count;
        }
        private void dfs(TreeNode node, Set<Integer> set) {
            if(node !=null) {
                if(set.contains(node.val)) set.remove(node.val); else set.add(node.val);
                if(node.left ==null && node.right == null) {
                    if(set.size() <=1) count++;
                } else {
                    dfs(node.left, new HashSet<>(set));
                    dfs(node.right, new HashSet<>(set));                
                }
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/13090851.html
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