Given a sentence
that consists of some words separated by a single space, and a searchWord
.
You have to check if searchWord
is a prefix of any word in sentence
.
Return the index of the word in sentence
where searchWord
is a prefix of this word (1-indexed).
If searchWord
is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.
A prefix of a string S
is any leading contiguous substring of S
.
Example 1:
Input: sentence = "i love eating burger", searchWord = "burg" Output: 4 Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.
Example 2:
Input: sentence = "this problem is an easy problem", searchWord = "pro" Output: 2 Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.
Example 3:
Input: sentence = "i am tired", searchWord = "you" Output: -1 Explanation: "you" is not a prefix of any word in the sentence.
Example 4:
Input: sentence = "i use triple pillow", searchWord = "pill" Output: 4
Example 5:
Input: sentence = "hello from the other side", searchWord = "they" Output: -1
Constraints:
1 <= sentence.length <= 100
1 <= searchWord.length <= 10
sentence
consists of lowercase English letters and spaces.searchWord
consists of lowercase English letters.
class Solution { public int isPrefixOfWord(String sentence, String searchWord) { String[] arr = sentence.split(" "); int le = arr.length; int c = searchWord.length(); for(int i = 0; i< le; i++){ if(arr[i].length() >= c){ String s = arr[i].substring(0, c); if(s.equals(searchWord)) return i+1; } } return -1; } }