• 1385. Find the Distance Value Between Two Arrays


    Given two integer arrays arr1 and arr2, and the integer dreturn the distance value between the two arrays.

    The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where |arr1[i]-arr2[j]| <= d.

    Example 1:

    Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
    Output: 2
    Explanation: 
    For arr1[0]=4 we have: 
    |4-10|=6 > d=2 
    |4-9|=5 > d=2 
    |4-1|=3 > d=2 
    |4-8|=4 > d=2 
    For arr1[1]=5 we have: 
    |5-10|=5 > d=2 
    |5-9|=4 > d=2 
    |5-1|=4 > d=2 
    |5-8|=3 > d=2
    For arr1[2]=8 we have:
    |8-10|=2 <= d=2
    |8-9|=1 <= d=2
    |8-1|=7 > d=2
    |8-8|=0 <= d=2
    

    Example 2:

    Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
    Output: 2
    

    Example 3:

    Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
    Output: 1
    

    Constraints:

    • 1 <= arr1.length, arr2.length <= 500
    • -10^3 <= arr1[i], arr2[j] <= 10^3
    • 0 <= d <= 100
    class Solution {
        public int findTheDistanceValue(int[] arr1, int[] arr2, int d) {
            int l1 = arr1.length;
            int l2 = arr2.length;
            int res = 0;
            Arrays.sort(arr1);
            Arrays.sort(arr2);
            int tmp = 0;
            for(int i = 0; i < l1; i++){
                for(int j = l2-1; j >= 0; j--){
                    if(Math.abs(arr1[i] - arr2[j]) <= d){
                       break;  
                    }
                    else tmp++;
                }
                if(tmp == l2) res++;
                tmp = 0;
            }
            return res;
        }
    }
  • 相关阅读:
    LeetCode——Add Binary
    UVA
    mac平台adb、tcpdump捕手android移动网络数据包
    代码农民提高生产力
    Atitit. 拉开拉链zip文件 最佳实践实施 java c# .net php
    Arc Object开发,概述2
    ArcGIS Object开发,概述
    GDI 编程基础简介
    科目三考试档位与速度匹配总结、及考试操作技巧
    倾斜摄影
  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/12578954.html
Copyright © 2020-2023  润新知