• 274. H-Index


    Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.

    According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."

    Example:

    Input: citations = [3,0,6,1,5]
    Output: 3 
    Explanation: [3,0,6,1,5] means the researcher has 5 papers in total and each of them had 
                 received 3, 0, 6, 1, 5 citations respectively. 
                 Since the researcher has 3 papers with at least 3 citations each and the remaining 
                 two with no more than 3 citations each, her h-index is 3.

    Note: If there are several possible values for h, the maximum one is taken as the h-index.

    public class Solution {
        public int hIndex(int[] citations) {
            ArrayList<Integer> list = new ArrayList();
            for(int i: citations){
                list.add(i);
            }
            Collections.sort(list);
            Collections.reverse(list);
            for (int i = 0; i < citations.length; ++i) {
                if (i + 1 == list.get(i)) return i+1;
                if (i + 1 > list.get(i)) return i; //[0]的情况,很傻逼
            }
            return citations.length;
        }
    }

    这个方法反而慢的一比

    public class Solution {
        public int hIndex(int[] citations) {
            Arrays.sort(citations);
            reverse(citations);
            for (int i = 0; i < citations.length; ++i) {
                if (i + 1 == citations[i]) return i+1;
                if (i + 1 > citations[i]) return i; //[0]的情况,傻逼
            }
            return citations.length;
        }
        private static void reverse(int[] nums) {
            int left = 0;
            int right = nums.length - 1;
            while (left < right) {
                final int tmp = nums[left];
                nums[left] = nums[right];
                nums[right] = tmp;
                ++left;
                --right;
            }
        }
    }

    先从大到小排序,然后从前往后扫描,如果当前文章数(即当前下标+1)等于值本身,则返回当前文章数作为 h-index;

    如果当前文章数大于值本身,则返回当前文章数-1作为H-Index, 因为当前文章的引用数小于当前文章数,不能算在内。时间复杂度O(nlog,空间复杂度O(1)。

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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/11496922.html
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