• SQL将一列转换成一行,并将这一行形成新的列


    SQL部分-----

    1. .查询出来要转换的数据
    SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1
    数据如图:

    2.将查询到的数据转换成行,以逗号隔开,以【】包裹

    SELECT STUFF((SELECT  '[' + name + '],'  
    FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a  FOR  XML PATH('')  ), 1,0, '') AS Name 
    如图:
    
    

    3,去掉最后一个逗号

    SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT  '[' + name + '],'  
    FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a  FOR  XML PATH('')  ), 1,0, '') AS Name ) AS a
    如图:
    
    

    4,这一行形成新的列,用PIVOT实现

    SELECT * FROM (
     select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from (
     SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount
     FROM dbo.shop_sellers AS ss
     LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id
     LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid
     LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid
     LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id
     INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner
     WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status='finished' and pay_status='paid' 
     and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 and shopid=15 or ParentShopId=15) 
     AND ol.order_time between '2018-01-17' and '2018-08-17 23:59:59') a
     GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR 
     pay_type_name IN ([现金],[支付宝],[微信支付],[会员卡],[康品汇会员卡],[银联扫码支付]))PPA
    如图:

    C#后台代码,先将一列转换成一行,以逗号隔开,【】包裹

    string SQL = "SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT  '[' + name + '],'  
    FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a FOR XML PATH('') ), 1, 0, '') AS Name ) AS a
    "; DataTable dt = dbAccess.ExecuteTable(SQL); string filwes = dt.Rows[0]["name"].ToString();
    得到的结果如上面标题3,然后拼接SQL,将filwes作为参数输入下面SQL语句

    SELECT * FROM (
    select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from (
    SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount
    FROM dbo.shop_sellers AS ss
    LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id
    LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid
    LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid
    LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id
    INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner
    WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status='finished' and pay_status='paid'
    and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 {1}) {2}) a
    GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR pay_type_name IN (‘“+filwes+”’))PPA

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  • 原文地址:https://www.cnblogs.com/weixin18/p/9517841.html
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