sql server中列中字符换使用分割字符后，判断是否存在指定的项

编辑器加载中... SELECT dbo.ContionsInters('2,3,1,33',333)>0

select * from [split]('1,2,3',',')

--创建函数 ，处理 字符串是否包含，指定的字符

alter FUNCTION [dbo].ContionsInters ( @ids NVARCHAR(1024) ,@Targetid INT )

RETURNS int

AS

begin

DECLARE @count INT SELECT @count= COUNT(*) FROM split(@ids,',') WHERE col=@Targetid

RETURN @count

END

 CREATE function [dbo].[split](@c varchar(2000),@split varchar(2))

returns @t table(col varchar(20))

as

 begin while(charindex(@split,@c)<>0) begin insert @t(col) values (substring(@c,1,charindex(@split,@c)-1))

set @c = stuff(@c,1,charindex(@split,@c),'')

end insert @t(col) values (@c)

return

end