• 一起谈.NET技术,通过16道练习学习Linq和Lambda 狼人:


    1 查询Student表中的所有记录的SnameSsexClass列。 

    select sname,ssex,class from student
    Linq:
    from s
    in Students
    select new
    {
    s.SNAME,
    s.SSEX,
    s.CLASS
    }
    Lambda:
    Students.Select( s
    => new {
    SNAME = s.SNAME,SSEX = s.SSEX,CLASS = s.CLASS
    })


    2 查询教师所有的单位即不重复的Depart列。
     

    select distinct depart from teacher
    Linq:
    from t
    in Teachers.Distinct()
    select
    t.DEPART
    Lambda:
    Teachers.Distinct().Select( t
    => t.DEPART)

    3 查询Student表的所有记录。
     

    select * from student
    Linq:
    from s
    in Students
    select
    s
    Lambda:
    Students.Select( s
    => s)

    4 查询Score表中成绩在6080之间的所有记录。 

    select * from score where degree between 60 and 80
    Linq:
    from s
    in Scores
    where s.DEGREE >= 60 && s.DEGREE < 80
    select
    s
    Lambda:
    Scores.Where(
    s
    => (
    s.DEGREE >= 60 && s.DEGREE < 80
    )
    )

    5 查询Score表中成绩为858688的记录。 

    select * from score where degree in (85,86,88)
    Linq:
    In
    from s in Scores
    where (
    new decimal[]{85,86,88}
    ).Contains(s.DEGREE)
    select
    s
    Lambda:
    Scores.Where( s
    => new Decimal[] {85,86,88}.Contains(s.DEGREE))
    Not in
    from s in Scores
    where !(
    new decimal[]{85,86,88}
    ).Contains(s.DEGREE)
    select
    s
    Lambda:
    Scores.Where( s
    => !(new Decimal[]{85,86,88}.Contains(s.DEGREE)))

      Any()应用:双表进行Any时,必须是主键为(String)
      CustomerDemographics CustomerTypeID(String)
      CustomerCustomerDemos (CustomerID CustomerTypeID)(String)
      一个主键与二个主建进行Any(或者是一对一关键进行Any)不可,以二个主键于与一个主键进行Any

    from e in CustomerDemographics
    where !e.CustomerCustomerDemos.Any()
    select e

    from c in Categories
    where !c.Products.Any()
    select c

    6 查询Student表中"95031"班或性别为""的同学记录。 

    select * from student where class ='95031' or ssex= N'女'
    Linq:
    from s in Students
    where s.CLASS == "95031"
    || s.CLASS == "女"
    select
    s
    Lambda:
    Students.Where(s
    => ( s.CLASS == "95031" || s.CLASS == "女"))

    7 Class降序查询Student表的所有记录。

    select * from student order by Class DESC
    Linq:
    from s
    in Students
    orderby s.CLASS descending
    select
    s
    Lambda:
    Students.OrderByDescending(s
    => s.CLASS)

    8 Cno升序、Degree降序查询Score表的所有记录。 

    select * from score order by Cno ASC,Degree DESC
    Linq:(这里Cno ASC在linq中要写在最外面)
    from s
    in Scores
    orderby s.DEGREE descending
    orderby s.CNO ascending
    select
    s
    Lambda:
    Scores.OrderByDescending( s
    => s.DEGREE)
    .OrderBy( s => s.CNO)

    9 查询"95031"班的学生人数。

    select count(*) from student where class = '95031'
    Linq:
    ( from s in Students
    where s.CLASS == "95031"
    select
    s
    ).Count()
    Lambda:
    Students.Where( s
    => s.CLASS == "95031" )
    .Select( s => s)
    .Count()

    10、查询Score表中的最高分的学生学号和课程号。 

    select distinct s.Sno,c.Cno from student as s,course as c ,score as sc
    where s.sno=(select sno from score where degree = (select max(degree) from score))
    and c.cno = (select cno from score where degree = (select max(degree) from score))
    Linq:
    (
    from s
    in Students
    from c in Courses
    from sc in Scores
    let maxDegree = (from sss in Scores
    select sss.DEGREE
    ).Max()
    let sno = (from ss in Scores
    where ss.DEGREE == maxDegree
    select ss.SNO).Single().ToString()
    let cno = (from ssss in Scores
    where ssss.DEGREE == maxDegree
    select ssss.CNO).Single().ToString()
    where s.SNO == sno && c.CNO == cno
    select new {
    s.SNO,
    c.CNO
    }
    ).Distinct()

      操作时问题?执行时报错: where s.SNO == sno(这行报出来的) 运算符"=="无法应用于"string""System.Linq.IQueryable<string>"类型的操作数
      解决:
      原:let sno = (from ss in Scores
                    where ss.DEGREE == maxDegree
                    select ss.SNO).ToString()
          Queryable().Single()
    返回序列的唯一元素;如果该序列并非恰好包含一个元素,则会引发异常。
      解:let sno = (from ss in Scores
                    where ss.DEGREE == maxDegree
                    select ss.SNO).Single().ToString()
     

    11、查询'3-105'号课程的平均分。

    select avg(degree) from score where cno = '3-105'
    Linq:
    (
    from s in Scores
    where s.CNO == "3-105"
    select
    s.DEGREE
    ).Average()
    Lambda:
    Scores.Where( s
    => s.CNO == "3-105")
    .Select( s => s.DEGREE)
    .Average()

    12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。

    select avg(degree) from score where cno like '3%' group by Cno having count(*)>=5
    Linq:
    from s in Scores
    where s.CNO.StartsWith("3")
    group s by s.CNO
    into cc
    where cc.Count() >= 5
    select cc.Average( c =>
    c.DEGREE)
    Lambda:
    Scores.Where( s
    => s.CNO.StartsWith("3") )
    .GroupBy( s => s.CNO )
    .Where( cc => ( cc.Count() >= 5) )
    .Select( cc => cc.Average( c => c.DEGREE) )
      Linq: SqlMethod
      like
    也可以这样写:
        s.CNO.StartsWith("3") or SqlMethods.Like(s.CNO,"%3")


    13、查询最低分大于70,最高分小于90Sno列。

    select sno from score group by sno having min(degree) > 70 and max(degree) < 90
    Linq:
    from s
    in Scores
    group s by s.SNO
    into ss
    where ss.Min(cc => cc.DEGREE) > 70 && ss.Max( cc => cc.DEGREE) < 90
    select new
    {
    sno =
    ss.Key
    }
    Lambda:
    Scores.GroupBy (s
    => s.SNO)
    .Where (ss => ((ss.Min (cc => cc.DEGREE) > 70) && (ss.Max (cc => cc.DEGREE) < 90)))
    .Select ( ss => new {
    sno = ss.Key
    })

    14、查询所有学生的SnameCnoDegree列。

    select s.sname,sc.cno,sc.degree from student as s,score as sc where s.sno = sc.sno
    Linq:
    from s
    in Students
    join sc in Scores
    on s.SNO equals sc.SNO
    select new

    {
    s.SNAME,
    sc.CNO,
    sc.DEGREE
    }
    Lambda:
    Students.Join(Scores, s
    => s.SNO,
    sc => sc.SNO,
    (s,sc) => new{
    SNAME = s.SNAME,
    CNO = sc.CNO,
    DEGREE = sc.DEGREE
    })

    15、查询所有学生的SnoCnameDegree列。

    select sc.sno,c.cname,sc.degree from course as c,score as sc where c.cno = sc.cno
    Linq:
    from c
    in Courses
    join sc in Scores
    on c.CNO equals sc.CNO
    select new

    {
    sc.SNO,c.CNAME,sc.DEGREE
    }
    Lambda:
    Courses.Join ( Scores, c
    => c.CNO,
    sc => sc.CNO,
    (c, sc) => new
    {
    SNO = sc.SNO,
    CNAME = c.CNAME,
    DEGREE = sc.DEGREE
    })

    16、查询所有学生的SnameCnameDegree列。

    select s.sname,c.cname,sc.degree from student as s,course as c,score as sc where s.sno = sc.sno and c.cno = sc.cno
    Linq:
    from s
    in Students
    from c in Courses
    from sc in Scores
    where s.SNO == sc.SNO && c.CNO == sc.CNO
    select new { s.SNAME,c.CNAME,sc.DEGREE }
    主要参考文章链接:http://www.cnblogs.com/RuiLei/archive/2008/11/09/1329905.html

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  • 原文地址:https://www.cnblogs.com/waw/p/2162688.html
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