The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤). Then N numbers are given in the next line, separated by one space.
Output Specification:
For each illegal input number, print in a line ERROR: X is not a legal number
where X
is the input. Then finally print in a line the result: The average of K numbers is Y
where K
is the number of legal inputs and Y
is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined
instead of Y
. In case K
is only 1, output The average of 1 number is Y
instead.
Sample Input 1:
7
5 -3.2 aaa 9999 2.3.4 7.123 2.35
Sample Output 1:
ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38
Sample Input 2:
2
aaa -9999
Sample Output 2:
ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined
#include<iostream> #include<cstring> int main(){ int n; scanf("%d",&n); double temp,sum = 0.0; int cnt = 0; char a[50],b[50]; for(int i = 0 ; i < n; i++){ scanf("%s",a); sscanf(a,"%lf",&temp); sprintf(b,"%.2f",temp); bool flag = true; for(int j = 0; j < strlen(a); j++){ if(a[j] != b[j]){ flag = false; break; } } if(flag && temp <= 1000 && temp >= -1000){ cnt++; sum += temp; }else{ printf("ERROR: %s is not a legal number ",a); } } if(cnt == 0){ printf("The average of 0 numbers is Undefined "); }else if(cnt == 1){ printf("The average of 1 number is %.2f",sum); }else{ printf("The average of %d numbers is %.2f",cnt,sum/cnt); } return 0; }