• 网络编程(7day-selector模块,队列)


     http://www.cnblogs.com/yuanchenqi/articles/6755717.html

     selector模块

    @程序运行流程
       1,建议大家用selectors模块,此模块IO多路复用会自动选择最佳模型
       2,在客户端第一次连接的时候,完成一次注册sel.register(sock,selectors.EVENT_READ,accept),其中注册只是放到列表中
          一旦有变化(sock)就会触发accept函数, # print(key.fileobj)    #第一次时sock  
                                               # print(key.data)       #第一次时 accept
          accept函数完成对conn的注册,加入到注册表中监控起来,sel.register(conn,selectors.EVENT_READ,read)
          开始通信时,sock不变,   # print(key.fileobj)           # 通信时 conn
                                   # print(key.data)              # 通信时 read
          然后read调用conn,如果客户端在win下突然断掉还会报错,所以就try,把注册去掉就行了,linux也是
          
          3,用的时候都不用动,只要写accept函数,和read函数及可
    
    import selectors  # 基于select模块实现的IO多路复用,建议大家使用
    
    import socket
    
    sock=socket.socket()
    sock.bind(("127.0.0.1",8800))
    
    sock.listen(5)
    
    sock.setblocking(False)
    
    sel=selectors.DefaultSelector() #根据具体平台选择最佳IO多路机制,比如在linux,选择epoll
    
    def read(conn,mask):
    
        try:
            data=conn.recv(1024)
            print(data.decode("UTF8"))
            data2=input(">>>")
            conn.send(data2.encode("utf8"))
        except Exception:
            sel.unregister(conn)
    
    def accept(sock,mask):
    
        conn, addr = sock.accept()
        print("conn",conn)
        sel.register(conn,selectors.EVENT_READ,read) #监听谁就把谁写到注册函数里,read是自己写的, conn
    
    sel.register(sock,selectors.EVENT_READ,accept)  # 注册事件,不是监听 不会卡到那,只是把sock,appcet绑定到这个对像去了,
                                                        #sock有变化直接触发accept,中间的参数没用
    
    while 1:
    
        print("wating...")
        events=sel.select()   #  监听,会卡到那    [(key1,mask1),(key2,mask2)],mask没有用,每注册一个都会以元组形式加到这里面,
        for key,mask in events:
    
            # print(key.fileobj)    #第一次时sock          # 通信时 conn
            # print(key.data)       #第一次时 accept       # 通信时 read
            func=key.data
            obj=key.fileobj
    
            func(obj,mask)  # 1次 accept(sock,mask)    # 2次 read(conn,mask)
    
    
    IO多路复用实现机制
    win: 下只有select
    linux: 下有select, poll, epoll
    
    select就是反复的遍历,而epoll是绑定回调函数,实现信号触发,不再遍历
    
    select是效率最低的 只有一个函数
        1,每次调用select都需要将所有的
           fd(文件描述符)从用户空间cp到内核空间,导致效率下降
        2,遍历所有的fd是否有数据访问,最重要的问题cpu数的时间多
        3,最大连接数1024
    poll跟select完全一样,只是在最大连接数做了个改进,没有限制了,只有一个函数
    
    epoll:通过三个函数来实现
        1  第一个函数来创建一个epoll句柄,fd(文件描述符)从用户空间cp到内核空间,只拷一次
        2,回调函数,某一个函数或者某一个动作成功完成后会触发的函数
            为所有的fd绑定一个回调函数,一旦有数据访问,触发回调函数
            回调函数将fd放到链表中
        3,连接数不限(端口,什么的也没那嘛多)

    队列

    import queue
    
    
    #q=queue.Queue(3)  # 默认是  先进先出(FIFO)
    
    
    # q.put(111)
    # q.put("hello")
    # q.put(222)
    #
    # q.put(223,False)
    #
    # print(q.get())
    # # print(q.get())
    # # print(q.get())
    # #
    # q.get(False)
    
    
    # queue 优点: 线程安全的  我不想用锁来控制,就想用queue来控制
    
    
    
    # join和task_done
    
    
    # q=queue.Queue(5)
    
    # q.put(111)
    # q.put(222)
    # q.put(22222)
    #
    #
    # while not q.empty():
    #         a=q.get()
    #         print(a)
    #q.task_done()
    
    
    # b=q.get()
    # print(b)
    # q.task_done()
    
    # q.join()
    #
    # print("ending")
    
    
    #  先进后出模式
    
    # q=queue.LifoQueue()  #  Lifo  last in first out
    #
    #
    # q.put(111)
    # q.put(222)
    # q.put(333)
    #
    # print(q.get())
    
    
    
    # 优先级
    
    # q=queue.PriorityQueue()
    #
    # q.put([4,"hello4"])
    # q.put([1,"hello"])
    # q.put([2,"hello2"])
    #
    # print(q.get())
    # print(q.get())
    
    
    
    # import queue
    #
    #
    # q=queue.Queue()
    #
    # q.put(111)
    # q.put(2222)
    # q.put(22333)
    #
    # print( )
    
    
    #生产者消费者模型
    
    import time,random
    import queue,threading
    
    q = queue.Queue()
    
    def Producer(name):
      count = 0
      while count <10:
        print("making........")
        time.sleep(2)
        q.put(count)
        print('Producer %s has produced %s baozi..' %(name, count))
    
        count +=1
        #q.task_done()
        #q.join()
        print("ok......")
    
    def Consumer(name):
      count = 0
      while count <10:
        time.sleep(1)
        if not q.empty():
            data = q.get()
            #q.task_done()
            #q.join()
            print(data)
            print('33[32;1mConsumer %s has eat %s baozi...33[0m' %(name, data))
        else:
            print("-----no baozi anymore----")
    
        count +=1
    
    p1 = threading.Thread(target=Producer, args=('A',))
    c1 = threading.Thread(target=Consumer, args=('B',))
    
    # c2 = threading.Thread(target=Consumer, args=('C',))
    # c3 = threading.Thread(target=Consumer, args=('D',))
    p1.start()
    c1.start()
    # c2.start()
    # c3.start()

     回顾

    进程:是最小的资源管理单位,可以理解成一个容器,放线程的 还包括其他的
    线程:是最小的执行单位
    cpython因为有GIL锁,一个进程只能同时由一个线程出去执行
    join,
    关于setdaemon:程序直到不存在非守护线程时退出
    同步锁  由于多线程处理公共数据 同步锁和递归锁都是互斥锁,一个拿到acquire其他的线程就拿不到
        有acquire release方法,
    event 线程通信不是锁 创建 threading.Event  wait是设为True,这个进
        程等着,等到其他线程 set=false才往下进行
        
    semaphore = threading.Semaphore(5)可以控制同时拿到acquire的线程数为5
    用到数据的连接池上的概念
        
        
    # # # import threading
    # # # from time import ctime,sleep
    # # # import time
    # # #
    # # # def Music(name):
    # # #
    # # #         print ("Begin listening to {name}. {time}".format(name=name,time=ctime()))
    # # #         sleep(6)
    # # #         print("end listening {time}".format(time=ctime()))
    # # #
    # # # def Blog(title):
    # # #
    # # #         print ("Begin recording the {title}. {time}".format(title=title,time=ctime()))
    # # #         sleep(5)
    # # #         print('end recording {time}'.format(time=ctime()))
    # # #
    # # #
    # # # threads = []
    # # #
    # # #
    # # # t1 = threading.Thread(target=Music,args=('FILL ME',),name="")
    # # # t2 = threading.Thread(target=Blog,args=('',))
    # # #
    # # # threads.append(t1)
    # # # threads.append(t2)
    # # #
    # # # if __name__ == '__main__':
    # # #
    # # #     t1.setDaemon(True)
    # # #
    # # #     for t in threads:
    # # #
    # # #         #t.setDaemon(True) #注意:一定在start之前设置
    # # #         t.start()
    # # #
    # # #         #t.join()
    # # #
    # # #     # t1.join()
    # # #     # t2.join()    #  考虑这三种join位置下的结果?
    # # #
    # # #     print ("all over %s" %ctime())
    # #
    # #
    # #
    # #
    # #
    # # # import time
    # # # import threading
    # # #
    # # # def addNum():
    # # #
    # # #     LOCK.acquire()
    # # #     global num #在每个线程中都获取这个全局变量
    # # #     #num-=1
    # # #
    # # #     temp=num
    # # #     time.sleep(0.1)
    # # #     num =temp-1  # 对此公共变量进行-1操作
    # # #
    # # #     LOCK.release()
    # # #
    # # # num = 100  #设定一个共享变量
    # # #
    # # # thread_list = []
    # # #
    # # # LOCK=threading.Lock()
    # # #
    # # # for i in range(100):
    # # #     t = threading.Thread(target=addNum)
    # # #     t.start()
    # # #     thread_list.append(t)
    # # #
    # # # for t in thread_list: #等待所有线程执行完毕
    # # #     t.join()
    # # #
    # # # print('Result: ', num)
    # #
    
    
    # #同步锁会造成死锁
    # # import threading
    # # import time
    # #
    # # # mutexA = threading.Lock()
    # # # mutexB = threading.Lock()
    # # RLock = threading.RLock() 递归锁是内部维护一个计数器,只要大于0别的线程就无法抢,抢到就加1
    # #
    # # class MyThread(threading.Thread):
    # #
    # #     def __init__(self):
    # #         threading.Thread.__init__(self)
    # #
    # #     def run(self): 使用继续方法使用线程,重写init,run方法是必须的
    # #
    # #         self.fun1()
    # #
    # #         self.fun2()
    # #
    # #     def fun1(self):
    # #         RLock.acquire()  # 如果锁被占用,则阻塞在这里,等待锁的释放
    # #
    # #         print ("I am %s , get res: %s---%s" %(self.name, "ResA",time.time()))
    # #
    # #         RLock.acquire()
    # #         print ("I am %s , get res: %s---%s" %(self.name, "ResB",time.time()))
    # #         RLock.release()
    # #         RLock.release()
    # #
    # #
    # #     def fun2(self):
    # #         RLock.acquire()
    # #         print ("I am %s , get res: %s---%s" %(self.name, "ResB",time.time()))
    # #         time.sleep(0.5)
    # #         RLock.acquire()
    # #
    # #         print ("I am %s , get res: %s---%s" %(self.name, "ResA",time.time()))
    # #         RLock.release()
    # #
    # #         RLock.release()
    # #
    # # if __name__ == "__main__":
    # #
    # #     print("start---------------------------%s"%time.time())
    # #
    # #     for i in range(0, 10):
    # #
    # #         my_thread = MyThread()
    # #         my_thread.start()
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #
    #threading.Event对像例子
    
    # import threading
    # import time
    # import logging
    #
    # logging.basicConfig(level=logging.DEBUG, format='(%(threadName)-10s) %(message)s',)
    #
    # def worker(event):
    #
    #     logging.debug('Waiting for redis ready...')
    #
    #     event.wait()  # flag=True 继续执行
    #
    #     logging.debug('redis ready, and connect to redis server and do some work [%s]', time.ctime())
    #     time.sleep(1)
    #
    # def main():
    #
    #     readis_ready = threading.Event()
    #
    #     t1 = threading.Thread(target=worker, args=(readis_ready,), name='t1')
    #     t1.start()
    #
    #     t2 = threading.Thread(target=worker, args=(readis_ready,), name='t2')
    #     t2.start()
    #
    #     logging.debug('first of all, check redis server, make sure it is OK, and then trigger the redis ready event')
    #     time.sleep(3) # simulate the check progress
    #     readis_ready.set()  # flag=True
    #
    # if __name__=="__main__":
    #
    #     main()
    
    
    
    
    
    
    
    import threading
    import time
    
    semaphore = threading.Semaphore(5)
    
    def func():
    
        semaphore.acquire()
    
        print (threading.currentThread().getName() + ' get semaphore')
        time.sleep(2)
    
        semaphore.release()
    
    for i in range(20):
      t1 = threading.Thread(target=func)
      t1.start()
     
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  • 原文地址:https://www.cnblogs.com/wanchenxi/p/7887238.html
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