福哥答案2020-06-02:
对于千万级长度的数组单值查找:
序号小的,单线程占明显优势;序号大的,多线程占明显优势。
单线程时间不稳定,多线程时间稳定。
go语言测试代码如下:
package main import ( "fmt" "math/rand" "testing" "time" ) const ( ARRLEN = 1000_0000 ) var arr []int var target int func init() { arr = make([]int, ARRLEN) rand.Seed(time.Now().UnixNano()) for i := 0; i < ARRLEN; i++ { arr[i] = rand.Intn(10_0000_0000) } target = arr[9990001] fmt.Println("初始化完成") } //go test -v -test.run TestMutiThreadsSearch func TestMutiThreadsSearch(t *testing.T) { fmt.Println("多线程开始") now := time.Now() const MAXGE = 10000 const MAXHANG = 1000 index := -1 chindex := make(chan struct{}, 0) ch := make(chan struct{}, MAXHANG) f := func(i int) { for j := 0; j < MAXGE; j++ { if target == arr[i*MAXGE+j] { index = i*MAXGE + j fmt.Println("找到了-------------------", time.Now().Sub(now)) chindex <- struct{}{} break } } ch <- struct{}{} } for i := 0; i < MAXHANG; i++ { go f(i) } for i := 0; i < MAXHANG; i++ { select { case <-chindex: //已经找到了 i = MAXHANG break case <-ch: break } } if index == -1 || index == MAXHANG { fmt.Println(target, "未找到") } else { fmt.Println(target, "已经找到了,序号是:", index) } fmt.Println("多线程结束", time.Now().Sub(now)) } //go test -v -test.run TestSingleThreadToSum //go test -bench=. -test.run TestSingleThreadToSum //go test -v -cover -run TestSingleThreadToSum func TestSingleThreadSearch(t *testing.T) { fmt.Println("单线程开始") now := time.Now() //target := 5 index := -1 for i := 0; i < ARRLEN; i++ { if target == arr[i] { index = i break } } fmt.Println(target, "的序号是:", index) fmt.Println("单线程结束", time.Now().Sub(now)) }
敲命令go test -v:
当查找序号为0时:
当查找序号为4990001时:
当查找序号为9990001时: