很裸的单调队列问题,不过O(n)的算法写出来5188+ms,超5s了。。。谁能告诉我500+ms的神级代码是什么。。.T_T
My Code:
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int N = 1000005;
struct node {
int i;
int num;
}q[N];
int ans[N];
int b[N];
int main() {
//freopen("data.in", "r", stdin);
int n, k, i, f, r;
while(~scanf("%d%d", &n, &k)) {
getchar();
for(i = 0; i < n; i++)
scanf("%d", &b[i]);
for(f = r = i = 0; i < n; i++) {
if(f < r && q[f].i <= i - k) f++;
while(f < r && q[r-1].num >= b[i]) r--;
q[r].i = i; q[r].num = b[i]; r++;
ans[i] = q[f].num;
}
for(i = k-1; i < n; i++) {
printf("%d", ans[i]);
if(i != n-1) putchar('');
else putchar('\n');
}
for(f = r = i = 0; i < n; i++) {
if(f < r && q[f].i <= i - k) f++;
while(f < r && q[r-1].num <= b[i]) r--;
q[r].i = i; q[r].num = b[i]; r++;
ans[i] = q[f].num;
}
for(i = k-1; i < n; i++) {
printf("%d", ans[i]);
if(i != n-1) putchar('');
else putchar('\n');
}
}
return 0;
}