• [BZOJ1036][ZJOI2008]树的统计Count(树链剖分)


    树剖模板题了,

    Code

    #include <cstdio>
    #include <algorithm>
    #define MID int mid=(l+r)>>1,ls=id<<1,rs=id<<1|1
    #define N 30010
    using namespace std;
    
    struct node{int sum,mx;node(){sum=0,mx=-1e9;}}T[N*4];
    struct info{int to,nex;}e[N*2];
    int n,A[N],tot,head[N],tag[N*4];
    int dep[N],fa[N],sz[N],son[N];
    int cnt,tp[N],tw[N],tid[N];
    
    inline int read(){
        int x=0,f=1;char ch=getchar();
        while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
        while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
        return x*f;
    }
    
    inline void Link(int u,int v){
    	e[++tot].nex=head[u];e[tot].to=v;head[u]=tot;
    }
    
    void update(int l,int r,int id,int p,int x){
    	if(l==r){T[id].sum=T[id].mx=x;return;}
    	MID;
    	if(p<=mid) update(l,mid,ls,p,x);
    	else update(mid+1,r,rs,p,x);
    	T[id].sum=T[ls].sum+T[rs].sum;
    	T[id].mx=max(T[ls].mx,T[rs].mx);
    }
    
    int querySum(int l,int r,int id,int L,int R){
    	if(L<=l&&r<=R) return T[id].sum;
    	MID;
    	int res=0;
    	if(L<=mid) res+=querySum(l,mid,ls,L,R);
    	if(R>mid) res+=querySum(mid+1,r,rs,L,R);
    	return res;
    }
    
    int queryMx(int l,int r,int id,int L,int R){
    	if(L<=l&&r<=R) return T[id].mx;
    	MID;
    	int res=-1e9;
    	if(L<=mid) res=max(res,queryMx(l,mid,ls,L,R));
    	if(R>mid) res=max(res,queryMx(mid+1,r,rs,L,R));
    	return res;
    }
    
    void dfs(int u,int pre){
    	sz[u]=1;
    	for(int i=head[u],mx=0;i;i=e[i].nex){
    		int v=e[i].to;
    		if(v==pre) continue;
    		dep[v]=dep[u]+1;
    		fa[v]=u;
    		dfs(v,u);
    		sz[u]+=sz[v];
    		if(sz[v]>mx) son[u]=v,mx=sz[v];
    	}
    }
    
    void dddfs(int u,int top){
    	tp[u]=top;
    	tid[u]=++cnt;
    	tw[cnt]=A[u];
    	if(!son[u]) return;
    	
    	dddfs(son[u],top);
    	for(int i=head[u];i;i=e[i].nex){
    		int v=e[i].to;
    		if(v!=son[u]&&v!=fa[u]) dddfs(v,v);
    	}
    }
    
    inline int qRangeSum(int u,int v){
    	int res=0;
    	while(tp[u]!=tp[v]){
    		if(dep[tp[u]]<dep[tp[v]]) swap(u,v);
    		res+=querySum(1,n,1,tid[tp[u]],tid[u]);
    		u=fa[tp[u]];
    	}
    	if(dep[u]>dep[v]) swap(u,v);
    	res+=querySum(1,n,1,tid[u],tid[v]);
    	return res;
    }
    
    inline int qRangeMx(int u,int v){
    	int res=-1e9;
    	while(tp[u]!=tp[v]){
    		if(dep[tp[u]]<dep[tp[v]]) swap(u,v);
    		res=max(res,queryMx(1,n,1,tid[tp[u]],tid[u]));
    		u=fa[tp[u]];
    	}
    	if(dep[u]>dep[v]) swap(u,v);
    	res=max(res,queryMx(1,n,1,tid[u],tid[v]));
    	return res;
    }
    
    void build(int l,int r,int id){
    	if(l==r){
    		T[id].sum=T[id].mx=tw[l];
    		return;
    	}
    	MID;
    	build(l,mid,ls);
    	build(mid+1,r,rs);
    	T[id].sum=T[ls].sum+T[rs].sum;
    	T[id].mx=max(T[ls].mx,T[rs].mx);
    }
    
    inline void Init(){
    	n=read();
    	for(int i=1;i<n;++i){
    		int u=read(),v=read();
    		Link(u,v),Link(v,u);
    	}
    	for(int i=1;i<=n;A[i++]=read());
    	dfs(1,0);
    	dddfs(1,1);
    	build(1,n,1);
    }
    
    inline void solve(){
    	int m=read(),x,y;
    	char s[10];
    	while(m--){
    		scanf("%s%d%d
    ",s,&x,&y);
    		if(s[1]=='H') update(1,n,1,tid[x],y);
    		else if(s[1]=='M') printf("%d
    ",qRangeMx(x,y));
    		else printf("%d
    ",qRangeSum(x,y));	
    	}
    }
    
    int main(){Init();solve();}
    
  • 相关阅读:
    Codeforces Round #526 (Div. 2) E. The Fair Nut and Strings
    Codeforces Round #526 (Div. 2) D. The Fair Nut and the Best Path
    S2SH项目实现分页功能
    S2SH项目实现分页功能
    HibernateDaoSupport类的使用
    object references an unsaved transient instance
    object references an unsaved transient instance
    启动Tomcat报WEB-INFlibj2ee.jar jar not loaded异常的解决办法
    启动Tomcat报WEB-INFlibj2ee.jar jar not loaded异常的解决办法
    解决eclipse中出现Resource is out of sync with the file system问题
  • 原文地址:https://www.cnblogs.com/void-f/p/9016230.html
Copyright © 2020-2023  润新知