namespace ConsoleApp
{
class Program
{
public static void Main()
{
string input=Console.ReadLine();
string output = Program.Replace (input, "ab", "00");
System.Console.ReadLine();
}
private static string Replace(string source, string a, string b)
{
string result = source;
int position = 0;//发现的位置
int len = 0;//
int num = 0;//记录发现的要替换的个数
for (int i = 0; i < result.Length - 1; i++)
{
if (result[i] == a[0])
{
position = i;
len = 0;
//int j = 0;
while (len<=a.Length-1 && result[position + len] == a[len])
{
len++;
}
if (len == a.Length)
{
Console.WriteLine("find a positon");
num++;
i = position+len;
Console.WriteLine("the posion is " + position + "\n the num is " + num);
continue;
}
if (a.Length == b.Length)
{
for (int j = position; j < a.Length - 1; j++)
{
result[j] = a[j];
}
}
else if (a.Length > b.Length)
{
}
else
{
}
}
}
return "";
}
}
}
{
class Program
{
public static void Main()
{
string input=Console.ReadLine();
string output = Program.Replace (input, "ab", "00");
System.Console.ReadLine();
}
private static string Replace(string source, string a, string b)
{
string result = source;
int position = 0;//发现的位置
int len = 0;//
int num = 0;//记录发现的要替换的个数
for (int i = 0; i < result.Length - 1; i++)
{
if (result[i] == a[0])
{
position = i;
len = 0;
//int j = 0;
while (len<=a.Length-1 && result[position + len] == a[len])
{
len++;
}
if (len == a.Length)
{
Console.WriteLine("find a positon");
num++;
i = position+len;
Console.WriteLine("the posion is " + position + "\n the num is " + num);
continue;
}
if (a.Length == b.Length)
{
for (int j = position; j < a.Length - 1; j++)
{
result[j] = a[j];
}
}
else if (a.Length > b.Length)
{
}
else
{
}
}
}
return "";
}
}
}
暂时实现了查找符合条件的个数和位置,替换的时候我想这样
if (a.Length == b.Length)
{
for (int j = position; j < a.Length - 1; j++)
{
result[j] = a[j];
}
}
else if (a.Length > b.Length)
{
}
else
{
}
要考虑三种情况,要查找的和要替换的字符串的长度相等,大于,小于。
相等就可以直接替换相应位置的字符就可以了,可是发现错误
////..............................
无法对属性或索引器“string.this[int]”赋值 -- 它是只读的
//.....................
我的思路是搞一个数组存放没有替换的和替换了的所有字符,不知各位有没有更好的呢,在这里先谢谢你的回复!!