剑指OFFER 数组中重复的数字
使用哈希表来完成
class Solution {
public:
// Parameters:
// numbers: an array of integers
// length: the length of array numbers
// duplication: (Output) the duplicated number in the array number
// Return value: true if the input is valid, and there are some duplications in the array number
// otherwise false
map<int,int> m;
bool duplicate(int num[], int length, int* duplication) {
for(int i=0;i<length;i++)
{
m[num[i]]++;
if(m[num[i]] > 1)
{
(*duplication) = num[i];
return true;
}
}
return false;
}
};