Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode *vectorToBST(vector<int>&a, int start, int end) { if(start>end) return NULL; int mid = (start+end)/2; TreeNode *Thead = new TreeNode(a[mid]); Thead->left = vectorToBST(a,start,mid-1); Thead->right = vectorToBST(a,mid+1,end); return Thead; } TreeNode *sortedListToBST(ListNode *head) { if(NULL==head) return NULL; if(NULL==head->next) { TreeNode *Thead = new TreeNode(head->val); return Thead; } vector<int>valVec; valVec.clear(); while(head) { valVec.push_back(head->val); head = head->next; } return vectorToBST(valVec,0,valVec.size()-1); } };
i dont know what's the usage of "sorted List",
unsorted also be ok