Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.
Follow up: Can you solve it without using extra space?
C++
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* detectCycle2(ListNode *head){
ListNode *fast = head;
ListNode *slow = head;
if(head==NULL) return NULL;
while (NULL != fast){
if (fast != NULL) fast = fast->next;
if (fast != NULL) fast = fast->next;
if (slow != NULL) slow = slow->next;
while(fast != NULL && slow == fast){
slow = head;
while(slow!=fast){
fast = fast->next;
slow = slow->next;
}
return slow;
}
}
return NULL;
}
ListNode *detectCycle(ListNode *head) {
ListNode *fast = head;
ListNode *slow = head;
if (NULL == head) return NULL;
while(fast && fast->next){
fast = fast->next->next;
slow = slow->next;
if (fast != NULL && slow == fast)
return FindTheFirstSameNode(fast,head);
}
return NULL;
}
ListNode *FindTheFirstSameNode(ListNode* head1, ListNode* head2){
while(head1 != head2){
head1 = head1->next;
head2 = head2->next;
}
return head1;
}
};