Given a string s, partition s such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of s.
For example, given s ="aab", Return
[ ["aa","b"], ["a","a","b"] ]
C++
class Solution {
public:
vector<vector<string>> partition(string s){
vector<vector<string>> res;
vector<string> out;
partitionDFS(s,0,out,res);
return res;
}
void partitionDFS(string s, int start, vector<string> &out, vector<vector<string>> &res) {
if (start == s.size()) {
res.push_back(out);
return;
}
for (int i = start; i < s.size(); ++i) {
if (isPalindrome(s, start, i)) {
out.push_back(s.substr(start, i - start + 1));
partitionDFS(s, i + 1, out, res);
out.pop_back();
}
}
}
bool isPalindrome(string s, int start, int end) {
while (start < end) {
if (s[start] != s[end]) return false;
++start;
--end;
}
return true;
}
};