A + B
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10502 Accepted Submission(s): 6043
Total Submission(s): 10502 Accepted Submission(s): 6043
Problem Description
读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
Input
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.
Output
对每个测试用例输出1行,即A+B的值.
Sample Input
one + two = three four + five six = zero seven + eight nine = zero + zero =
Sample Output
3 90 96#include <iostream> #include <map> #include <string> using namespace std; map<string,int> Map; void init() { Map["one"]=1;//注意这个操作必须放在函数内,自定义函数或main函数。函数体外只能声明定义基本类型,及常量。 Map["two"]=2; Map["three"]=3; Map["four"]=4; Map["five"]=5; Map["six"]=6; Map["seven"]=7; Map["eight"]=8; Map["nine"]=9; Map["zero"]=0; } int main() { init(); while(1) { string s; int a=0; while(cin>>s&&s!="+") { a=a*10+Map[s]; } int b=0; while(cin>>s&&s!="=") { b=b*10+Map[s]; } if(a==0&&b==0) break; cout<<a+b<<endl; } return 0; }