• 数据库sql语句例题(转)


    SQL数据库面试题以及答案(50例题)

    Student(S#,Sname,Sage,Ssex)学生表
    S#:学号
    Sname:学生姓名
    Sage:学生年龄
    Ssex:学生性别
    Course(C#,Cname,T#)课程表
    C#:课程编号
    Cname:课程名称
    T#:教师编号
    SC(S#,C#,score)成绩表
    S#:学号
    C#:课程编号
    score:成绩
    Teacher(T#,Tname)教师表
    T#:教师编号:
    Tname:教师名字
    

    问题:

    1、查询“001”课程比“002”课程成绩高的所有学生的学号

    select a.S# from (select S#,score from SC where C#='001')a, (select s#,score from SC where c#='002')b Where a.score>b.score and a.s# = b.s#;
    

    2、查询平均成绩大于60分的同学的学号和平均成绩

    select S#, avg(score) from sc group by S# having avg(score)>60
    

    3、查询所有同学的学号、姓名、选课数、总成绩

    select student.S#, student.Sname, count(sc.C#), sum(score) from student left outer join SC on student.S# = SC.S# group by Student.S#, Sname
    

    4、查询姓‘李’的老师的个数:

    select count(distinct(Tname)) 
    from teacher 
    where tname like '李%';
    

    5、查询没有学过“叶平”老师可的同学的学号、姓名:

    select student.S#, student.Sname 
    from Student 
    where S# not in (select distinct(SC.S#) from SC,Course,Teacher 
    where sc.c#=course.c# AND teacher.T#=course.T# AND Teahcer.Tname ='叶平');
    

    6、查询学过“叶平”老师所教的所有课的同学的学号、姓名:

    select S#,Sname   from Student    
    where S# in (select S# from SC ,Course ,Teacher 
    where SC.C#=Course.C# and Teacher.T#=Course.T# 
    and Teacher.Tname='叶平' group by S# 
    having count(SC.C#)=(select count(C#) from Course,Teacher  
    where Teacher.T#=Course.T# and Tname='叶平'));
    

    7、查询学过“011”并且也学过编号“002”课程的同学的学号、姓名:

    select Student.S#,Student.Sname 
    from Student,SC where Student.S#=SC.S# 
    and SC.C#='001'and 
    exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
    

    8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名:

    Select S#,Sname 
    from (select Student.S#,Student.Sname,score ,
    (select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2    
    from Student,SC 
    where Student.S#=SC.S# and C#='001') S_2 
    where score2 < score; 
    

    9、查询所有课程成绩小于60的同学的学号、姓名:

    select S#, sname 
    from student 
    where s# not in 
    (select student.s# from student, sc where s.s# = sc.s# and score>60);
    

    10、查询没有学全所有课的同学的学号、姓名:

    select student.s#, student.sname 
    from student, sc
    where student.s#=sc.s# 
    group by student.s#, student.sname 
    having count(c#)<(select count(c#) from course);
    

    11、查询至少有一门课与学号为“1001”同学所学相同的同学的学号和姓名:

    select s#, Sname 
    from Student, SC 
    where student.s# = sc.s# 
    and c# in (select c# from SC where s#='1001');
    

    12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;

    select distinct sc.s# , sname 
    from student, sc 
    where student.s#=sc.s# 
    and c# in (select C# from sc where s#='001');
    

    13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩:

    Update Sc Set Score=(Select Avg(s2_Score) From sc s2 Where s2.c#=sc.c#)  
    Where c# IN
    (Select c# From sc cs INNER JOIN Teacher tc ON cs.t#=tc.t# WHERE tname ='叶平')
    

    14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名:

    select s# from sc where c#  in 
    (select c# from sc where s#='1002') 
    group by s# having count(*)=
    (select count(*) from sc where s#='1002');
    

    15、删除学习“叶平”老师课的SC表记录:

    delect sc 
    from course, Teacher 
    where course.c#=sc.c# 
    and course.t#=teacher.t# 
    and tname='叶平';
    

    16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、002号课的平均成绩:

    Insert SC select S#,'002',
    (Select avg(score) from SC where C#='002') 
    from Student where S# not in (Select S# from SC where C#='002');
    

    17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,数据库,企业管理,英语,有效课程数,有效平均分:

    select s# as 学生ID,
    (select score from sc where sc.s#=t.s# and c#='004') as 数据库,
    (select score from sc where sc.s#=t.s# and c#='001') as 企业管理,
    (select score from sc where sc.s#=t.s# and c#='006') as 英语,
    count(*) as 有效课程数, avg(t.score) as 平局成绩
    from sc as t
    group by s# 
    order by avg(t.score)
    

    18、查询各科成绩最高和最低的分: 以如下的形式显示:课程ID,最高分,最低分

    select L.c# as 课程ID, L.score as 最高分,
    R.score as 最低分
    from sc L, sc R 
    where L.c# = R.c# 
    and L.score = (select max(IL.score) 
            from sc IL, student as IM 
            where L.c#=IL.c# and IM.s#=IL.s#
            group by IL.c#)
    and R.score = (select min(IR.score)
            from sc as IR
            where R.c#=IR.c#
            group by IR.c#);
    

    19、按各科平均成绩从低到高和及格率的百分数从高到低顺序:

    SELECT t.C# AS 课程号,
    max(course.Cname)AS 课程名,
    isnull(AVG(score),0) AS 平均成绩,
    100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数     
    FROM SC T,Course     
    where t.C#=course.C#     
    GROUP BY t.C#      
    ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 
    

    20、查询如下课程平均成绩和及格率的百分数(用”1行”显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004):

    21、查询不同老师所教不同课程平均分从高到低显示:

     SELECT max(Z.T#) AS 教师ID,
     MAX(Z.Tname) AS 教师姓名,
     C.C# AS 课程ID,
     AVG(Score) AS 平均成绩     
     FROM SC AS T,Course AS C ,Teacher AS Z    
     where T.C#=C.C# and C.T#=Z.T#   
     GROUP BY C.C#    
     ORDER BY AVG(Score) DESC
    

    22、查询如下课程成绩第3名到第6名的学生成绩单:企业管理(001),马克思(002),UML(003),数据库(004):

    23、统计下列各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ 小于60] :

    SELECT SC.C# as 课程ID, Cname as 课程名称,
    SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]  ,
    SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70],
    SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60],
    SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]     
    FROM SC,Course     
    where SC.C#=Course.C#     
    GROUP BY SC.C#,Cname;
    

    24、查询学生平均成绩及其名次:

    SELECT 1+(SELECT COUNT( distinct 平均成绩)                
    FROM (SELECT S#,AVG(score) AS 平均成绩                       
    FROM SC                   
    GROUP BY S#  ) AS T1  WHERE 平均成绩 > T2.平均成绩) as 名次,       
    S# as 学生学号,平均成绩      
    FROM (SELECT S#,AVG(score) 平均成绩             
    FROM SC         
    GROUP BY S# ) AS T2      
    ORDER BY 平均成绩 desc; 
    

    25、查询各科成绩前三名的记录(不考虑成绩并列情况):

    SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数       
    FROM SC t1        
    WHERE score IN 
    (SELECT TOP 3 score               
    FROM SC               
    WHERE t1.C#= C#             
    ORDER BY score DESC)        
    

    26、查询每门课程被选修的学生数:

    select c#, count(s#) 
    from sc 
    group by c#;
    

    27、查询出只选修一门课程的全部学生的学号和姓名:

    select sc.s#, student.sname, count(c#) as 选课数
    from sc,student 
    where sc.s# =student.s# 
    group by sc.s#,Student.sname 
    having count(c#)=1;
    

    28、查询男生、女生人数:

    select count(Ssex) as 男生人数 
    from student 
    group by Ssex 
    having Ssex='男';
    select count(Ssex) as 女生人数 
    from student 
    group by Ssex 
    having Ssex='女';
    

    29、查询姓“张”的学生名单:

    select sname 
    from student 
    where sname like '张%';
    

    30、查询同名同姓的学生名单,并统计同名人数:

    select sanme,count(*) 
    from student 
    group by sname 
    havang count(*)>1;
    

    31、1981年出生的学生名单(注:student表中sage列的类型是datetime):

    select sname, convert(char(11),DATEPART(year,sage)) as age
    from student 
    where convert(char(11),DATEPART(year,Sage))='1981';
    

    32、查询平均成绩大于85的所有学生的学号、姓名和平均成绩:

    select Sname,SC.S# ,avg(score)     
    from Student,SC      
    where Student.S#=SC.S# 
    group by SC.S#,Sname 
    having    avg(score)>85;
    

    33、查询每门课程的平均成绩,结果按平均成绩升序排序,平均成绩相同时,按课程号降序排列:

    select C#, avg(score) 
    from sc 
    group by c# 
    order by avg(score), c# desc;
    

    34、查询课程名称为“数据库”,且分数低于60的学生名字和分数:

    select sname, isnull(score,0) 
    from student, sc ,course 
    where sc.s#=student.s#  and sc.c#=course.c# and course.cname='数据库' and score<60;
    

    35、查询所有学生的选课情况:

    select sc.s#,sc.c#,sname,cname 
    from sc,student course 
    where sc.s#=student.s# and sc.c#=course.c#;
    

    36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数:

    select distinct student.s#,student.sname,sc.c#,sc.score 
    from student,sc 
    where sc.score>=70 and sc.s#=student.s#;
    

    37、查询不及格的课程,并按课程号从大到小的排列:

    select c# 
    from sc 
    where score<60 
    order by c#;
    

    38、查询课程编号为“003”且课程成绩在80分以上的学生的学号和姓名:

    select sc.s#,student.sname 
    from sc,student 
    where sc.s#=student.s# and score>80 and c#='003';
    

    39、求选了课程的学生人数:

    select count(*) from sc;
    

    40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩:

    select student.sname,score 
    from student,sc,course c, teacher 
    where student.s#=sc.S# and sc.c#=c.c#
    and c.T#=teacher.T#
    and teacher.tname='叶平' 
    and sc.score=(select max(score) from sc where c#=c.c#);
    

    41、查询各个课程及相应的选修人数:

    select count(*) from sc group by c#;
    

    42、查询不同课程成绩相同的学生和学号、课程号、学生成绩:

    select distinct a.s#,b.score 
    from sc a ,sc b 
    where a.score=b.score 
    and a.c#<>b.c#;
    

    43、查询每门课程成绩最好的前两名:

    select t1.s# as 学生ID,t1.c#  课程ID, Score as 分数
    from sc t1 
    where score in (select top 2 score from sc 
            where t1.c#=c#
            order by score desc)
    order by t1.c#;
    

    44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排序,若人数相同,按课程号升序排序:

    select c# as 课程号,count(*) as 人数
    from sc 
    group by c#
    order by count(*) desc c#;
    

    45、检索至少选修两门课程的学生学号:

    select s# 
    from sc 
    group by s# 
    having count(*)>=2;
    

    46、查询全部学生选修的课程和课程号和课程名:

    select c# ,cname
    from course 
    where c# in (select c# from sc group by c#);
    

    47、查询没学过”叶平”老师讲授的任一门课程的学生姓名:

    select sname 
    from student 
    where s# not in (select s# from course,teacher,sc where course.t#=teacher.t# and sc.c#=course.c# 
    and tname='叶平');
    

    48、查询两门以上不及格课程的同学的学号以及其平均成绩:

    select s#,avg(isnull(score,0)) 
    from sc 
    where s# in (select s# from sc where score<60 group by s# having count(*)>2)
    group by s#;
    

    49、检索“004”课程分数小于60,按分数降序排列的同学学号:

    select s# 
    from sc 
    where c#='004' 
    and score<60 
    order by score desc;
    

    50、删除“002”同学的“001”课程的成绩:

    delect from sc 
    where s#='002' 
    and c#='001';



    转自:http://blog.csdn.net/hundan_520520/article/details/54881208
  • 相关阅读:
    Maven 那点事儿
    maven pom文件详解
    Maven Missing artifact jar
    JVM调优总结 -Xms -Xmx -Xmn -Xss
    LoadRunner做性能测试 从设计到分析执行
    linux内核参数注释与优化
    tcpdump详解
    [转]Linux服务器上11种网络连接状态 和 TCP三次握手/四次挥手详解
    MSM--Memcached_Session_Manager介绍及使用
    黏性Session和非黏性Session
  • 原文地址:https://www.cnblogs.com/twoheads/p/8406213.html
Copyright © 2020-2023  润新知