LeetCode 278 First Bad Version

题目：

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

Example:

Given n = 5, and version = 4 is the first bad version.

call isBadVersion(3) -> false
call isBadVersion(5) -> true
call isBadVersion(4) -> true

Then 4 is the first bad version. 

解法：

从头到尾搜索会超时，很容易想到二分法

/* The isBadVersion API is defined in the parent class VersionControl.
      boolean isBadVersion(int version); */

public class Solution extends VersionControl {
    public int firstBadVersion(int n) {
        
        int s = 1;
        int e = n;
        int m = 0;
        while(s<e)
        {
            m = s + (e-s)/2;
            if(isBadVersion(m)) e = m;
            else s = m+1;
        }
        return s;
    }
}

PS： 这里的中点 m 等于 s+(e-s)/2 而不能是 (e+s)/2，这是个坑点，e+s可能会溢出int的范围，而得到错误的结果甚至是死循环。