题目:
Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "hello", needle = "ll" Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba" Output: -1
Clarification:
What should we return when needle
is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle
is an empty string. This is consistent to C's strstr() and Java's indexOf().
解法:
字符串匹配,算法有很多,BF,KMP等等,因为这是个简单题,所以这里用最简单的暴力解法BF(其实其他的我还不会写)
class Solution { public int strStr(String haystack, String needle) { int hlen = haystack.length(); int nlen = needle.length(); if(nlen==0) return 0; if(nlen>hlen) return -1; for(int i=0;i<hlen-nlen+1;i++) if(needle.equals(haystack.substring(i,i+nlen))) return i; return -1; } }