noi 提取数字串按数值排序

原题链接：点我转移

#include<bits/stdc++.h>
using namespace std;
int main()
{
    char str[400];
    while(cin >> str)
    {
        int num[200]={0};
        int flag=0,coun=0;
        for (int i = 0; str[i] != ''; i++)
        {
            if (flag == 0 && str[i] >= '0'&&str[i] <= '9')
            {
                coun++;
                num[coun] = str[i] - '0';
                flag = 1;
                continue;
            }
            if (flag == 1 && str[i] >= '0'&&str[i] <= '9')
            {
                num[coun] = num[coun] * 10 + str[i] - '0';
                continue;
            }
            if(flag==1&&( str[i] < '0'||str[i] > '9'))
                flag = 0;
        }
        if (coun == 0)
            cout << "0" << endl;
        else
        {
            sort(num+1,num+coun+1);
            for (int i = 1; i <= coun-1; i++)
                cout << num[i]<<",";
            cout << num[coun]<<endl;
        }
    }

    return 0;
}