Building your Recurrent Neural Network - Step by Step
Welcome to Course 5's first assignment! In this assignment, you will implement key components of a Recurrent Neural Network in numpy.
Recurrent Neural Networks (RNN) are very effective for Natural Language Processing and other sequence tasks because they have "memory". They can read inputs (x^{langle t angle}) (such as words) one at a time, and remember some information/context through the hidden layer activations that get passed from one time-step to the next. This allows a unidirectional RNN to take information from the past to process later inputs. A bidirectional RNN can take context from both the past and the future.
Notation:
Superscript ([l]) denotes an object associated with the (l^{th}) layer.
Superscript ((i)) denotes an object associated with the (i^{th}) example.
Superscript (langle t angle) denotes an object at the (t^{th}) time-step.
Subscript (i) denotes the (i^{th}) entry of a vector.
Example:
- (a^{(2)[3]<4>}_5) denotes the activation of the 2nd training example (2), 3rd layer [3], 4th time step <4>, and 5th entry in the vector.
Pre-requisites
- We assume that you are already familiar with
numpy. - To refresh your knowledge of numpy, you can review course 1 of this specialization "Neural Networks and Deep Learning".
- Specifically, review the week 2 assignment "Python Basics with numpy (optional)".
Be careful when modifying the starter code
- When working on graded functions, please remember to only modify the code that is between the
Python #### START CODE HEREandPython #### END CODE HERE - In particular, Be careful to not modify the first line of graded routines. These start with:
Python # GRADED FUNCTION: routine_name - The automatic grader (autograder) needs these to locate the function.
- Even a change in spacing will cause issues with the autograder.
- It will return 'failed' if these are modified or missing."
Updates for 3b
If you were working on the notebook before this update...
- The current notebook is version "3b".
- You can find your original work saved in the notebook with the previous version name ("v3a")
- To view the file directory, go to the menu "File->Open", and this will open a new tab that shows the file directory.
List of updates
rnn_cell_backward- fixed error in equations
- harmonize rnn backward diagram with rnn_forward diagram and fixed Wax multiple (changed from at to xt).
- clarified dba batch as summing 'm' examples
- aligned equations
lstm_cell_backward- aligned equations
lstm_forward- fixed typo, Wb to bf
lstm_cell_forward- changed c_next_tmp.shape to a_next_tmp.shape in test case
- clarified dbxx batch as summing 'm' examples
Let's first import all the packages that you will need during this assignment.
import numpy as np
from rnn_utils import *
1 - Forward propagation for the basic Recurrent Neural Network
Later this week, you will generate music using an RNN. The basic RNN that you will implement has the structure below. In this example, (T_x = T_y).
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Dimensions of input (x)
Input with (n_x) number of units
- For a single timestep of a single input example, (x^{(i) langle t angle }) is a one-dimensional input vector.
- Using language as an example, a language with a 5000 word vocabulary could be one-hot encoded into a vector that has 5000 units. So (x^{(i)langle t
angle}) would have the shape (5000,).
- We'll use the notation (n_x) to denote the number of units in a single timestep of a single training example.
Time steps of size (T_{x})
- A recurrent neural network has multiple time steps, which we'll index with (t).
- In the lessons, we saw a single training example (x^{(i)}) consist of multiple time steps (T_x). For example, if there are 10 time steps, (T_{x} = 10)
Batches of size (m)
- Let's say we have mini-batches, each with 20 training examples.
- To benefit from vectorization, we'll stack 20 columns of (x^{(i)}) examples.
- For example, this tensor has the shape (5000,20,10).
- We'll use (m) to denote the number of training examples.
- So the shape of a mini-batch is ((n_x,m,T_x))
3D Tensor of shape ((n_{x},m,T_{x}))
- The 3-dimensional tensor (x) of shape ((n_x,m,T_x)) represents the input (x) that is fed into the RNN.
Taking a 2D slice for each time step: (x^{langle t angle})
- At each time step, we'll use a mini-batches of training examples (not just a single example).
- So, for each time step (t), we'll use a 2D slice of shape ((n_x,m)).
- We're referring to this 2D slice as (x^{langle t
angle}). The variable name in the code is
xt.
Definition of hidden state (a)
- The activation (a^{langle t angle}) that is passed to the RNN from one time step to another is called a "hidden state."
Dimensions of hidden state (a)
- Similar to the input tensor (x), the hidden state for a single training example is a vector of length (n_{a}).
- If we include a mini-batch of (m) training examples, the shape of a mini-batch is ((n_{a},m)).
- When we include the time step dimension, the shape of the hidden state is ((n_{a}, m, T_x))
- We will loop through the time steps with index (t), and work with a 2D slice of the 3D tensor.
- We'll refer to this 2D slice as (a^{langle t angle}).
- In the code, the variable names we use are either
a_prevora_next, depending on the function that's being implemented. - The shape of this 2D slice is ((n_{a}, m))
Dimensions of prediction (hat{y})
- Similar to the inputs and hidden states, (hat{y}) is a 3D tensor of shape ((n_{y}, m, T_{y})).
- (n_{y}): number of units in the vector representing the prediction.
- (m): number of examples in a mini-batch.
- (T_{y}): number of time steps in the prediction.
- For a single time step (t), a 2D slice (hat{y}^{langle t angle}) has shape ((n_{y}, m)).
- In the code, the variable names are:
y_pred: (hat{y})yt_pred: (hat{y}^{langle t angle})
Here's how you can implement an RNN:
Steps:
- Implement the calculations needed for one time-step of the RNN.
- Implement a loop over (T_x) time-steps in order to process all the inputs, one at a time.
1.1 - RNN cell
A recurrent neural network can be seen as the repeated use of a single cell. You are first going to implement the computations for a single time-step. The following figure describes the operations for a single time-step of an RNN cell.
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rnn cell versus rnn_cell_forward
- Note that an RNN cell outputs the hidden state (a^{langle t
angle}).
- The rnn cell is shown in the figure as the inner box which has solid lines.
- The rnn cell is shown in the figure as the inner box which has solid lines.
- The function that we will implement,
rnn_cell_forward, also calculates the prediction (hat{y}^{langle t angle})- The rnn_cell_forward is shown in the figure as the outer box that has dashed lines.
Exercise: Implement the RNN-cell described in Figure (2).
Instructions:
- Compute the hidden state with tanh activation: (a^{langle t angle} = anh(W_{aa} a^{langle t-1 angle} + W_{ax} x^{langle t angle} + b_a)).
- Using your new hidden state (a^{langle t
angle}), compute the prediction (hat{y}^{langle t
angle} = softmax(W_{ya} a^{langle t
angle} + b_y)). We provided the function
softmax. - Store ((a^{langle t
angle}, a^{langle t-1
angle}, x^{langle t
angle}, parameters)) in a
cache. - Return (a^{langle t
angle}) , (hat{y}^{langle t
angle}) and
cache
Additional Hints
- numpy.tanh
- We've created a
softmaxfunction that you can use. It is located in the file 'rnn_utils.py' and has been imported. - For matrix multiplication, use numpy.dot
# GRADED FUNCTION: rnn_cell_forward
def rnn_cell_forward(xt, a_prev, parameters):
"""
Implements a single forward step of the RNN-cell as described in Figure (2)
Arguments:
xt -- your input data at timestep "t", numpy array of shape (n_x, m).
a_prev -- Hidden state at timestep "t-1", numpy array of shape (n_a, m)
parameters -- python dictionary containing:
Wax -- Weight matrix multiplying the input, numpy array of shape (n_a, n_x)
Waa -- Weight matrix multiplying the hidden state, numpy array of shape (n_a, n_a)
Wya -- Weight matrix relating the hidden-state to the output, numpy array of shape (n_y, n_a)
ba -- Bias, numpy array of shape (n_a, 1)
by -- Bias relating the hidden-state to the output, numpy array of shape (n_y, 1)
Returns:
a_next -- next hidden state, of shape (n_a, m)
yt_pred -- prediction at timestep "t", numpy array of shape (n_y, m)
cache -- tuple of values needed for the backward pass, contains (a_next, a_prev, xt, parameters)
"""
# Retrieve parameters from "parameters"
Wax = parameters["Wax"]
Waa = parameters["Waa"]
Wya = parameters["Wya"]
ba = parameters["ba"]
by = parameters["by"]
### START CODE HERE ### (≈2 lines)
# compute next activation state using the formula given above
a_next = np.tanh((np.dot(Waa,a_prev)+ np.dot(Wax, xt)+ba))
# compute output of the current cell using the formula given above
yt_pred = softmax(np.dot(Wya, a_next) + by)
### END CODE HERE ###
# store values you need for backward propagation in cache
cache = (a_next, a_prev, xt, parameters)
return a_next, yt_pred, cache
np.random.seed(1)
xt_tmp = np.random.randn(3,10)
a_prev_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Waa'] = np.random.randn(5,5)
parameters_tmp['Wax'] = np.random.randn(5,3)
parameters_tmp['Wya'] = np.random.randn(2,5)
parameters_tmp['ba'] = np.random.randn(5,1)
parameters_tmp['by'] = np.random.randn(2,1)
a_next_tmp, yt_pred_tmp, cache_tmp = rnn_cell_forward(xt_tmp, a_prev_tmp, parameters_tmp)
print("a_next[4] =
", a_next_tmp[4])
print("a_next.shape =
", a_next_tmp.shape)
print("yt_pred[1] =
", yt_pred_tmp[1])
print("yt_pred.shape =
", yt_pred_tmp.shape)
a_next[4] =
[ 0.59584544 0.18141802 0.61311866 0.99808218 0.85016201 0.99980978
-0.18887155 0.99815551 0.6531151 0.82872037]
a_next.shape =
(5, 10)
yt_pred[1] =
[ 0.9888161 0.01682021 0.21140899 0.36817467 0.98988387 0.88945212
0.36920224 0.9966312 0.9982559 0.17746526]
yt_pred.shape =
(2, 10)
Expected Output:
a_next[4] =
[ 0.59584544 0.18141802 0.61311866 0.99808218 0.85016201 0.99980978
-0.18887155 0.99815551 0.6531151 0.82872037]
a_next.shape =
(5, 10)
yt_pred[1] =
[ 0.9888161 0.01682021 0.21140899 0.36817467 0.98988387 0.88945212
0.36920224 0.9966312 0.9982559 0.17746526]
yt_pred.shape =
(2, 10)
1.2 - RNN forward pass
- A recurrent neural network (RNN) is a repetition of the RNN cell that you've just built.
- If your input sequence of data is 10 time steps long, then you will re-use the RNN cell 10 times.
- Each cell takes two inputs at each time step:
- (a^{langle t-1 angle}): The hidden state from the previous cell.
- (x^{langle t angle}): The current time-step's input data.
- It has two outputs at each time step:
- A hidden state ((a^{langle t angle}))
- A prediction ((y^{langle t angle}))
- The weights and biases ((W_{aa}, b_{a}, W_{ax}, b_{x})) are re-used each time step.
- They are maintained between calls to rnn_cell_forward in the 'parameters' dictionary.
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Exercise: Code the forward propagation of the RNN described in Figure (3).
Instructions:
- Create a 3D array of zeros, (a) of shape ((n_{a}, m, T_{x})) that will store all the hidden states computed by the RNN.
- Create a 3D array of zeros, (hat{y}), of shape ((n_{y}, m, T_{x})) that will store the predictions.
- Note that in this case, (T_{y} = T_{x}) (the prediction and input have the same number of time steps).
- Initialize the 2D hidden state
a_nextby setting it equal to the initial hidden state, (a_{0}). - At each time step (t):
- Get (x^{langle t
angle}), which is a 2D slice of (x) for a single time step (t).
- (x^{langle t angle}) has shape ((n_{x}, m))
- (x) has shape ((n_{x}, m, T_{x}))
- Update the 2D hidden state (a^{langle t
angle}) (variable name
a_next), the prediction (hat{y}^{langle t angle}) and the cache by runningrnn_cell_forward.- (a^{langle t angle}) has shape ((n_{a}, m))
- Store the 2D hidden state in the 3D tensor (a), at the (t^{th}) position.
- (a) has shape ((n_{a}, m, T_{x}))
- Store the 2D (hat{y}^{langle t
angle}) prediction (variable name
yt_pred) in the 3D tensor (hat{y}_{pred}) at the (t^{th}) position.- (hat{y}^{langle t angle}) has shape ((n_{y}, m))
- (hat{y}) has shape ((n_{y}, m, T_x))
- Append the cache to the list of caches.
- Get (x^{langle t
angle}), which is a 2D slice of (x) for a single time step (t).
- Return the 3D tensor (a) and (hat{y}), as well as the list of caches.
Additional Hints
- np.zeros
- If you have a 3 dimensional numpy array and are indexing by its third dimension, you can use array slicing like this:
var_name[:,:,i].
# GRADED FUNCTION: rnn_forward
def rnn_forward(x, a0, parameters):
"""
Implement the forward propagation of the recurrent neural network described in Figure (3).
Arguments:
x -- Input data for every time-step, of shape (n_x, m, T_x).
a0 -- Initial hidden state, of shape (n_a, m)
parameters -- python dictionary containing:
Waa -- Weight matrix multiplying the hidden state, numpy array of shape (n_a, n_a)
Wax -- Weight matrix multiplying the input, numpy array of shape (n_a, n_x)
Wya -- Weight matrix relating the hidden-state to the output, numpy array of shape (n_y, n_a)
ba -- Bias numpy array of shape (n_a, 1)
by -- Bias relating the hidden-state to the output, numpy array of shape (n_y, 1)
Returns:
a -- Hidden states for every time-step, numpy array of shape (n_a, m, T_x)
y_pred -- Predictions for every time-step, numpy array of shape (n_y, m, T_x)
caches -- tuple of values needed for the backward pass, contains (list of caches, x)
"""
# Initialize "caches" which will contain the list of all caches
caches = []
# Retrieve dimensions from shapes of x and parameters["Wya"]
n_x, m, T_x = x.shape
n_y, n_a = parameters["Wya"].shape
### START CODE HERE ###
# initialize "a" and "y_pred" with zeros (≈2 lines)
a = np.zeros((n_a, m, T_x));
y_pred = np.zeros((n_y,m,T_x));
# Initialize a_next (≈1 line)
a_next = a0;
# loop over all time-steps of the input 'x' (1 line)
for t in range(x.shape[2]):
# Update next hidden state, compute the prediction, get the cache (≈2 lines)
xt = x[:,:,t]
a_next, yt_pred, cache = rnn_cell_forward(xt, a_next, parameters)
# Save the value of the new "next" hidden state in a (≈1 line)
a[:,:,t] = a_next
# Save the value of the prediction in y (≈1 line)
y_pred[:,:,t] = yt_pred
# Append "cache" to "caches" (≈1 line)
caches.append(cache)
### END CODE HERE ###
# store values needed for backward propagation in cache
caches = (caches, x)
return a, y_pred, caches
np.random.seed(1)
x_tmp = np.random.randn(3,10,4)
a0_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Waa'] = np.random.randn(5,5)
parameters_tmp['Wax'] = np.random.randn(5,3)
parameters_tmp['Wya'] = np.random.randn(2,5)
parameters_tmp['ba'] = np.random.randn(5,1)
parameters_tmp['by'] = np.random.randn(2,1)
a_tmp, y_pred_tmp, caches_tmp = rnn_forward(x_tmp, a0_tmp, parameters_tmp)
print("a[4][1] =
", a_tmp[4][1])
print("a.shape =
", a_tmp.shape)
print("y_pred[1][3] =
", y_pred_tmp[1][3])
print("y_pred.shape =
", y_pred_tmp.shape)
print("caches[1][1][3] =
", caches_tmp[1][1][3])
print("len(caches) =
", len(caches_tmp))
a[4][1] =
[-0.99999375 0.77911235 -0.99861469 -0.99833267]
a.shape =
(5, 10, 4)
y_pred[1][3] =
[ 0.79560373 0.86224861 0.11118257 0.81515947]
y_pred.shape =
(2, 10, 4)
caches[1][1][3] =
[-1.1425182 -0.34934272 -0.20889423 0.58662319]
len(caches) =
2
Expected Output:
a[4][1] =
[-0.99999375 0.77911235 -0.99861469 -0.99833267]
a.shape =
(5, 10, 4)
y_pred[1][3] =
[ 0.79560373 0.86224861 0.11118257 0.81515947]
y_pred.shape =
(2, 10, 4)
caches[1][1][3] =
[-1.1425182 -0.34934272 -0.20889423 0.58662319]
len(caches) =
2
Congratulations! You've successfully built the forward propagation of a recurrent neural network from scratch.
Situations when this RNN will perform better:
- This will work well enough for some applications, but it suffers from the vanishing gradient problems.
- The RNN works best when each output (hat{y}^{langle t
angle}) can be estimated using "local" context.
- "Local" context refers to information that is close to the prediction's time step (t).
- More formally, local context refers to inputs (x^{langle t' angle}) and predictions (hat{y}^{langle t angle}) where (t') is close to (t).
In the next part, you will build a more complex LSTM model, which is better at addressing vanishing gradients. The LSTM will be better able to remember a piece of information and keep it saved for many timesteps.
2 - Long Short-Term Memory (LSTM) network
The following figure shows the operations of an LSTM-cell.
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Note, the (softmax^{*}) includes a dense layer and softmax
Similar to the RNN example above, you will start by implementing the LSTM cell for a single time-step. Then you can iteratively call it from inside a "for-loop" to have it process an input with (T_x) time-steps.
Overview of gates and states
- Forget gate (mathbf{Gamma}_{f})
- Let's assume we are reading words in a piece of text, and plan to use an LSTM to keep track of grammatical structures, such as whether the subject is singular ("puppy") or plural ("puppies").
- If the subject changes its state (from a singular word to a plural word), the memory of the previous state becomes outdated, so we "forget" that outdated state.
- The "forget gate" is a tensor containing values that are between 0 and 1.
- If a unit in the forget gate has a value close to 0, the LSTM will "forget" the stored state in the corresponding unit of the previous cell state.
- If a unit in the forget gate has a value close to 1, the LSTM will mostly remember the corresponding value in the stored state.
Equation
[mathbf{Gamma}_f^{langle t angle} = sigma(mathbf{W}_f[mathbf{a}^{langle t-1 angle}, mathbf{x}^{langle t angle}] + mathbf{b}_f) ag{1} ]
Explanation of the equation:
- (mathbf{W_{f}}) contains weights that govern the forget gate's behavior.
- The previous time step's hidden state ([a^{langle t-1 angle}) and current time step's input (x^{langle t angle}]) are concatenated together and multiplied by (mathbf{W_{f}}).
- A sigmoid function is used to make each of the gate tensor's values (mathbf{Gamma}_f^{langle t angle}) range from 0 to 1.
- The forget gate (mathbf{Gamma}_f^{langle t angle}) has the same dimensions as the previous cell state (c^{langle t-1 angle}).
- This means that the two can be multiplied together, element-wise.
- Multiplying the tensors (mathbf{Gamma}_f^{langle t angle} * mathbf{c}^{langle t-1 angle}) is like applying a mask over the previous cell state.
- If a single value in (mathbf{Gamma}_f^{langle t
angle}) is 0 or close to 0, then the product is close to 0.
- This keeps the information stored in the corresponding unit in (mathbf{c}^{langle t-1 angle}) from being remembered for the next time step.
- Similarly, if one value is close to 1, the product is close to the original value in the previous cell state.
- The LSTM will keep the information from the corresponding unit of (mathbf{c}^{langle t-1 angle}), to be used in the next time step.
Variable names in the code
The variable names in the code are similar to the equations, with slight differences.
Wf: forget gate weight (mathbf{W}_{f})bf: forget gate bias (mathbf{b}_{f})ft: forget gate (Gamma_f^{langle t angle})
Candidate value ( ilde{mathbf{c}}^{langle t angle})
- The candidate value is a tensor containing information from the current time step that may be stored in the current cell state (mathbf{c}^{langle t angle}).
- Which parts of the candidate value get passed on depends on the update gate.
- The candidate value is a tensor containing values that range from -1 to 1.
- The tilde "~" is used to differentiate the candidate ( ilde{mathbf{c}}^{langle t angle}) from the cell state (mathbf{c}^{langle t angle}).
Equation
[mathbf{ ilde{c}}^{langle t angle} = anhleft( mathbf{W}_{c} [mathbf{a}^{langle t - 1 angle}, mathbf{x}^{langle t angle}] + mathbf{b}_{c} ight) ag{3}]
Explanation of the equation
- The 'tanh' function produces values between -1 and +1.
Variable names in the code
cct: candidate value (mathbf{ ilde{c}}^{langle t angle})
- Update gate (mathbf{Gamma}_{i})
- We use the update gate to decide what aspects of the candidate ( ilde{mathbf{c}}^{langle t angle}) to add to the cell state (c^{langle t angle}).
- The update gate decides what parts of a "candidate" tensor ( ilde{mathbf{c}}^{langle t angle}) are passed onto the cell state (mathbf{c}^{langle t angle}).
- The update gate is a tensor containing values between 0 and 1.
- When a unit in the update gate is close to 1, it allows the value of the candidate ( ilde{mathbf{c}}^{langle t angle}) to be passed onto the hidden state (mathbf{c}^{langle t angle})
- When a unit in the update gate is close to 0, it prevents the corresponding value in the candidate from being passed onto the hidden state.
- Notice that we use the subscript "i" and not "u", to follow the convention used in the literature.
Equation
[mathbf{Gamma}_i^{langle t angle} = sigma(mathbf{W}_i[a^{langle t-1 angle}, mathbf{x}^{langle t angle}] + mathbf{b}_i) ag{2} ]
Explanation of the equation
- Similar to the forget gate, here (mathbf{Gamma}_i^{langle t angle}), the sigmoid produces values between 0 and 1.
- The update gate is multiplied element-wise with the candidate, and this product ((mathbf{Gamma}_{i}^{langle t angle} * ilde{c}^{langle t angle})) is used in determining the cell state (mathbf{c}^{langle t angle}).
Variable names in code (Please note that they're different than the equations)
In the code, we'll use the variable names found in the academic literature. These variables don't use "u" to denote "update".
Wiis the update gate weight (mathbf{W}_i) (not "Wu")biis the update gate bias (mathbf{b}_i) (not "bu")itis the forget gate (mathbf{Gamma}_i^{langle t angle}) (not "ut")
- Cell state (mathbf{c}^{langle t angle})
- The cell state is the "memory" that gets passed onto future time steps.
- The new cell state (mathbf{c}^{langle t angle}) is a combination of the previous cell state and the candidate value.
Equation
[ mathbf{c}^{langle t angle} = mathbf{Gamma}_f^{langle t angle}* mathbf{c}^{langle t-1 angle} + mathbf{Gamma}_{i}^{langle t angle} *mathbf{ ilde{c}}^{langle t angle} ag{4} ]
Explanation of equation
- The previous cell state (mathbf{c}^{langle t-1 angle}) is adjusted (weighted) by the forget gate (mathbf{Gamma}_{f}^{langle t angle})
- and the candidate value ( ilde{mathbf{c}}^{langle t angle}), adjusted (weighted) by the update gate (mathbf{Gamma}_{i}^{langle t angle})
Variable names and shapes in the code
c: cell state, including all time steps, (mathbf{c}) shape ((n_{a}, m, T))c_next: new (next) cell state, (mathbf{c}^{langle t angle}) shape ((n_{a}, m))c_prev: previous cell state, (mathbf{c}^{langle t-1 angle}), shape ((n_{a}, m))
- Output gate (mathbf{Gamma}_{o})
- The output gate decides what gets sent as the prediction (output) of the time step.
- The output gate is like the other gates. It contains values that range from 0 to 1.
Equation
[ mathbf{Gamma}_o^{langle t angle}= sigma(mathbf{W}_o[mathbf{a}^{langle t-1 angle}, mathbf{x}^{langle t angle}] + mathbf{b}_{o}) ag{5}]
Explanation of the equation
- The output gate is determined by the previous hidden state (mathbf{a}^{langle t-1 angle}) and the current input (mathbf{x}^{langle t angle})
- The sigmoid makes the gate range from 0 to 1.
Variable names in the code
Wo: output gate weight, (mathbf{W_o})bo: output gate bias, (mathbf{b_o})ot: output gate, (mathbf{Gamma}_{o}^{langle t angle})
- Hidden state (mathbf{a}^{langle t angle})
- The hidden state gets passed to the LSTM cell's next time step.
- It is used to determine the three gates ((mathbf{Gamma}_{f}, mathbf{Gamma}_{u}, mathbf{Gamma}_{o})) of the next time step.
- The hidden state is also used for the prediction (y^{langle t angle}).
Equation
[ mathbf{a}^{langle t angle} = mathbf{Gamma}_o^{langle t angle} * anh(mathbf{c}^{langle t angle}) ag{6} ]
Explanation of equation
- The hidden state (mathbf{a}^{langle t angle}) is determined by the cell state (mathbf{c}^{langle t angle}) in combination with the output gate (mathbf{Gamma}_{o}).
- The cell state state is passed through the "tanh" function to rescale values between -1 and +1.
- The output gate acts like a "mask" that either preserves the values of ( anh(mathbf{c}^{langle t angle})) or keeps those values from being included in the hidden state (mathbf{a}^{langle t angle})
Variable names and shapes in the code
a: hidden state, including time steps. (mathbf{a}) has shape ((n_{a}, m, T_{x}))- 'a_prev`: hidden state from previous time step. (mathbf{a}^{langle t-1 angle}) has shape ((n_{a}, m))
a_next: hidden state for next time step. (mathbf{a}^{langle t angle}) has shape ((n_{a}, m))
- Prediction (mathbf{y}^{langle t angle}_{pred})
- The prediction in this use case is a classification, so we'll use a softmax.
The equation is:
[mathbf{y}^{langle t
angle}_{pred} = extrm{softmax}(mathbf{W}_{y} mathbf{a}^{langle t
angle} + mathbf{b}_{y})]
Variable names and shapes in the code
y_pred: prediction, including all time steps. (mathbf{y}_{pred}) has shape ((n_{y}, m, T_{x})). Note that ((T_{y} = T_{x})) for this example.yt_pred: prediction for the current time step (t). (mathbf{y}^{langle t angle}_{pred}) has shape ((n_{y}, m))
2.1 - LSTM cell
Exercise: Implement the LSTM cell described in the Figure (4).
Instructions:
- Concatenate the hidden state (a^{langle t-1
angle}) and input (x^{langle t
angle}) into a single matrix:
[concat = egin{bmatrix} a^{langle t-1 angle} \ x^{langle t angle} end{bmatrix}]
- Compute all the formulas 1 through 6 for the gates, hidden state, and cell state.
- Compute the prediction (y^{langle t angle}).
Additional Hints
- You can use numpy.concatenate. Check which value to use for the
axisparameter. - The functions
sigmoid()andsoftmaxare imported fromrnn_utils.py. - numpy.tanh
- Use np.dot for matrix multiplication.
- Notice that the variable names
Wi,birefer to the weights and biases of the update gate. There are no variables named "Wu" or "bu" in this function.
# GRADED FUNCTION: lstm_cell_forward
def lstm_cell_forward(xt, a_prev, c_prev, parameters):
"""
Implement a single forward step of the LSTM-cell as described in Figure (4)
Arguments:
xt -- your input data at timestep "t", numpy array of shape (n_x, m).
a_prev -- Hidden state at timestep "t-1", numpy array of shape (n_a, m)
c_prev -- Memory state at timestep "t-1", numpy array of shape (n_a, m)
parameters -- python dictionary containing:
Wf -- Weight matrix of the forget gate, numpy array of shape (n_a, n_a + n_x)
bf -- Bias of the forget gate, numpy array of shape (n_a, 1)
Wi -- Weight matrix of the update gate, numpy array of shape (n_a, n_a + n_x)
bi -- Bias of the update gate, numpy array of shape (n_a, 1)
Wc -- Weight matrix of the first "tanh", numpy array of shape (n_a, n_a + n_x)
bc -- Bias of the first "tanh", numpy array of shape (n_a, 1)
Wo -- Weight matrix of the output gate, numpy array of shape (n_a, n_a + n_x)
bo -- Bias of the output gate, numpy array of shape (n_a, 1)
Wy -- Weight matrix relating the hidden-state to the output, numpy array of shape (n_y, n_a)
by -- Bias relating the hidden-state to the output, numpy array of shape (n_y, 1)
Returns:
a_next -- next hidden state, of shape (n_a, m)
c_next -- next memory state, of shape (n_a, m)
yt_pred -- prediction at timestep "t", numpy array of shape (n_y, m)
cache -- tuple of values needed for the backward pass, contains (a_next, c_next, a_prev, c_prev, xt, parameters)
Note: ft/it/ot stand for the forget/update/output gates, cct stands for the candidate value (c tilde),
c stands for the cell state (memory)
"""
# Retrieve parameters from "parameters"
Wf = parameters["Wf"] # forget gate weight
bf = parameters["bf"]
Wi = parameters["Wi"] # update gate weight (notice the variable name)
bi = parameters["bi"] # (notice the variable name)
Wc = parameters["Wc"] # candidate value weight
bc = parameters["bc"]
Wo = parameters["Wo"] # output gate weight
bo = parameters["bo"]
Wy = parameters["Wy"] # prediction weight
by = parameters["by"]
# Retrieve dimensions from shapes of xt and Wy
n_x, m = xt.shape
n_y, n_a = Wy.shape
### START CODE HERE ###
# Concatenate a_prev and xt (≈1 line)
concat = np.concatenate((a_prev, xt),axis = 0)
# Compute values for ft (forget gate), it (update gate),
# cct (candidate value), c_next (cell state),
# ot (output gate), a_next (hidden state) (≈6 lines)
ft = sigmoid(np.dot(Wf,concat)+bf) # forget gate
it = sigmoid(np.dot(Wi,concat)+bi) # update gate
cct = np.tanh(np.dot(Wc,concat)+bc) # candidate value
c_next = ft * c_prev + it * cct # cell state
ot = sigmoid(np.dot(Wo,concat)+bo) # output gate
a_next = ot * np.tanh(c_next) # hidden state
# Compute prediction of the LSTM cell (≈1 line)
yt_pred = softmax(np.dot(Wy, a_next)+ by);
### END CODE HERE ###
# store values needed for backward propagation in cache
cache = (a_next, c_next, a_prev, c_prev, ft, it, cct, ot, xt, parameters)
return a_next, c_next, yt_pred, cache
np.random.seed(1)
xt_tmp = np.random.randn(3,10)
a_prev_tmp = np.random.randn(5,10)
c_prev_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wf'] = np.random.randn(5, 5+3)
parameters_tmp['bf'] = np.random.randn(5,1)
parameters_tmp['Wi'] = np.random.randn(5, 5+3)
parameters_tmp['bi'] = np.random.randn(5,1)
parameters_tmp['Wo'] = np.random.randn(5, 5+3)
parameters_tmp['bo'] = np.random.randn(5,1)
parameters_tmp['Wc'] = np.random.randn(5, 5+3)
parameters_tmp['bc'] = np.random.randn(5,1)
parameters_tmp['Wy'] = np.random.randn(2,5)
parameters_tmp['by'] = np.random.randn(2,1)
a_next_tmp, c_next_tmp, yt_tmp, cache_tmp = lstm_cell_forward(xt_tmp, a_prev_tmp, c_prev_tmp, parameters_tmp)
print("a_next[4] =
", a_next_tmp[4])
print("a_next.shape = ", a_next_tmp.shape)
print("c_next[2] =
", c_next_tmp[2])
print("c_next.shape = ", c_next_tmp.shape)
print("yt[1] =", yt_tmp[1])
print("yt.shape = ", yt_tmp.shape)
print("cache[1][3] =
", cache_tmp[1][3])
print("len(cache) = ", len(cache_tmp))
a_next[4] =
[-0.66408471 0.0036921 0.02088357 0.22834167 -0.85575339 0.00138482
0.76566531 0.34631421 -0.00215674 0.43827275]
a_next.shape = (5, 10)
c_next[2] =
[ 0.63267805 1.00570849 0.35504474 0.20690913 -1.64566718 0.11832942
0.76449811 -0.0981561 -0.74348425 -0.26810932]
c_next.shape = (5, 10)
yt[1] = [ 0.79913913 0.15986619 0.22412122 0.15606108 0.97057211 0.31146381
0.00943007 0.12666353 0.39380172 0.07828381]
yt.shape = (2, 10)
cache[1][3] =
[-0.16263996 1.03729328 0.72938082 -0.54101719 0.02752074 -0.30821874
0.07651101 -1.03752894 1.41219977 -0.37647422]
len(cache) = 10
Expected Output:
a_next[4] =
[-0.66408471 0.0036921 0.02088357 0.22834167 -0.85575339 0.00138482
0.76566531 0.34631421 -0.00215674 0.43827275]
a_next.shape = (5, 10)
c_next[2] =
[ 0.63267805 1.00570849 0.35504474 0.20690913 -1.64566718 0.11832942
0.76449811 -0.0981561 -0.74348425 -0.26810932]
c_next.shape = (5, 10)
yt[1] = [ 0.79913913 0.15986619 0.22412122 0.15606108 0.97057211 0.31146381
0.00943007 0.12666353 0.39380172 0.07828381]
yt.shape = (2, 10)
cache[1][3] =
[-0.16263996 1.03729328 0.72938082 -0.54101719 0.02752074 -0.30821874
0.07651101 -1.03752894 1.41219977 -0.37647422]
len(cache) = 10
2.2 - Forward pass for LSTM
Now that you have implemented one step of an LSTM, you can now iterate this over this using a for-loop to process a sequence of (T_x) inputs.
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Exercise: Implement lstm_forward() to run an LSTM over (T_x) time-steps.
Instructions
- Get the dimensions (n_x, n_a, n_y, m, T_x) from the shape of the variables:
xandparameters. - Initialize the 3D tensors (a), (c) and (y).
- (a): hidden state, shape ((n_{a}, m, T_{x}))
- (c): cell state, shape ((n_{a}, m, T_{x}))
- (y): prediction, shape ((n_{y}, m, T_{x})) (Note that (T_{y} = T_{x}) in this example).
- Note Setting one variable equal to the other is a "copy by reference". In other words, don't do `c = a', otherwise both these variables point to the same underlying variable.
- Initialize the 2D tensor (a^{langle t
angle})
- (a^{langle t
angle}) stores the hidden state for time step (t). The variable name is
a_next. - (a^{langle 0
angle}), the initial hidden state at time step 0, is passed in when calling the function. The variable name is
a0. - (a^{langle t angle}) and (a^{langle 0 angle}) represent a single time step, so they both have the shape ((n_{a}, m))
- Initialize (a^{langle t angle}) by setting it to the initial hidden state ((a^{langle 0 angle})) that is passed into the function.
- (a^{langle t
angle}) stores the hidden state for time step (t). The variable name is
- Initialize (c^{langle t
angle}) with zeros.
- The variable name is
c_next. - (c^{langle t angle}) represents a single time step, so its shape is ((n_{a}, m))
- Note: create
c_nextas its own variable with its own location in memory. Do not initialize it as a slice of the 3D tensor (c). In other words, don't doc_next = c[:,:,0].
- The variable name is
- For each time step, do the following:
- From the 3D tensor (x), get a 2D slice (x^{langle t angle}) at time step (t).
- Call the
lstm_cell_forwardfunction that you defined previously, to get the hidden state, cell state, prediction, and cache. - Store the hidden state, cell state and prediction (the 2D tensors) inside the 3D tensors.
- Also append the cache to the list of caches.
# GRADED FUNCTION: lstm_forward
def lstm_forward(x, a0, parameters):
"""
Implement the forward propagation of the recurrent neural network using an LSTM-cell described in Figure (4).
Arguments:
x -- Input data for every time-step, of shape (n_x, m, T_x).
a0 -- Initial hidden state, of shape (n_a, m)
parameters -- python dictionary containing:
Wf -- Weight matrix of the forget gate, numpy array of shape (n_a, n_a + n_x)
bf -- Bias of the forget gate, numpy array of shape (n_a, 1)
Wi -- Weight matrix of the update gate, numpy array of shape (n_a, n_a + n_x)
bi -- Bias of the update gate, numpy array of shape (n_a, 1)
Wc -- Weight matrix of the first "tanh", numpy array of shape (n_a, n_a + n_x)
bc -- Bias of the first "tanh", numpy array of shape (n_a, 1)
Wo -- Weight matrix of the output gate, numpy array of shape (n_a, n_a + n_x)
bo -- Bias of the output gate, numpy array of shape (n_a, 1)
Wy -- Weight matrix relating the hidden-state to the output, numpy array of shape (n_y, n_a)
by -- Bias relating the hidden-state to the output, numpy array of shape (n_y, 1)
Returns:
a -- Hidden states for every time-step, numpy array of shape (n_a, m, T_x)
y -- Predictions for every time-step, numpy array of shape (n_y, m, T_x)
c -- The value of the cell state, numpy array of shape (n_a, m, T_x)
caches -- tuple of values needed for the backward pass, contains (list of all the caches, x)
"""
# Initialize "caches", which will track the list of all the caches
caches = []
### START CODE HERE ###
Wy = parameters['Wy'] # saving parameters['Wy'] in a local variable in case students use Wy instead of parameters['Wy']
# Retrieve dimensions from shapes of x and parameters['Wy'] (≈2 lines)
n_x, m, T_x = x.shape
n_y, n_a = parameters["Wy"].shape
# initialize "a", "c" and "y" with zeros (≈3 lines)
a = np.zeros((n_a, m, T_x))
c = np.zeros((n_a, m, T_x))
y = np.zeros((n_y, m, T_x))
# Initialize a_next and c_next (≈2 lines)
a_next = a0
c_next = np.zeros((n_a, m))
# loop over all time-steps
for t in range(T_x):
# Get the 2D slice 'xt' from the 3D input 'x' at time step 't'
xt = x[:,:,t]
# Update next hidden state, next memory state, compute the prediction, get the cache (≈1 line)
a_next, c_next, yt, cache = lstm_cell_forward(xt, a_next, c_next, parameters)
# Save the value of the new "next" hidden state in a (≈1 line)
a[:,:,t] = a_next
# Save the value of the next cell state (≈1 line)
c[:,:,t] = c_next
# Save the value of the prediction in y (≈1 line)
y[:,:,t] = yt
# Append the cache into caches (≈1 line)
caches.append(cache)
### END CODE HERE ###
# store values needed for backward propagation in cache
caches = (caches, x)
return a, y, c, caches
np.random.seed(1)
x_tmp = np.random.randn(3,10,7)
a0_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wf'] = np.random.randn(5, 5+3)
parameters_tmp['bf'] = np.random.randn(5,1)
parameters_tmp['Wi'] = np.random.randn(5, 5+3)
parameters_tmp['bi']= np.random.randn(5,1)
parameters_tmp['Wo'] = np.random.randn(5, 5+3)
parameters_tmp['bo'] = np.random.randn(5,1)
parameters_tmp['Wc'] = np.random.randn(5, 5+3)
parameters_tmp['bc'] = np.random.randn(5,1)
parameters_tmp['Wy'] = np.random.randn(2,5)
parameters_tmp['by'] = np.random.randn(2,1)
a_tmp, y_tmp, c_tmp, caches_tmp = lstm_forward(x_tmp, a0_tmp, parameters_tmp)
print("a[4][3][6] = ", a_tmp[4][3][6])
print("a.shape = ", a_tmp.shape)
print("y[1][4][3] =", y_tmp[1][4][3])
print("y.shape = ", y_tmp.shape)
print("caches[1][1][1] =
", caches_tmp[1][1][1])
print("c[1][2][1]", c_tmp[1][2][1])
print("len(caches) = ", len(caches_tmp))
a[4][3][6] = 0.172117767533
a.shape = (5, 10, 7)
y[1][4][3] = 0.95087346185
y.shape = (2, 10, 7)
caches[1][1][1] =
[ 0.82797464 0.23009474 0.76201118 -0.22232814 -0.20075807 0.18656139
0.41005165]
c[1][2][1] -0.855544916718
len(caches) = 2
Expected Output:
a[4][3][6] = 0.172117767533
a.shape = (5, 10, 7)
y[1][4][3] = 0.95087346185
y.shape = (2, 10, 7)
caches[1][1][1] =
[ 0.82797464 0.23009474 0.76201118 -0.22232814 -0.20075807 0.18656139
0.41005165]
c[1][2][1] -0.855544916718
len(caches) = 2
Congratulations! You have now implemented the forward passes for the basic RNN and the LSTM. When using a deep learning framework, implementing the forward pass is sufficient to build systems that achieve great performance.
The rest of this notebook is optional, and will not be graded.
3 - Backpropagation in recurrent neural networks (OPTIONAL / UNGRADED)
In modern deep learning frameworks, you only have to implement the forward pass, and the framework takes care of the backward pass, so most deep learning engineers do not need to bother with the details of the backward pass. If however you are an expert in calculus and want to see the details of backprop in RNNs, you can work through this optional portion of the notebook.
When in an earlier course you implemented a simple (fully connected) neural network, you used backpropagation to compute the derivatives with respect to the cost to update the parameters. Similarly, in recurrent neural networks you can calculate the derivatives with respect to the cost in order to update the parameters. The backprop equations are quite complicated and we did not derive them in lecture. However, we will briefly present them below.
Note that this notebook does not implement the backward path from the Loss 'J' backwards to 'a'. This would have included the dense layer and softmax which are a part of the forward path. This is assumed to be calculated elsewhere and the result passed to rnn_backward in 'da'. It is further assumed that loss has been adjusted for batch size (m) and division by the number of examples is not required here.
This section is optional and ungraded. It is more difficult and has fewer details regarding its implementation. This section only implements key elements of the full path.
3.1 - Basic RNN backward pass
We will start by computing the backward pass for the basic RNN-cell and then in the following sections, iterate through the cells.
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Recall from lecture, the shorthand for the partial derivative of cost relative to a variable is dVariable. For example, (frac{partial J}{partial W_{ax}}) is (dW_{ax}). This will be used throughout the remaining sections.
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(da_{next}) is (frac{partial{J}}{partial a^{langle t angle}}) and includes loss from previous stages and current stage output logic. The addition shown in green will be part of your implementation of rnn_backward.
Equations
To compute the rnn_cell_backward you can utilize the following equations. It is a good exercise to derive them by hand. Here, (*) denotes element-wise multiplication while the absence of a symbol indicates matrix multiplication.
egin{align}
displaystyle a{langle t
angle} &= anh(W_{ax} x{langle t
angle} + W_{aa} a{langle t-1
angle} + b_{a}) ag{-} [8pt]
displaystyle frac{partial anh(x)} {partial x} &= 1 - anh2(x) ag{-} [8pt]
displaystyle {dW_{ax}} &= (da_{next} * ( 1- anh2(W_{ax}x{langle t
angle}+W_{aa} a{langle t-1
angle} + b_{a}) )) x{langle t
angle T} ag{1} [8pt]
displaystyle dW_{aa} &= (da_{next} * ( 1- anh2(W_{ax}x{langle t
angle}+W_{aa} a{langle t-1
angle} + b_{a}) )) a{langle t-1
angle T} ag{2} [8pt]
displaystyle db_a& = sum_{batch}( da_{next} * ( 1- anh2(W_{ax}x{langle t
angle}+W_{aa} a{langle t-1
angle} + b_{a}) )) ag{3} [8pt]
displaystyle dx{langle t
angle} &= { W_{ax}}T (da_{next} * ( 1- anh2(W_{ax}x{langle t
angle}+W_{aa} a{langle t-1
angle} + b_{a}) )) ag{4} [8pt]
displaystyle da_{prev} &= { W_{aa}}T(da_{next} * ( 1- anh2(W_{ax}x{langle t
angle}+W_{aa} a{langle t-1
angle} + b_{a}) )) ag{5}
end{align}
Implementing rnn_cell_backward
The results can be computed directly by implementing the equations above. However, the above can optionally be simplified by computing 'dz' and utlilizing the chain rule.
This can be further simplified by noting that ( anh(W_{ax}x^{langle t
angle}+W_{aa} a^{langle t-1
angle} + b_{a})) was computed and saved in the forward pass.
To calculate dba, the 'batch' above is a sum across all 'm' examples (axis= 1). Note that you should use the keepdims = True option.
It may be worthwhile to review Course 1 Derivatives with a computational graph through Backpropagation Intuition, which decompose the calculation into steps using the chain rule.
Matrix vector derivatives are described here, though the equations above incorporate the required transformations.
Note rnn_cell_backward does not include the calculation of loss from (y langle t angle), this is incorporated into the incoming da_next. This is a slight mismatch with rnn_cell_forward which includes a dense layer and softmax.
Note: in the code:
(displaystyle dx^{langle t
angle}) is represented by dxt,
(displaystyle d W_{ax}) is represented by dWax,
(displaystyle da_{prev}) is represented by da_prev,
(displaystyle dW_{aa}) is represented by dWaa,
(displaystyle db_{a}) is represented by dba,
dz is not derived above but can optionally be derived by students to simplify the repeated calculations.
def rnn_cell_backward(da_next, cache):
"""
Implements the backward pass for the RNN-cell (single time-step).
Arguments:
da_next -- Gradient of loss with respect to next hidden state
cache -- python dictionary containing useful values (output of rnn_cell_forward())
Returns:
gradients -- python dictionary containing:
dx -- Gradients of input data, of shape (n_x, m)
da_prev -- Gradients of previous hidden state, of shape (n_a, m)
dWax -- Gradients of input-to-hidden weights, of shape (n_a, n_x)
dWaa -- Gradients of hidden-to-hidden weights, of shape (n_a, n_a)
dba -- Gradients of bias vector, of shape (n_a, 1)
"""
# Retrieve values from cache
(a_next, a_prev, xt, parameters) = cache
# Retrieve values from parameters
Wax = parameters["Wax"]
Waa = parameters["Waa"]
Wya = parameters["Wya"]
ba = parameters["ba"]
by = parameters["by"]
### START CODE HERE ###
# compute the gradient of the loss with respect to z (optional) (≈1 line)
dz =(1-a_next**2) * da_next
# compute the gradient of the loss with respect to Wax (≈2 lines)
dxt = np.dot(Wax.T, dz)
dWax = np.dot(dz, xt.T)
# compute the gradient with respect to Waa (≈2 lines)
da_prev = np.dot(Waa.T, dz)
dWaa = np.dot(dz, a_prev.T)
# compute the gradient with respect to b (≈1 line)
dba = np.sum(dz, keepdims=True, axis= -1)
### END CODE HERE ###
# Store the gradients in a python dictionary
gradients = {"dxt": dxt, "da_prev": da_prev, "dWax": dWax, "dWaa": dWaa, "dba": dba}
return gradients
np.random.seed(1)
xt_tmp = np.random.randn(3,10)
a_prev_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wax'] = np.random.randn(5,3)
parameters_tmp['Waa'] = np.random.randn(5,5)
parameters_tmp['Wya'] = np.random.randn(2,5)
parameters_tmp['ba'] = np.random.randn(5,1)
parameters_tmp['by'] = np.random.randn(2,1)
a_next_tmp, yt_tmp, cache_tmp = rnn_cell_forward(xt_tmp, a_prev_tmp, parameters_tmp)
da_next_tmp = np.random.randn(5,10)
gradients_tmp = rnn_cell_backward(da_next_tmp, cache_tmp)
print("gradients["dxt"][1][2] =", gradients_tmp["dxt"][1][2])
print("gradients["dxt"].shape =", gradients_tmp["dxt"].shape)
print("gradients["da_prev"][2][3] =", gradients_tmp["da_prev"][2][3])
print("gradients["da_prev"].shape =", gradients_tmp["da_prev"].shape)
print("gradients["dWax"][3][1] =", gradients_tmp["dWax"][3][1])
print("gradients["dWax"].shape =", gradients_tmp["dWax"].shape)
print("gradients["dWaa"][1][2] =", gradients_tmp["dWaa"][1][2])
print("gradients["dWaa"].shape =", gradients_tmp["dWaa"].shape)
print("gradients["dba"][4] =", gradients_tmp["dba"][4])
print("gradients["dba"].shape =", gradients_tmp["dba"].shape)
gradients["dxt"][1][2] = -1.3872130506
gradients["dxt"].shape = (3, 10)
gradients["da_prev"][2][3] = -0.152399493774
gradients["da_prev"].shape = (5, 10)
gradients["dWax"][3][1] = 0.410772824935
gradients["dWax"].shape = (5, 3)
gradients["dWaa"][1][2] = 1.15034506685
gradients["dWaa"].shape = (5, 5)
gradients["dba"][4] = [ 0.20023491]
gradients["dba"].shape = (5, 1)
Expected Output:
| **gradients["dxt"][1][2]** = | -1.3872130506 |
| **gradients["dxt"].shape** = | (3, 10) |
| **gradients["da_prev"][2][3]** = | -0.152399493774 |
| **gradients["da_prev"].shape** = | (5, 10) |
| **gradients["dWax"][3][1]** = | 0.410772824935 |
| **gradients["dWax"].shape** = | (5, 3) |
| **gradients["dWaa"][1][2]** = | 1.15034506685 |
| **gradients["dWaa"].shape** = | (5, 5) |
| **gradients["dba"][4]** = | [ 0.20023491] |
| **gradients["dba"].shape** = | (5, 1) |
Backward pass through the RNN
Computing the gradients of the cost with respect to (a^{langle t angle}) at every time-step (t) is useful because it is what helps the gradient backpropagate to the previous RNN-cell. To do so, you need to iterate through all the time steps starting at the end, and at each step, you increment the overall (db_a), (dW_{aa}), (dW_{ax}) and you store (dx).
Instructions:
Implement the rnn_backward function. Initialize the return variables with zeros first and then loop through all the time steps while calling the rnn_cell_backward at each time timestep, update the other variables accordingly.
- Note that this notebook does not implement the backward path from the Loss 'J' backwards to 'a'.
- This would have included the dense layer and softmax which are a part of the forward path.
- This is assumed to be calculated elsewhere and the result passed to rnn_backward in 'da'.
- You must combine this with the loss from the previous stages when calling rnn_cell_backward (see figure 7 above).
- It is further assumed that loss has been adjusted for batch size (m).
- Therefore, division by the number of examples is not required here.
def rnn_backward(da, caches):
"""
Implement the backward pass for a RNN over an entire sequence of input data.
Arguments:
da -- Upstream gradients of all hidden states, of shape (n_a, m, T_x)
caches -- tuple containing information from the forward pass (rnn_forward)
Returns:
gradients -- python dictionary containing:
dx -- Gradient w.r.t. the input data, numpy-array of shape (n_x, m, T_x)
da0 -- Gradient w.r.t the initial hidden state, numpy-array of shape (n_a, m)
dWax -- Gradient w.r.t the input's weight matrix, numpy-array of shape (n_a, n_x)
dWaa -- Gradient w.r.t the hidden state's weight matrix, numpy-arrayof shape (n_a, n_a)
dba -- Gradient w.r.t the bias, of shape (n_a, 1)
"""
### START CODE HERE ###
# Retrieve values from the first cache (t=1) of caches (≈2 lines)
(caches, x) = caches
(a1, a0, x1, parameters) = caches[0]
# Retrieve dimensions from da's and x1's shapes (≈2 lines)
n_a, m, T_x = da.shape
n_x, m = x1.shape
# initialize the gradients with the right sizes (≈6 lines)
dx = np.zeros((n_x,m,T_x))
dWax = np.zeros((n_a,n_x))
dWaa = np.zeros((n_a,n_a))
dba = np.zeros((n_a,1))
da0 = np.zeros((n_a,m))
da_prevt = np.zeros((n_a,m))
# Loop through all the time steps
for t in reversed(range(T_x)):
# Compute gradients at time step t.
# Remember to sum gradients from the output path (da) and the previous timesteps (da_prevt) (≈1 line)
gradients = rnn_cell_backward(da[:,:,t] +da_prevt, caches[t])
# Retrieve derivatives from gradients (≈ 1 line)
dxt, da_prevt, dWaxt, dWaat, dbat = gradients["dxt"], gradients["da_prev"], gradients["dWax"], gradients["dWaa"], gradients["dba"]
# Increment global derivatives w.r.t parameters by adding their derivative at time-step t (≈4 lines)
dx[:, :, t] = dxt
dWax += dWaxt
dWaa += dWaat
dba += dbat
# Set da0 to the gradient of a which has been backpropagated through all time-steps (≈1 line)
da0 = da_prevt
### END CODE HERE ###
# Store the gradients in a python dictionary
gradients = {"dx": dx, "da0": da0, "dWax": dWax, "dWaa": dWaa,"dba": dba}
return gradients
np.random.seed(1)
x_tmp = np.random.randn(3,10,4)
a0_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wax'] = np.random.randn(5,3)
parameters_tmp['Waa'] = np.random.randn(5,5)
parameters_tmp['Wya'] = np.random.randn(2,5)
parameters_tmp['ba'] = np.random.randn(5,1)
parameters_tmp['by'] = np.random.randn(2,1)
a_tmp, y_tmp, caches_tmp = rnn_forward(x_tmp, a0_tmp, parameters_tmp)
da_tmp = np.random.randn(5, 10, 4)
gradients_tmp = rnn_backward(da_tmp, caches_tmp)
print("gradients["dx"][1][2] =", gradients_tmp["dx"][1][2])
print("gradients["dx"].shape =", gradients_tmp["dx"].shape)
print("gradients["da0"][2][3] =", gradients_tmp["da0"][2][3])
print("gradients["da0"].shape =", gradients_tmp["da0"].shape)
print("gradients["dWax"][3][1] =", gradients_tmp["dWax"][3][1])
print("gradients["dWax"].shape =", gradients_tmp["dWax"].shape)
print("gradients["dWaa"][1][2] =", gradients_tmp["dWaa"][1][2])
print("gradients["dWaa"].shape =", gradients_tmp["dWaa"].shape)
print("gradients["dba"][4] =", gradients_tmp["dba"][4])
print("gradients["dba"].shape =", gradients_tmp["dba"].shape)
gradients["dx"][1][2] = [-2.07101689 -0.59255627 0.02466855 0.01483317]
gradients["dx"].shape = (3, 10, 4)
gradients["da0"][2][3] = -0.314942375127
gradients["da0"].shape = (5, 10)
gradients["dWax"][3][1] = 11.2641044965
gradients["dWax"].shape = (5, 3)
gradients["dWaa"][1][2] = 2.30333312658
gradients["dWaa"].shape = (5, 5)
gradients["dba"][4] = [-0.74747722]
gradients["dba"].shape = (5, 1)
Expected Output:
| **gradients["dx"][1][2]** = | [-2.07101689 -0.59255627 0.02466855 0.01483317] |
| **gradients["dx"].shape** = | (3, 10, 4) |
| **gradients["da0"][2][3]** = | -0.314942375127 |
| **gradients["da0"].shape** = | (5, 10) |
| **gradients["dWax"][3][1]** = | 11.2641044965 |
| **gradients["dWax"].shape** = | (5, 3) |
| **gradients["dWaa"][1][2]** = | 2.30333312658 |
| **gradients["dWaa"].shape** = | (5, 5) |
| **gradients["dba"][4]** = | [-0.74747722] |
| **gradients["dba"].shape** = | (5, 1) |
3.2 - LSTM backward pass
3.2.1 One Step backward
The LSTM backward pass is slightly more complicated than the forward pass.
style="500;height:400px;">
The equations for the LSTM backward pass are provided below. (If you enjoy calculus exercises feel free to try deriving these from scratch yourself.)
3.2.2 gate derivatives
Note the location of the gate derivatives ((gamma)..) between the dense layer and the activation function (see graphic above). This is convenient for computing parameter derivatives in the next step.
egin{align}
dgamma_o{langle t
angle} &= da_{next}* anh(c_{next}) * Gamma_o{langle t
angle}left(1-Gamma_o{langle t
angle}
ight) ag{7} [8pt]
dpwidetilde{c}{langle t
angle} &= left(dc_{next}Gamma_u{langle t
angle}+ Gamma_o{langle t
angle}* (1- anh2(c_{next})) * Gamma_u{langle t
angle} * da_{next}
ight) * left(1-left(widetilde c{langle t
angle}
ight)2
ight) ag{8} [8pt]
dgamma_u{langle t
angle} &= left(dc_{next}widetilde{c}{langle t
angle} + Gamma_o{langle t
angle} (1- anh2(c_{next})) * widetilde{c}{langle t
angle} * da_{next}
ight)Gamma_u{langle t
angle}left(1-Gamma_u{langle t
angle}
ight) ag{9} [8pt]
dgamma_f{langle t
angle} &= left(dc_{next}* c_{prev} + Gamma_o{langle t
angle} * (1- anh2(c_{next})) * c_{prev} * da_{next}
ight)Gamma_f{langle t
angle}left(1-Gamma_f{langle t
angle}
ight) ag{10}
end{align}
3.2.3 parameter derivatives
( dW_f = dgamma_f^{langle t
angle} egin{bmatrix} a_{prev} \ x_tend{bmatrix}^T ag{11} )
( dW_u = dgamma_u^{langle t
angle} egin{bmatrix} a_{prev} \ x_tend{bmatrix}^T ag{12} )
( dW_c = dpwidetilde c^{langle t
angle} egin{bmatrix} a_{prev} \ x_tend{bmatrix}^T ag{13} )
( dW_o = dgamma_o^{langle t
angle} egin{bmatrix} a_{prev} \ x_tend{bmatrix}^T ag{14})
To calculate (db_f, db_u, db_c, db_o) you just need to sum across all 'm' examples (axis= 1) on (dgamma_f^{langle t
angle}, dgamma_u^{langle t
angle}, dpwidetilde c^{langle t
angle}, dgamma_o^{langle t
angle}) respectively. Note that you should have the keepdims = True option.
(displaystyle db_f = sum_{batch}dgamma_f^{langle t
angle} ag{15})
(displaystyle db_u = sum_{batch}dgamma_u^{langle t
angle} ag{16})
(displaystyle db_c = sum_{batch}dgamma_c^{langle t
angle} ag{17})
(displaystyle db_o = sum_{batch}dgamma_o^{langle t
angle} ag{18})
Finally, you will compute the derivative with respect to the previous hidden state, previous memory state, and input.
( da_{prev} = W_f^T dgamma_f^{langle t angle} + W_u^T dgamma_u^{langle t angle}+ W_c^T dpwidetilde c^{langle t angle} + W_o^T dgamma_o^{langle t angle} ag{19})
Here, to account for concatenation, the weights for equations 19 are the first n_a, (i.e. (W_f = W_f[:,:n_a]) etc...)
( dc_{prev} = dc_{next}*Gamma_f^{langle t angle} + Gamma_o^{langle t angle} * (1- anh^2(c_{next}))*Gamma_f^{langle t angle}*da_{next} ag{20})
( dx^{langle t angle} = W_f^T dgamma_f^{langle t angle} + W_u^T dgamma_u^{langle t angle}+ W_c^T dpwidetilde c^{langle t angle} + W_o^T dgamma_o^{langle t angle} ag{21} )
where the weights for equation 21 are from n_a to the end, (i.e. (W_f = W_f[:,n_a:]) etc...)
Exercise: Implement lstm_cell_backward by implementing equations (7-21) below.
Note: In the code:
(dgamma_o^{langle t
angle}) is represented by dot,
(dpwidetilde{c}^{langle t
angle}) is represented by dcct,
(dgamma_u^{langle t
angle}) is represented by dit,
(dgamma_f^{langle t
angle}) is represented by dft
def lstm_cell_backward(da_next, dc_next, cache):
"""
Implement the backward pass for the LSTM-cell (single time-step).
Arguments:
da_next -- Gradients of next hidden state, of shape (n_a, m)
dc_next -- Gradients of next cell state, of shape (n_a, m)
cache -- cache storing information from the forward pass
Returns:
gradients -- python dictionary containing:
dxt -- Gradient of input data at time-step t, of shape (n_x, m)
da_prev -- Gradient w.r.t. the previous hidden state, numpy array of shape (n_a, m)
dc_prev -- Gradient w.r.t. the previous memory state, of shape (n_a, m, T_x)
dWf -- Gradient w.r.t. the weight matrix of the forget gate, numpy array of shape (n_a, n_a + n_x)
dWi -- Gradient w.r.t. the weight matrix of the update gate, numpy array of shape (n_a, n_a + n_x)
dWc -- Gradient w.r.t. the weight matrix of the memory gate, numpy array of shape (n_a, n_a + n_x)
dWo -- Gradient w.r.t. the weight matrix of the output gate, numpy array of shape (n_a, n_a + n_x)
dbf -- Gradient w.r.t. biases of the forget gate, of shape (n_a, 1)
dbi -- Gradient w.r.t. biases of the update gate, of shape (n_a, 1)
dbc -- Gradient w.r.t. biases of the memory gate, of shape (n_a, 1)
dbo -- Gradient w.r.t. biases of the output gate, of shape (n_a, 1)
"""
# Retrieve information from "cache"
(a_next, c_next, a_prev, c_prev, ft, it, cct, ot, xt, parameters) = cache
### START CODE HERE ###
# Retrieve dimensions from xt's and a_next's shape (≈2 lines)
n_x, m = xt.shape
n_a, m = a_next.shape
# Compute gates related derivatives, you can find their values can be found by looking carefully at equations (7) to (10) (≈4 lines)
dot = da_next*np.tanh(c_next)*ot*(1-ot)
dcct = (dc_next*it+ot*(1-np.square(np.tanh(c_next)))*it*da_next)*(1-np.square(cct))
dit = (dc_next*cct+ot*(1-np.square(np.tanh(c_next)))*cct*da_next)*it*(1-it)
dft = (dc_next*c_prev+ot*(1-np.square(np.tanh(c_next)))*c_prev*da_next)*ft*(1-ft)
# Compute parameters related derivatives. Use equations (11)-(18) (≈8 lines)
dWf = np.dot(dft,np.concatenate((a_prev, xt), axis=0).T)
dWi = np.dot(dit,np.concatenate((a_prev, xt), axis=0).T)
dWc = np.dot(dcct,np.concatenate((a_prev, xt), axis=0).T)
dWo = np.dot(dot,np.concatenate((a_prev, xt), axis=0).T)
dbf = np.sum(dft,axis=1,keepdims=True)
dbi = np.sum(dit,axis=1,keepdims=True)
dbc = np.sum(dcct,axis=1,keepdims=True)
dbo = np.sum(dot,axis=1,keepdims=True)
# Compute derivatives w.r.t previous hidden state, previous memory state and input. Use equations (19)-(21). (≈3 lines)
da_prev = np.dot(parameters['Wf'][:,:n_a].T,dft)+np.dot(parameters['Wi'][:,:n_a].T,dit)+np.dot(parameters['Wc'][:,:n_a].T,dcct)+np.dot(parameters['Wo'][:,:n_a].T,dot)
dc_prev = dc_next*ft+ot*(1-np.square(np.tanh(c_next)))*ft*da_next
dxt = np.dot(parameters['Wf'][:,n_a:].T,dft)+np.dot(parameters['Wi'][:,n_a:].T,dit)+np.dot(parameters['Wc'][:,n_a:].T,dcct)+np.dot(parameters['Wo'][:,n_a:].T,dot)
### END CODE HERE ###
# Save gradients in dictionary
gradients = {"dxt": dxt, "da_prev": da_prev, "dc_prev": dc_prev, "dWf": dWf,"dbf": dbf, "dWi": dWi,"dbi": dbi,
"dWc": dWc,"dbc": dbc, "dWo": dWo,"dbo": dbo}
return gradients
np.random.seed(1)
xt_tmp = np.random.randn(3,10)
a_prev_tmp = np.random.randn(5,10)
c_prev_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wf'] = np.random.randn(5, 5+3)
parameters_tmp['bf'] = np.random.randn(5,1)
parameters_tmp['Wi'] = np.random.randn(5, 5+3)
parameters_tmp['bi'] = np.random.randn(5,1)
parameters_tmp['Wo'] = np.random.randn(5, 5+3)
parameters_tmp['bo'] = np.random.randn(5,1)
parameters_tmp['Wc'] = np.random.randn(5, 5+3)
parameters_tmp['bc'] = np.random.randn(5,1)
parameters_tmp['Wy'] = np.random.randn(2,5)
parameters_tmp['by'] = np.random.randn(2,1)
a_next_tmp, c_next_tmp, yt_tmp, cache_tmp = lstm_cell_forward(xt_tmp, a_prev_tmp, c_prev_tmp, parameters_tmp)
da_next_tmp = np.random.randn(5,10)
dc_next_tmp = np.random.randn(5,10)
gradients_tmp = lstm_cell_backward(da_next_tmp, dc_next_tmp, cache_tmp)
print("gradients["dxt"][1][2] =", gradients_tmp["dxt"][1][2])
print("gradients["dxt"].shape =", gradients_tmp["dxt"].shape)
print("gradients["da_prev"][2][3] =", gradients_tmp["da_prev"][2][3])
print("gradients["da_prev"].shape =", gradients_tmp["da_prev"].shape)
print("gradients["dc_prev"][2][3] =", gradients_tmp["dc_prev"][2][3])
print("gradients["dc_prev"].shape =", gradients_tmp["dc_prev"].shape)
print("gradients["dWf"][3][1] =", gradients_tmp["dWf"][3][1])
print("gradients["dWf"].shape =", gradients_tmp["dWf"].shape)
print("gradients["dWi"][1][2] =", gradients_tmp["dWi"][1][2])
print("gradients["dWi"].shape =", gradients_tmp["dWi"].shape)
print("gradients["dWc"][3][1] =", gradients_tmp["dWc"][3][1])
print("gradients["dWc"].shape =", gradients_tmp["dWc"].shape)
print("gradients["dWo"][1][2] =", gradients_tmp["dWo"][1][2])
print("gradients["dWo"].shape =", gradients_tmp["dWo"].shape)
print("gradients["dbf"][4] =", gradients_tmp["dbf"][4])
print("gradients["dbf"].shape =", gradients_tmp["dbf"].shape)
print("gradients["dbi"][4] =", gradients_tmp["dbi"][4])
print("gradients["dbi"].shape =", gradients_tmp["dbi"].shape)
print("gradients["dbc"][4] =", gradients_tmp["dbc"][4])
print("gradients["dbc"].shape =", gradients_tmp["dbc"].shape)
print("gradients["dbo"][4] =", gradients_tmp["dbo"][4])
print("gradients["dbo"].shape =", gradients_tmp["dbo"].shape)
gradients["dxt"][1][2] = 3.23055911511
gradients["dxt"].shape = (3, 10)
gradients["da_prev"][2][3] = -0.0639621419711
gradients["da_prev"].shape = (5, 10)
gradients["dc_prev"][2][3] = 0.797522038797
gradients["dc_prev"].shape = (5, 10)
gradients["dWf"][3][1] = -0.147954838164
gradients["dWf"].shape = (5, 8)
gradients["dWi"][1][2] = 1.05749805523
gradients["dWi"].shape = (5, 8)
gradients["dWc"][3][1] = 2.30456216369
gradients["dWc"].shape = (5, 8)
gradients["dWo"][1][2] = 0.331311595289
gradients["dWo"].shape = (5, 8)
gradients["dbf"][4] = [ 0.18864637]
gradients["dbf"].shape = (5, 1)
gradients["dbi"][4] = [-0.40142491]
gradients["dbi"].shape = (5, 1)
gradients["dbc"][4] = [ 0.25587763]
gradients["dbc"].shape = (5, 1)
gradients["dbo"][4] = [ 0.13893342]
gradients["dbo"].shape = (5, 1)
Expected Output:
| **gradients["dxt"][1][2]** = | 3.23055911511 |
| **gradients["dxt"].shape** = | (3, 10) |
| **gradients["da_prev"][2][3]** = | -0.0639621419711 |
| **gradients["da_prev"].shape** = | (5, 10) |
| **gradients["dc_prev"][2][3]** = | 0.797522038797 |
| **gradients["dc_prev"].shape** = | (5, 10) |
| **gradients["dWf"][3][1]** = | -0.147954838164 |
| **gradients["dWf"].shape** = | (5, 8) |
| **gradients["dWi"][1][2]** = | 1.05749805523 |
| **gradients["dWi"].shape** = | (5, 8) |
| **gradients["dWc"][3][1]** = | 2.30456216369 |
| **gradients["dWc"].shape** = | (5, 8) |
| **gradients["dWo"][1][2]** = | 0.331311595289 |
| **gradients["dWo"].shape** = | (5, 8) |
| **gradients["dbf"][4]** = | [ 0.18864637] |
| **gradients["dbf"].shape** = | (5, 1) |
| **gradients["dbi"][4]** = | [-0.40142491] |
| **gradients["dbi"].shape** = | (5, 1) |
| **gradients["dbc"][4]** = | [ 0.25587763] |
| **gradients["dbc"].shape** = | (5, 1) |
| **gradients["dbo"][4]** = | [ 0.13893342] |
| **gradients["dbo"].shape** = | (5, 1) |
3.3 Backward pass through the LSTM RNN
This part is very similar to the rnn_backward function you implemented above. You will first create variables of the same dimension as your return variables. You will then iterate over all the time steps starting from the end and call the one step function you implemented for LSTM at each iteration. You will then update the parameters by summing them individually. Finally return a dictionary with the new gradients.
Instructions: Implement the lstm_backward function. Create a for loop starting from (T_x) and going backward. For each step call lstm_cell_backward and update the your old gradients by adding the new gradients to them. Note that dxt is not updated but is stored.
def lstm_backward(da, caches):
"""
Implement the backward pass for the RNN with LSTM-cell (over a whole sequence).
Arguments:
da -- Gradients w.r.t the hidden states, numpy-array of shape (n_a, m, T_x)
caches -- cache storing information from the forward pass (lstm_forward)
Returns:
gradients -- python dictionary containing:
dx -- Gradient of inputs, of shape (n_x, m, T_x)
da0 -- Gradient w.r.t. the previous hidden state, numpy array of shape (n_a, m)
dWf -- Gradient w.r.t. the weight matrix of the forget gate, numpy array of shape (n_a, n_a + n_x)
dWi -- Gradient w.r.t. the weight matrix of the update gate, numpy array of shape (n_a, n_a + n_x)
dWc -- Gradient w.r.t. the weight matrix of the memory gate, numpy array of shape (n_a, n_a + n_x)
dWo -- Gradient w.r.t. the weight matrix of the save gate, numpy array of shape (n_a, n_a + n_x)
dbf -- Gradient w.r.t. biases of the forget gate, of shape (n_a, 1)
dbi -- Gradient w.r.t. biases of the update gate, of shape (n_a, 1)
dbc -- Gradient w.r.t. biases of the memory gate, of shape (n_a, 1)
dbo -- Gradient w.r.t. biases of the save gate, of shape (n_a, 1)
"""
# Retrieve values from the first cache (t=1) of caches.
(caches, x) = caches
(a1, c1, a0, c0, f1, i1, cc1, o1, x1, parameters) = caches[0]
### START CODE HERE ###
# Retrieve dimensions from da's and x1's shapes (≈2 lines)
n_a, m, T_x = da.shape
n_x, m = x1.shape
# initialize the gradients with the right sizes (≈12 lines)
dx = np.zeros((n_x, m, T_x))
da0 = np.zeros((n_a, m))
da_prevt = np.zeros((n_a, m))
dc_prevt = np.zeros((n_a, m))
dWf = np.zeros((n_a, n_a + n_x))
dWi = np.zeros((n_a, n_a + n_x))
dWc = np.zeros((n_a, n_a + n_x))
dWo = np.zeros((n_a, n_a + n_x))
dbf = np.zeros((n_a, 1))
dbi = np.zeros((n_a, 1))
dbc = np.zeros((n_a, 1))
# loop back over the whole sequence
for t in reversed(range(T_x)):
# Compute all gradients using lstm_cell_backward
gradients = lstm_cell_backward(da[:,:,t]+da_prevt,dc_prevt,caches[t])
# Store or add the gradient to the parameters' previous step's gradient
da_prevt = gradients["da_prev"]
dc_prevt = gradients["dc_prev"]
dx[:,:,t] = gradients["dxt"]
dWf = dWf+gradients["dWf"]
dWi = dWi+gradients["dWi"]
dWc = dWc+gradients["dWc"]
dWo = dWo+gradients["dWo"]
dbf = dbf+gradients["dbf"]
dbi = dbi+gradients["dbi"]
dbc = dbc+gradients["dbc"]
dbo = dbo+gradients["dbo"]
# Set the first activation's gradient to the backpropagated gradient da_prev.
da0 = gradients["da_prev"]
### END CODE HERE ###
# Store the gradients in a python dictionary
gradients = {"dx": dx, "da0": da0, "dWf": dWf,"dbf": dbf, "dWi": dWi,"dbi": dbi,
"dWc": dWc,"dbc": dbc, "dWo": dWo,"dbo": dbo}
return gradients
np.random.seed(1)
x_tmp = np.random.randn(3,10,7)
a0_tmp = np.random.randn(5,10)
parameters_tmp = {}
parameters_tmp['Wf'] = np.random.randn(5, 5+3)
parameters_tmp['bf'] = np.random.randn(5,1)
parameters_tmp['Wi'] = np.random.randn(5, 5+3)
parameters_tmp['bi'] = np.random.randn(5,1)
parameters_tmp['Wo'] = np.random.randn(5, 5+3)
parameters_tmp['bo'] = np.random.randn(5,1)
parameters_tmp['Wc'] = np.random.randn(5, 5+3)
parameters_tmp['bc'] = np.random.randn(5,1)
parameters_tmp['Wy'] = np.zeros((2,5)) # unused, but needed for lstm_forward
parameters_tmp['by'] = np.zeros((2,1)) # unused, but needed for lstm_forward
a_tmp, y_tmp, c_tmp, caches_tmp = lstm_forward(x_tmp, a0_tmp, parameters_tmp)
da_tmp = np.random.randn(5, 10, 4)
gradients_tmp = lstm_backward(da_tmp, caches_tmp)
print("gradients["dx"][1][2] =", gradients_tmp["dx"][1][2])
print("gradients["dx"].shape =", gradients_tmp["dx"].shape)
print("gradients["da0"][2][3] =", gradients_tmp["da0"][2][3])
print("gradients["da0"].shape =", gradients_tmp["da0"].shape)
print("gradients["dWf"][3][1] =", gradients_tmp["dWf"][3][1])
print("gradients["dWf"].shape =", gradients_tmp["dWf"].shape)
print("gradients["dWi"][1][2] =", gradients_tmp["dWi"][1][2])
print("gradients["dWi"].shape =", gradients_tmp["dWi"].shape)
print("gradients["dWc"][3][1] =", gradients_tmp["dWc"][3][1])
print("gradients["dWc"].shape =", gradients_tmp["dWc"].shape)
print("gradients["dWo"][1][2] =", gradients_tmp["dWo"][1][2])
print("gradients["dWo"].shape =", gradients_tmp["dWo"].shape)
print("gradients["dbf"][4] =", gradients_tmp["dbf"][4])
print("gradients["dbf"].shape =", gradients_tmp["dbf"].shape)
print("gradients["dbi"][4] =", gradients_tmp["dbi"][4])
print("gradients["dbi"].shape =", gradients_tmp["dbi"].shape)
print("gradients["dbc"][4] =", gradients_tmp["dbc"][4])
print("gradients["dbc"].shape =", gradients_tmp["dbc"].shape)
print("gradients["dbo"][4] =", gradients_tmp["dbo"][4])
print("gradients["dbo"].shape =", gradients_tmp["dbo"].shape)
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-41-0b7e3890788a> in <module>()
18
19 da_tmp = np.random.randn(5, 10, 4)
---> 20 gradients_tmp = lstm_backward(da_tmp, caches_tmp)
21
22 print("gradients["dx"][1][2] =", gradients_tmp["dx"][1][2])
<ipython-input-40-b81430045616> in lstm_backward(da, caches)
67 # Store the gradients in a python dictionary
68 gradients = {"dx": dx, "da0": da0, "dWf": dWf,"dbf": dbf, "dWi": dWi,"dbi": dbi,
---> 69 "dWc": dWc,"dbc": dbc, "dWo": dWo,"dbo": dbo}
70
71 return gradients
NameError: name 'dbo' is not defined
Expected Output:
| **gradients["dx"][1][2]** = | [0.00218254 0.28205375 -0.48292508 -0.43281115] |
| **gradients["dx"].shape** = | (3, 10, 4) |
| **gradients["da0"][2][3]** = | 0.312770310257 |
| **gradients["da0"].shape** = | (5, 10) |
| **gradients["dWf"][3][1]** = | -0.0809802310938 |
| **gradients["dWf"].shape** = | (5, 8) |
| **gradients["dWi"][1][2]** = | 0.40512433093 |
| **gradients["dWi"].shape** = | (5, 8) |
| **gradients["dWc"][3][1]** = | -0.0793746735512 |
| **gradients["dWc"].shape** = | (5, 8) |
| **gradients["dWo"][1][2]** = | 0.038948775763 |
| **gradients["dWo"].shape** = | (5, 8) |
| **gradients["dbf"][4]** = | [-0.15745657] |
| **gradients["dbf"].shape** = | (5, 1) |
| **gradients["dbi"][4]** = | [-0.50848333] |
| **gradients["dbi"].shape** = | (5, 1) |
| **gradients["dbc"][4]** = | [-0.42510818] |
| **gradients["dbc"].shape** = | (5, 1) |
| **gradients["dbo"][4]** = | [ -0.17958196] |
| **gradients["dbo"].shape** = | (5, 1) |
Congratulations !
Congratulations on completing this assignment. You now understand how recurrent neural networks work!
Let's go on to the next exercise, where you'll use an RNN to build a character-level language model.