asp mvc 中重写JsonResult，解决Json返回值序列化问题

1、先新建一个 JsonConvertResult:JsonResult，继承自JsonResult;

public class JsonConvertResult : JsonResult
    {
        /// <summary>
        /// 格式化字符串
        /// </summary>
        public string FormateStr
        {
            get;
            set;
        }

        /// <summary>
        /// 重写执行视图
        /// </summary>
        /// <param name="context">上下文</param>
        public override void ExecuteResult(ControllerContext context)
        {
            if (context == null)
            {
                throw new ArgumentNullException("context");
            }
            HttpResponseBase response = context.HttpContext.Response;

            if (!string.IsNullOrEmpty(this.ContentType))
            {
                response.ContentType = this.ContentType;
            }
            else
            {
                response.ContentType = "application/json";
                //response.setContentType("text/html;charset=utf-8");
            }

            if (this.ContentEncoding != null)
            {
                response.ContentEncoding = this.ContentEncoding;
            }

            if (this.Data != null)
            {

                JavaScriptSerializer jss = new JavaScriptSerializer();
                string jsonString = jss.Serialize(Data);
                string p = @"\/Date((d+))\/";
                MatchEvaluator matchEvaluator = new MatchEvaluator(this.ConvertJsonDateToDateString);
                Regex reg = new Regex(p);

                jsonString = reg.Replace(jsonString, matchEvaluator);
                JsonSerializerSettings set = new JsonSerializerSettings();
                set.NullValueHandling = NullValueHandling.Ignore;

                //string jsonString = ExtJsonManager.SerializeObject(Data);
                response.Write(jsonString);
            }
        }

        /// <summary>  
        /// 将Json序列化的时间由/Date(1294499956278)转为字符串 .
        /// </summary>  
        /// <param name="m">正则匹配</param>
        /// <returns>格式化后的字符串</returns>
        private string ConvertJsonDateToDateString(Match m)
        {
            string result = string.Empty;
            DateTime dt = new DateTime(1970, 1, 1);
            dt = dt.AddMilliseconds(long.Parse(m.Groups[1].Value));
            dt = dt.ToLocalTime();
            result = dt.ToString(FormateStr);
            return result;
        }
    }

2、BaseController中重写Json返回值方法就可以了。

  protected override JsonResult Json(object data, string contentType, System.Text.Encoding contentEncoding, JsonRequestBehavior behavior)
        {
            return new JsonConvertResult
            {
                Data = data,
                ContentType = contentType,
                ContentEncoding = contentEncoding,
                JsonRequestBehavior = behavior,
                FormateStr = "yyyy-MM-dd HH:mm:ss"
            };
        }