Machine
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1586 Accepted Submission(s): 708
Problem Description
There is a machine with m(2≤m≤30) coloured
bulbs and a button.When the button is pushed, the rightmost bulb changes.
For any changed bulb,
if it is red now it will be green;
if it is green now it will be blue;
if it is blue now it will be red and the bulb that on the left(if it exists) will change too.
Initally all the bulbs are red. What colour are the bulbs after the button be
pushedn(1≤n<263) times?
Input
For any changed bulb,
if it is red now it will be green;
if it is green now it will be blue;
if it is blue now it will be red and the bulb that on the left(if it exists) will change too.
Initally all the bulbs are red. What colour are the bulbs after the button be
pushed
There are multiple test cases. The first line of input contains an integer T(1≤T≤15) indicating
the number of test cases. For each test case:
The only line contains two integersm(2≤m≤30) and n(1≤n<263) .
Output
The only line contains two integers
For each test case, output the colour of m bulbs from left to right.
R indicates red. G indicates green. B indicates blue.
Sample Input
R indicates red. G indicates green. B indicates blue.
2 3 1 2 3
RRG GR
问题链接:HDU5670 Machine。
题意简述:参见上文。
问题分析:这是一个进制转换问题。程序说明:(略)
题记:(略)
AC的C语言程序如下:
/* HDU5670 Machine */ #include <stdio.h> #include <string.h> #define BASE 3 #define N 30 char rgb[] = "RGB"; int color[N]; int main(void) { int t, m, len, i; long long n; scanf("%d", &t); while(t--) { memset(color, 0, sizeof(color)); scanf("%d%lld", &m, &n); len = m; while (n > 0 && m > 0) { color[--m] = n % BASE; n /= BASE; } for (i=0; i<len; i++) putchar(rgb[color[i]]); putchar(' '); } return 0; }