Just A Triangle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2862 Accepted Submission(s): 2028
Problem Description
This is an easy problem, just for you to warm up.
Give you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
Input
Give you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
The first line contains an integer t means the number of test cases.
The each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
Output
The each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
For each case, output the answer in one line.
Sample Input
4 3 4 5 2 2 3 1 4 4 4 6 3
good perfect perfect just a triangle
问题链接：HDU3188 Just A Triangle。
问题简述：参见上文。
问题分析：（略）
程序说明：（略）题记：（略）
AC的C++语言程序如下：
/* HDU3188 Just A Triangle */
#include <iostream>
using namespace std;
int main()
{
int t, a, b, c;
cin >> t;
while(t--) {
cin >> a >> b >> c;
if(a == b || b == c || a == c)
cout << "perfect" << endl;
else if(a * a + b * b == c * c || b * b + c * c == a * a || a * a + c * c == b * b)
cout << "good" << endl;
else
cout << "just a triangle" << endl;
}
return 0;
}