本文主要介绍后台接收处理
1.在使用控制器接收
1: [HttpPost] 2: public IActionResult UploadFiles(IList<IFormFile> files) 3: { 4: long size = 0; 5: foreach(var file in files) 6: { 7: var filename = ContentDispositionHeaderValue 8: .Parse(file.ContentDisposition) 9: .FileName 10: .Trim('"'); 11: filename = hostingEnv.WebRootPath + $@"{fileName}"; 12: size += file.Length; 13: using (FileStream fs = System.IO.File.Create(filename)) 14: { 15: file.CopyTo(fs); 16: fs.Flush(); 17: } 18: }
2.使用HttpRequest接收
方式1:
1: [HttpPost] 2: public IActionResult UploadFilesAjax() 3: { 4: long size = 0; 5: var files = Request.Form.Files; 6: foreach (var file in files) 7: { 8: var filename = ContentDispositionHeaderValue 9: .Parse(file.ContentDisposition) 10: .FileName 11: .Trim('"'); 12: filename = hostingEnv.WebRootPath + $@"{filename}"; 13: size += file.Length; 14: using (FileStream fs = System.IO.File.Create(filename)) 15: { 16: file.CopyTo(fs); 17: fs.Flush(); 18: } 19: } 20: string message = $"{files.Count} file(s) / 21: {size} bytes uploaded successfully!"; 22: return Json(message); 23: }
方式2:
//接收文件 var files = req.Form.Files; if (files.Count <= 0) throw new Exception("获取上传文件失败"); IFormFile _file = files[0]; string backInfo = req.Form["backinfo"]; if (string.IsNullOrEmpty(backInfo)) throw new Exception("获取文件信息失败"); UploadMsg upMsg = backInfo.JsonDeserializer<UploadMsg>(); this.file = new UploadInfo(upMsg); //获取文件数据 Stream stream = _file.OpenReadStream(); try { byte[] dataOne = new byte[stream.Length]; stream.Read(dataOne, 0, dataOne.Length); AppendFile(dataOne); } finally { stream.Close(); }
支持.Net Core的上传控件:https://github.com/tianma3798/Uploader
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