• lambda表达式使用解析


    1、Predicate/Consumer/Function/Supplier介绍

    Predicate boolean test(T t);
    Consumer accpet(T t);
    Function<T, R> R apply(T t);
    Supplier<T> T get();

    以Predicate为例,引申出很多类似的Predicate,如IntPredicate、DoublePredicate、BiPredicate、LongPredicate。但是他们的用法都是差不多的。比较类似。

    2、举例子:

    package com.cy.java8;
    
    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.List;
    import java.util.function.*;
    
    public class LambdaUsage {
    
        private static List<Apple> filter(List<Apple> source, Predicate<Apple> predicate){
            List<Apple> result = new ArrayList<>();
            for(Apple a : source){
                if(predicate.test(a)){
                    result.add(a);
                }
            }
            return result;
        }
    
        //根据一个long类型的参数过滤
        private static List<Apple> filterByWeight(List<Apple> source, LongPredicate predicate){
            List<Apple> result = new ArrayList<>();
            for(Apple a : source){
                if(predicate.test(a.getWeight())){
                    result.add(a);
                }
            }
            return result;
        }
    
        //根据两个参数过滤
        private static List<Apple> filterByColorWeight(List<Apple> source, BiPredicate<String, Long> bipredicate){
            List<Apple> result = new ArrayList<>();
            for(Apple a : source){
                if(bipredicate.test(a.getColor(), a.getWeight())){
                    result.add(a);
                }
            }
            return result;
        }
    
        private static void simpleTestConsumer(List<Apple> source, Consumer<Apple> consumer){
            for(Apple a : source){
                consumer.accept(a);
            }
        }
    
        private static String testFunction(Apple apple, Function<Apple, String> fun){
            return fun.apply(apple);
        }
    
        public static void main(String[] args) {
            List<Apple> list = Arrays.asList(new Apple("green", 120), new Apple("red", 150));
            List<Apple> greenList = filter(list, apple -> apple.getColor().equals("green"));
            System.out.println(greenList);
    
            System.out.println("-----------------------------");
            List<Apple> weightList = filterByWeight(list, weight -> weight>=150);
            System.out.println(weightList);
    
            System.out.println("-----------------------------");
            List<Apple> result = filterByColorWeight(list, (color, weight) -> color.equals("red") && weight > 100);
            System.out.println(result);
    
            System.out.println("-----------------------------");
            simpleTestConsumer(list, apple -> System.out.println("print apple's string method: " +apple));
    
            System.out.println("-----------------------------");
            String color = testFunction(new Apple("yellow", 10), apple -> apple.getColor());
            System.out.println(color);
    
            System.out.println("-----------------------------");
            Supplier<String> supplier = String::new;
            System.out.println(supplier.get().getClass());
        }
    
    }

    打印结果:

    [Apple(color=green, weight=120)]
    -----------------------------
    [Apple(color=red, weight=150)]
    -----------------------------
    [Apple(color=red, weight=150)]
    -----------------------------
    print apple's string method: Apple(color=green, weight=120)
    print apple's string method: Apple(color=red, weight=150)
    -----------------------------
    yellow
    -----------------------------
    class java.lang.String
    

    3、方法推导解析      

    什么情况下允许方法推导的方式来写呢?
    1.可以通过一个类的静态方法,比如Integer::parseInt
    2.可以通过一个类的成员方法。
    3.可以通过一个类的实例的方法。
    4.可以通过构造函数的推导。

    举例子:

    package com.cy.java8;
    
    import lombok.Data;
    
    @Data
    public class ComplexApple {
        private String color;
        private long weight;
        private String name;
    
        public ComplexApple(String color, long weight, String name) {
            this.color = color;
            this.weight = weight;
            this.name = name;
        }
    }
    View Code
    package com.cy.java8;
    
    @FunctionalInterface
    public interface ThreeParamFuntion<T, U, K, R> {
    
        R apply(T t, U u, K k);
    }
    View Code
    package com.cy.java8;
    
    import java.util.Arrays;
    import java.util.Comparator;
    import java.util.List;
    import java.util.function.BiFunction;
    import java.util.function.Consumer;
    import java.util.function.Function;
    import java.util.function.Supplier;
    import java.util.stream.Stream;
    
    public class MethodReference {
    
        public static void main(String[] args) {
            /*Consumer<String> consumer = s -> System.out.println(s);
            useConsumer(consumer,"hello alex");*/
    
            useConsumer(s -> System.out.println(s),"hello alex");
            useConsumer(System.out::println, "hello today");
    
            List<Apple> list = Arrays.asList(new Apple("green", 120), new Apple("abc", 100), new Apple("red", 150));
            System.out.println(list);
            list.sort((a1, a2) -> a1.getColor().compareTo(a2.getColor()));
            System.out.println(list);
            
            //比如循环输出apple信息
            list.stream().forEach(apple -> System.out.println(apple));
            
            //可以改成成如下
            System.out.println("-----------------------------------------");
            list.stream().forEach(System.out::println);
            System.out.println("-----------------------------------------");
    
            //方法推导,通过一个类的静态方法
            Function<String, Integer> funtion = Integer::parseInt;
            int result = funtion.apply("123");
            System.out.println(result);
    
            //方法推导,通过一个类的成员方法
            BiFunction<String, Integer, Character> f1 = String::charAt;
            System.out.println(f1.apply("index", 0));
    
            //方法推导,通过一个类的实例的方法
            String s = new String("index");
            Function<Integer, Character> f2 = s::charAt;
            System.out.println(f2.apply(1));
    
            //通过构造函数的推导
            Supplier<String> s1 = String::new;
            System.out.println(s1.get().getClass().getSimpleName());
    
            BiFunction<String, Long, Apple> biFunction = Apple::new;
            System.out.println(biFunction.apply("pink", 2L));
    
            //三个参数的构造方法,ComplexApple::new,需要自己定义FunctionalInterface
            ThreeParamFuntion<String, Long, String, ComplexApple> threeParamFuntion = ComplexApple::new;
            System.out.println(threeParamFuntion.apply("black", 1L, "blackApple"));
    
            //再次看下上面list的排序的另一种方法
            List<Apple> list2 = Arrays.asList(new Apple("green", 120), new Apple("abc", 100), new Apple("red", 150));
            list2.sort(Comparator.comparing(Apple::getColor));
            System.out.println(list2);
        }
    
        private static <T> void useConsumer(Consumer<T> consumer, T t){
            consumer.accept(t);
            consumer.accept(t);
        }
    
    }

    打印如下:

    hello alex
    hello alex
    hello today
    hello today
    [Apple(color=green, weight=120), Apple(color=abc, weight=100), Apple(color=red, weight=150)]
    [Apple(color=abc, weight=100), Apple(color=green, weight=120), Apple(color=red, weight=150)]
    Apple(color=abc, weight=100)
    Apple(color=green, weight=120)
    Apple(color=red, weight=150)
    -----------------------------------------
    Apple(color=abc, weight=100)
    Apple(color=green, weight=120)
    Apple(color=red, weight=150)
    -----------------------------------------
    123
    i
    n
    String
    Apple(color=pink, weight=2)
    ComplexApple(color=black, weight=1, name=blackApple)
    [Apple(color=abc, weight=100), Apple(color=green, weight=120), Apple(color=red, weight=150)]
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  • 原文地址:https://www.cnblogs.com/tenWood/p/11486624.html
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