使用C++的模板函数做展示输出
template <typename T>
inline void displayVector(vector<T>& vec){
for(T v : vec)cout << v;
cout << endl;
}
template <typename T, typename S>
inline void displayMap(map<T, S>& mp){
for(typename map<T, S>::iterator iter = mp.begin(); iter!=mp.end(); iter++)cout << iter->first << " " << iter->second << endl;
}
template <typename T, typename S>
inline void displayMapVector(map<T, vector<S>>& mp){
for(typename map<T, vector<S>>::iterator iter = mp.begin(); iter != mp.end(); iter++)cout << iter->first << " " << displayVector(iter->second);
}
报错后在map::iterator前面加个typename声明模板类型是类型名即可。
参考链接：
Error: need ‘typename’ before iterator [duplicate]
编译错误need 'typename' before *** because *** is a dependent scope 浅析