Lamda所有的Capture均是引用

【Lamda所有的Capture均是引用】

　　下面的程序，两个lambda 引用的实际上是同一个a、b。连int都能引用了，说明Lambda对所有类型都是以引用来处理。

int a = 0;
        int b = 1;
        Func<int> exe = ()=>{
            int tmp = a;
            a = b;
            b = tmp+b;
            return a;
        };
        Debug.Log("a1 = " + exe());
        Debug.Log("a2 = " + exe());
        Debug.Log("a3 = " + exe());
        Debug.Log("a4 = " + exe());
        Debug.Log("a5 = " + exe());

        Func<int> exe2 = ()=>{
            int tmp = a;
            a = b;
            b = tmp+b;
            return a;
        };
        Debug.Log("a1 = " + exe2());
        Debug.Log("a2 = " + exe2());
        Debug.Log("a3 = " + exe2());
        Debug.Log("a4 = " + exe2());
        Debug.Log("a5 = " + exe2());

　　结果为：