pytest中使用assertpy断言

Pytest中使用assertpy断言

在我调研assertpy的时候发现了这么一句话：
Of course, assertpy works best with a python test runner like pytest (our favorite) or Nose.
那么正好我们也是使用pytest+allure，但是我的断言都是：
assert 1 = 1
assert 'x' in 'xyz'
如果我想对某一段字符串做很多断言呢？

s = '1234567890'
assert '1' in s
assert '0' in s

这样就会写很多assert
如果我修改成用assertpy

from assertpy import assert_that
s='1234567890'
assert_that(s).contains('1','2','0')  # 表示 1 2  0 都在 s 中

如果报错的话，就是这样子：

assert_that(s).contains('1','2','0','s')
# 报错信息
AssertionError: Expected <1234567890> to contain items <'1', '2', '0', 's'>, but did not contain <s>

我从官网拷贝过来的很多断言方法：

字符串断言

assert_that('').is_not_none()
assert_that('').is_empty()
assert_that('').is_false()
assert_that('').is_type_of(str)
assert_that('').is_instance_of(str)

assert_that('foo').is_length(3)
assert_that('foo').is_not_empty()
assert_that('foo').is_true()
assert_that('foo').is_alpha()
assert_that('123').is_digit()
assert_that('foo').is_lower()
assert_that('FOO').is_upper()
assert_that('foo').is_iterable()
assert_that('foo').is_equal_to('foo')
assert_that('foo').is_not_equal_to('bar')
assert_that('foo').is_equal_to_ignoring_case('FOO')

assert_that(u'foo').is_unicode()  # on python 2
assert_that('foo').is_unicode()   # on python 3

assert_that('foo').contains('f')
assert_that('foo').contains('f','oo')
assert_that('foo').contains_ignoring_case('F','oO')
assert_that('foo').does_not_contain('x')
assert_that('foo').contains_only('f','o')
assert_that('foo').contains_sequence('o','o')

assert_that('foo').contains_duplicates()
assert_that('fox').does_not_contain_duplicates()

assert_that('foo').is_in('foo','bar','baz')
assert_that('foo').is_not_in('boo','bar','baz')
assert_that('foo').is_subset_of('abcdefghijklmnopqrstuvwxyz')

assert_that('foo').starts_with('f')
assert_that('foo').ends_with('oo')

assert_that('foo').matches(r'\w')
assert_that('123-456-7890').matches(r'\d{3}-\d{3}-\d{4}')
assert_that('foo').does_not_match(r'\d+')

正则匹配

# partial matches, these all pass
assert_that('foo').matches(r'\w')
assert_that('foo').matches(r'oo')
assert_that('foo').matches(r'\w{2}')

# match the entire string with an anchored regex pattern, passes
assert_that('foo').matches(r'^\w{3}$')

# fails
assert_that('foo').matches(r'^\w{2}$')