--有id,name,createDate的一张表testTable
--根据name分组,获取每组中createDate最大的那条记录(整条)查询出来
----------------------------------------------
创建一张表,语句如下:
- CREATE TABLE [dbo].[testTable]
- (
- [id] [int] NOT NULL IDENTITY(1, 1),
- [name] [nchar] (10) COLLATE Chinese_PRC_CI_AS NULL,
- [counts] [int] NULL,
- [createDate] [datetime] NULL
- )
- GO
- -- Constraints and Indexes
- ALTER TABLE [dbo].[testTable] ADD CONSTRAINT [PK_testTable] PRIMARY KEY CLUSTERED ([id])
- GO
插入测试数据:
- insert into testTable(id,name,counts,createDate) values(1,'A ',20,'01 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(2,'A ',10,'02 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(3,'B ',20,'03 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(4,'B ',40,'04 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(5,'B ',10,'05 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(6,'C ',20,'06 14 2011 10:52PM')
- insert into testTable(id,name,counts,createDate) values(7,'C ',40,'07 14 2011 10:52PM')
查询SQL语句:
- select * from (
- select id,name,counts,createDate,row_number() over(partition by name order by createDate desc) rn
- from testTable
- ) t where t.rn <=1
结果如下: