• poj2195&&hdu1533 最小费用流


    这题也可以用km做,我写的代码km比费用流快很多。

    最小费用流:

    #include<stdio.h>
    #include<string.h>
    #include<math.h>
    #include<queue>
    #include<stdlib.h>
    #define INF 1000000000
    using namespace std;
    const int maxn = 1100;
    struct Set
    {
        int x,y;
    }mnum[110*110],hnum[110*110];
    struct node
    {
        int to;
        int v;
        int flag;
        int cost;
        int next;
    }edge[maxn*maxn/2];
    char map[110][110];
    int n,m,cou1,cou2,index,head[maxn],s,t,pre[maxn],fpre[maxn],N,dis[maxn];
    int Get(int i,int j)
    {
        return abs(mnum[i].x-hnum[j].x)+abs(mnum[i].y-hnum[j].y);
    }
    void add(int x,int y,int v,int cost)
    {
        edge[index].to=y;
        edge[index].v=v;
        edge[index].cost=cost;
        edge[index].flag=index+1;
        edge[index].next=head[x];
        head[x]=index++;
        edge[index].to=x;
        edge[index].v=0;
        edge[index].cost=-cost;
        edge[index].flag=index-1;
        edge[index].next=head[y];
        head[y]=index++;
    }
    void makemap()
    {
        int i,j;
        cou1=cou2=0;
        for(i=0;i<n;i++)
        {
            for(j=0;j<m;j++)
            {
                if(map[i][j]=='m')
                {
                    mnum[++cou1].x=i;
                    mnum[cou1].y=j;
                }
                else if(map[i][j]=='H')
                {
                    hnum[++cou2].x=i;
                    hnum[cou2].y=j;
                }
            }
        }
        index=1;
        memset(head,-1,sizeof(head));
        N=cou1+cou2+1;
        s=0;
        t=cou1+cou2+1;
        for(i=1;i<=cou1;i++)
            add(s,i,1,0);
        for(i=1;i<=cou2;i++)
            add(i+cou1,t,1,0);
        for(i=1;i<=cou1;i++)
        {
            for(j=1;j<=cou2;j++)
            {
                add(i,j+cou1,1,Get(i,j));
            }
        }
    }
    bool spfa(int s,int t)
    {
        int vis[maxn];
        queue<int>q;
        memset(pre,-1,sizeof(pre));
        memset(vis,0,sizeof(vis));
        int i;
        for(i=0;i<=N;i++)
            dis[i]=INF;
        vis[s]=1;
        dis[s]=0;
        pre[s]=0;
        q.push(s);
        while(!q.empty())
        {
            int u=q.front();
            q.pop();
            vis[u]=0;
            for(i=head[u];i!=-1;i=edge[i].next)
            {
                if(edge[i].v&&dis[edge[i].to]>dis[u]+edge[i].cost)
                {
                    dis[edge[i].to]=dis[u]+edge[i].cost;
                    if(!vis[edge[i].to])
                    {
                        vis[edge[i].to]=1;
                        q.push(edge[i].to);
                    }
                    pre[edge[i].to]=u;
                    fpre[edge[i].to]=i;
                }
            }
        }
        if(dis[t]>=INF)return false;
        return true;
    }
    int main()
    {
        int i,j;
        while(~scanf("%d%d",&n,&m))
        {
            if(!n&&!m)break;
            for(i=0;i<n;i++)
                scanf("%s",map[i]);
            makemap();
            int ans=0;
            while(spfa(s,t))
            {
                int minflow=INF;
                for(i=t;i!=0;i=pre[i])
                {
                    if(minflow>edge[fpre[i]].v)
                        minflow=edge[fpre[i]].v;
                }
                ans+=minflow*dis[t];
                for(i=t;i!=0;i=pre[i])
                {
                    edge[fpre[i]].v-=minflow;
                    edge[edge[fpre[i]].flag].v+=minflow;
                }
            }
            printf("%d
    ",ans);
        }
    }

    km:

    #include<stdio.h>
    #include<string.h>
    #include<algorithm>
    #define INF 99999999
    #define maxn 105
    using namespace std;
    struct node
    {
        int x;
        int y;
    }h[maxn],m[maxn];
    char g[maxn][maxn];
    int map[maxn][maxn],pr[maxn],pl[maxn],visr[maxn],visl[maxn],match[maxn],slack[maxn];
    int col,row;
    void init(int x)
    {
        int i,j;
        for(i=0;i<=x;i++)
            for(j=0;j<=x;j++)
                if(i==j)map[i][j]=0;
                else map[i][j]=INF;
    }
    int dfs(int u,int n)
    {
        int i,j;
        visl[u]=1;
        for(i=0;i<n;i++)
        {
            if(!visr[i])
            {
                int val=pl[u]+pr[i]-map[u][i];
                if(val==0)
                {
                    visr[i]=1;
                    if(match[i]==-1||dfs(match[i],n))
                    {
                        match[i]=u;
                        return 1;
                    }
                }
                if(val>0&&val<slack[i])
                    slack[i]=val;
            }
        }
        return 0;
    }
    int km(int n)
    {
        int i,j;
        memset(pr,0,sizeof(pr));
        memset(match,-1,sizeof(match));
        for(i=0;i<n;i++)
            pl[i]=INF;
        for(i=0;i<n;i++)
        {
            for(j=0;j<n;j++)
                slack[j]=INF;
            while(1)
            {
                memset(visr,0,sizeof(visr));
                memset(visl,0,sizeof(visl));
                if(dfs(i,n))break;
                int k=INF;
                for(j=0;j<n;j++)
                {
                    if(!visr[j]&&slack[j]<k)
                        k=slack[j];
                }
                for(j=0;j<n;j++)
                {
                    if(visl[j])
                        pl[j]-=k;
                    if(visr[j])
                        pr[j]+=k;
                }
            }
        }
        int res=0;
        for(i=0;i<n;i++)
        {
            res+=map[match[i]][i];
        }
        return res;
    }
    int main()
    {
        int i,j;
        while(scanf("%d%d",&row,&col)!=EOF)
        {
            if(row==0&&col==0)
                break;
            int count1=0,count2=0;
            for(i=0;i<row;i++)
                scanf("%s",g[i]);
            for(i=0;i<row;i++)
                for(j=0;j<col;j++)
                {
                    if(g[i][j]=='H')
                    {
                        h[count1].x=i;h[count1++].y=j;
                    }
                    else if(g[i][j]=='m')
                    {
                        m[count2].x=i;m[count2++].y=j;
                    }
                }
            init(count1);
            for(i=0;i<count1;i++)
                for(j=0;j<count2;j++)
                {
                    map[i][j]=-(abs(h[i].x-m[j].x)+abs(h[i].y-m[j].y));
                }
            printf("%d
    ",-km(count1));
        }
    }
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  • 原文地址:https://www.cnblogs.com/sweat123/p/4900569.html
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