Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2
.
Note: m and n will be at most 100.
class Solution { public: int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<vector<long long>> dp; for(unsigned int i=0;i<obstacleGrid.size();i++){ vector<long long>row; for(unsigned int j=0;j<obstacleGrid[0].size();j++){ row.push_back(0); } dp.push_back(row); } dp[0][0]=1; for(unsigned int i=0;i<obstacleGrid.size();i++){ for(unsigned int j=0;j<obstacleGrid[0].size();j++){ if(!obstacleGrid[i][j]){ if(i>0)dp[i][j]+=dp[i-1][j]; if(j>0)dp[i][j]+=dp[i][j-1]; } else dp[i][j]=0; } } return dp[obstacleGrid.size()-1][obstacleGrid[0].size()-1]; } };