u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 40905 Accepted Submission(s): 18610
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
Source
#include<iostream> #include<stdio.h> using namespace std; int main() { printf("n e - ----------- "); double ans=2.5; double tmp=2; printf("0 1 "); printf("1 2 "); printf("2 2.5 "); for(int i=3;i<10;i++) { tmp*=i; ans+=1/tmp; printf("%d %.9lf ",i,ans); } }
水题,注意精度就行。