Contains Duplicate III
问题:Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k.
思路:
二分查找树
我的代码:
public class Solution { public boolean containsNearbyAlmostDuplicate(int[] nums, int k, int t) { if(nums==null || nums.length==0 || k<=0) return false; TreeSet<Integer> tree = new TreeSet<Integer>(); for(int i=0; i<nums.length; i++) { Integer floor = tree.floor(nums[i]+t); Integer ceil = tree.ceiling(nums[i]-t); if((floor!=null && floor>=nums[i]) || (ceil!=null && ceil<=nums[i])) return true; tree.add(nums[i]); if(i >= k) tree.remove(nums[i-k]); } return false; } }
学习之处:
- 之前没注意到java中还有TreeSet这样一个集合,实现的机理是红黑树,所以查找和删除的时间复杂度O(logk),该API在查找和删除上有巨大的优势啊。在涉及到查找历史数据问题的时候,考虑到此
- 该题的思路是维持一个大小为k的二分查找树