• 【HackerRank】Service Lane


     Calvin is driving his favorite vehicle on the 101 freeway. He notices that the check engine light of his vehicle is on, and he wants to service it immediately to avoid any risks. Luckily, a service lane runs parallel to the highway. The length of the highway and the service lane is N units. The service lane consists of N segments of unit length, where each segment can have different widths.

    Calvin can enter into and exit from any segment. Let's call the entry segment as index i and the exit segment as index j. Assume that the exit segment lies after the entry segment(j>i) and i ≥ 0. Calvin has to pass through all segments from index i to indexj (both inclusive).

    Calvin has three types of vehicles - bike, car and truck, represented by 1, 2 and 3 respectively. These numbers also denote the width of the vehicle. We are given an array width[] of length N, where width[k] represents the width of kth segment of our service lane. It is guaranteed that while servicing he can pass through at most 1000 segments, including entry and exit segments.

    • If width[k] is 1, only the bike can pass through kth segment.

    • If width[k] is 2, the bike and car can pass through kth segment.

    • If width[k] is 3, any of the bike, car or truck can pass through kth segment.

    Given the entry and exit point of Calvin's vehicle in the service lane, output the type of largest vehicle which can pass through the service lane (including the entry & exit segment)

    Input Format
    The first line of input contains two integers - N & T, where N is the length of the freeway, and T is the number of test cases. The next line has N space separated integers which represents the width array.

    T test cases follow. Each test case contains two integers - i & j, where i is the index of segment through which Calvin enters the service lane and j is the index of the lane segment where he exits.

    Output Format
    For each test case, print the number that represents the largest vehicle type that can pass through the service lane.

    Note
    Calvin has to pass through all segments from index i to indexj (both inclusive).

    Constraints
    2 <= N <= 100000
    1 <= T <= 1000
    0 <= i < j < N
    2 <= j-i+1 <= min(N,1000)
    1 <= width[k] <= 3, where 0 <= k < N


    题解:

     1 import java.io.*;
     2 import java.util.*;
     3 import java.text.*;
     4 import java.math.*;
     5 import java.util.regex.*;
     6 
     7 public class Solution {
     8    static int Service_Lane(int[] lane,int enter,int exit){
     9        int minimal = Integer.MAX_VALUE;
    10        for(int i = enter;i<=exit;i++)
    11            minimal = Math.min(minimal, lane[i]);
    12        return minimal;
    13    }
    14 
    15  public static void main(String[] args) {
    16         Scanner in = new Scanner(System.in);
    17         int n;
    18         n = in.nextInt();
    19         int t;
    20         t = in.nextInt();
    21         int[] lane = new int[n];
    22         for(int i = 0;i < n;i++){
    23             lane[i] = in.nextInt(); 
    24         }
    25         for(int i = 0;i < t;i++){
    26             int enter = in.nextInt();
    27             int exit = in.nextInt();
    28             int mini = Service_Lane(lane, enter, exit);
    29             if(mini >= 3)
    30                 System.out.println(3);
    31             else if(mini >= 2)
    32                 System.out.println(2);
    33             else
    34                 System.out.println(1);
    35         }
    36    }
    37 }
  • 相关阅读:
    Use Eclipse to develop groovy[docs.codehaus.org]
    Map.putAll方法——追加另一个Map对象到当前Map集合(转)
    限制某个进程只能在某个CPU上运行
    Java实现蓝桥杯 算法提高 身份证号码升级
    Java实现蓝桥杯 算法提高 身份证号码升级
    Java实现蓝桥杯 算法提高 身份证号码升级
    Java实现蓝桥杯 算法提高 身份证号码升级
    Java蓝桥杯 算法训练 复数归一化
    Java实现 蓝桥杯 算法提高 最大乘积
    Java实现 蓝桥杯 算法训练 p1103
  • 原文地址:https://www.cnblogs.com/sunshineatnoon/p/3874862.html
Copyright © 2020-2023  润新知