• leetcode — validate-binary-search-tree


    import apple.laf.JRSUIUtils;
    
    /**
     * Source : https://oj.leetcode.com/problems/validate-binary-search-tree/
     *
     *
     *
     * Given a binary tree, determine if it is a valid binary search tree (BST).
     *
     * Assume a BST is defined as follows:
     *
     * The left subtree of a node contains only nodes with keys less than the node's key.
     * The right subtree of a node contains only nodes with keys greater than the node's key.
     * Both the left and right subtrees must also be binary search trees.
     *
     * confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.
     *
     * OJ's Binary Tree Serialization:
     *
     * The serialization of a binary tree follows a level order traversal, where '#' signifies
     * a path terminator where no node exists below.
     *
     * Here's an example:
     *
     *    1
     *   / 
     *  2   3
     *     /
     *    4
     *     
     *      5
     *
     * The above binary tree is serialized as "{1,2,3,#,#,4,#,#,5}".
     */
    public class ValidateBinarySearchTree {
    
        public boolean validate (TreeNode root) {
            return isValid(root, Integer.MIN_VALUE, Integer.MAX_VALUE);
        }
    
        /**
         * 先判断根节点是否满足 root.value > min && root.value < max,如果满足,再递归判断左右子树
         *
         * @param root
         * @param min
         * @param max
         * @return
         */
        public boolean isValid (TreeNode root, int min, int max) {
            if (root == null) {
                return true;
            }
            if (root.value > max || root.value < min) {
                return false;
            }
            return isValid(root.leftChild, min, root.value) && isValid(root.rightChild, root.value, max);
        }
    
        /**
         * 二叉搜索树的中序遍历结果是单调递增的,所以中序遍历的时候当前节点值大于上一个节点的值
         * 注意:这里每次递归会改变lastMax的值,需要保存下来,所以这里需要一个类似指针的变量,不能直接使用Integer等包装类型
         *
         * @param root
         * @param lastMax
         * @return
         */
        public boolean isValidByInorder (TreeNode root, TreeNode lastMax) {
            if (root == null) {
                return true;
            }
            if (!isValidByInorder(root.leftChild, lastMax)) {
                return false;
            }
            if (lastMax.value >= root.value) {
                return false;
            }
            lastMax.value = root.value;
            return isValidByInorder(root.rightChild, lastMax);
        }
        public boolean validate1 (TreeNode root) {
            TreeNode lastMax = new TreeNode(Integer.MIN_VALUE);
            return isValidByInorder(root, lastMax);
        }
    
    
    
        public TreeNode createTree (char[] treeArr) {
            TreeNode[] tree = new TreeNode[treeArr.length];
            for (int i = 0; i < treeArr.length; i++) {
                if (treeArr[i] == '#') {
                    tree[i] = null;
                    continue;
                }
                tree[i] = new TreeNode(treeArr[i]-'0');
            }
            int pos = 0;
            for (int i = 0; i < treeArr.length && pos < treeArr.length-1; i++) {
                if (tree[i] != null) {
                    tree[i].leftChild = tree[++pos];
                    if (pos < treeArr.length-1) {
                        tree[i].rightChild = tree[++pos];
                    }
                }
            }
            return tree[0];
        }
    
    
    
        private class TreeNode {
            TreeNode leftChild;
            TreeNode rightChild;
            int value;
    
            public TreeNode(int value) {
                this.value = value;
            }
    
            public TreeNode() {
            }
        }
    
        public static void main(String[] args) {
            ValidateBinarySearchTree validateBinarySearchTree = new ValidateBinarySearchTree();
            System.out.println(validateBinarySearchTree.validate(validateBinarySearchTree.createTree(new char[]{'1','2','3','#','#','4','#','#','5'})) + "-------false");
            System.out.println(validateBinarySearchTree.validate(validateBinarySearchTree.createTree(new char[]{'3','1','4'})) + "-------true");
            System.out.println(validateBinarySearchTree.validate(validateBinarySearchTree.createTree(new char[]{'3','2','4','1','#'})) + "-------true");
    
            System.out.println();
            System.out.println(validateBinarySearchTree.validate1(validateBinarySearchTree.createTree(new char[]{'1','2','3','#','#','4','#','#','5'})) + "-------false");
            System.out.println(validateBinarySearchTree.validate1(validateBinarySearchTree.createTree(new char[]{'3','1','4'})) + "-------true");
            System.out.println(validateBinarySearchTree.validate1(validateBinarySearchTree.createTree(new char[]{'3','2','4','1','#'})) + "-------true");
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/sunshine-2015/p/7791515.html
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