• Java Trie字典树,前缀树


    Trie查询每个条目的时间复杂度,和字典中一共有多少条无关。

    时间复杂度为O(W)

    w为查询单词的长度

    import java.util.TreeMap;
    
    public class Trie {
    	private class Node {
    		public boolean isWord;
    		public TreeMap<Character, Node> next;
    
    		public Node(boolean isWord) {
    			this.isWord = isWord;
    			next = new TreeMap<>();
    		}
    
    		public Node() {
    			this(false);
    		}
    	}
    
    	private Node root;
    	private int size;
    
    	public Trie() {
    		root = new Node();
    		size = 0;
    	}
    
    	// 返回Trie中存储的单词数量
    	public int getSize() {
    		return size;
    	}
    
    	// 向Trie中添加一个新的单词word
    	public void add(String word) {
    		Node cur = root;
    		for (int i = 0; i < word.length(); i++) {
    			char c = word.charAt(i);
    			if (cur.next.get(c) == null)
    				cur.next.put(c, new Node());
    			cur = cur.next.get(c);
    		}
    		if (!cur.isWord) {
    			cur.isWord = true;
    			size++;
    		}
    	}
        
    	//查询单词word是否在Trie中
    	public boolean contains(String word){
    		Node cur=root;
    		for (int i = 0; i < word.length(); i++) {
    			char c=word.charAt(i);
    			if(cur.next.get(c)==null)
    				return false;
    			cur=cur.next.get(c);
    		}
    		return cur.isWord;
    	}
    //查询是否在Trie中有单词以prefix为前缀
    	public boolean isPrefix(String prefix) {
    		Node cur=root;
    		for (int i = 0; i < prefix.length(); i++) {
    			char c=prefix.charAt(i);
    			if(cur.next.get(c)==null)
    				return false;
    			cur=cur.next.get(c);
    		}
    		return true;
    	}
    }

    测试:

    public class Main {
    	public static void Main(String[] args){
    		 System.out.println("Pride and Prejudice");
             ArrayList<String> words=new ArrayList<>();
             if(FileOperation.readFile("pride-and-prejudice.txt", words)){
    
                 long startTime = System.nanoTime();
                 BSTSet<String> set=new BSTSet<String>();
                 for(String word:words)
                	 set.add(word);
                 for(String word:words)
                	 set.contains(word);
    
                 long endTime = System.nanoTime();
                 double time = (endTime - startTime) / 1000000000.0;
    
                 System.out.println("Total different words: " + set.getSize());
                 System.out.println("BSTSet: " + time + " s");
                 
                 startTime = System.nanoTime();
    
                 Trie trie = new Trie();
                 for(String word: words)
                     trie.add(word);
    
                 for(String word: words)
                     trie.contains(word);
    
                 endTime = System.nanoTime();
    
                 time = (endTime - startTime) / 1000000000.0;
    
                 System.out.println("Total different words: " + trie.getSize());
                 System.out.println("Trie: " + time + " s");
             }
    	}
    }
    

      search可以搜索文字或正则表达式字符串,字符串只包含字母.或者a-z.

    import java.util.TreeMap;
    
    public class WordDictionary {
    	public class Node{
    	private boolean isWord;
    	public TreeMap<Character, Node> next;
    	public Node(boolean isWord){
    		this.isWord=isWord;
    		next=new TreeMap<>();
    	}
    		public Node() {
    			this(false);
    		}
    	}
    	 private  Node root; 
    	 
         public WordDictionary(){
        	 root =new Node();
         }
    
    	public void addWord(String word) {
    		Node cur = root;
    		for (int i = 0; i < word.length(); i++) {
    			char c = word.charAt(i);
    			if (cur.next.get(c) == null)
    				cur.next.put(c, new Node());
    			cur = cur.next.get(c);
    		}
    		cur.isWord = true;
    	}
         public boolean search(String word){
        	 return match(root, word, 0);
         }
         private boolean match(Node node,String word,int index) {
    		if(index==word.length()) 
    			return node.isWord;
    		char c=word.charAt(index);
    		if(c!='.'){
    			if(node.next.get(c)==null)
    				return false;
    			return match(node.next.get(c), word, index+1);
    		}else{
    			for (char nextChar :node.next.keySet()) {
    				if(match(node.next.get(nextChar), word, index+1))
    					return true;
    			}
    			return false;	
    		}
    	}
    }
    

      Trie和映射

    import java.util.TreeMap;
    
    public class MapSum {
    	private class Node{
    		public boolean isWord;
    		public int value;
    		
    		public TreeMap<Character, Node> next;
    		public Node(int value){
    			this.value=value;
    			next=new TreeMap<>();
    		}
    		public Node(){this(0);}
    	}
    	private Node root;
    	public MapSum() {
    		root=new Node();
    	}
    	public void insert(String word,int val){
    		Node cur=root;
    		for (int i = 0; i < word.length(); i++) {
    			char c=word.charAt(i);
    			if(cur.next.get(c)==null)
    				cur.next.put(c,new Node());
    			cur=cur.next.get(c);
    		}
         cur.value=val;
    	}
    	public int sum(String prefix){
    		Node cur=root;
    		for (int i = 0; i < prefix.length(); i++) {
    			char c=prefix.charAt(i);
    			if(cur.next.get(c)==null)
    				return 0;
    			cur=cur.next.get(c);
    		}
    	    return sum(cur);	
    	}
    	private int sum(Node node){
    		if(node.next.size()==0)
    			return node.value;
    		int res=node.value;
    		for (char c:node.next.keySet()) 
    			res+=sum(node.next.get(c));
    		return res;
    	}
    }
    

      

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  • 原文地址:https://www.cnblogs.com/sunliyuan/p/10742774.html
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