• 在LINQ中实现多条件联合主键LEFT JOIN


    我昨天遇到一个LINQ下使用多条件比对产生LEFT JOIN的问题,经过深入研究,终于解决了,也让我学到了新的东西,特地拿来分享。

    实例:有一张库存异常变更视图KCYD,仓库ID[Ckid]和物品ID[SpxxId]是该视图的唯一约束。有一张物品表ITEM,物品ID[ITEM_ID]是主键。还有一张表是统计正品和次品库存数量的视图SPKC,仓库ID[CKID]和物品ID[SPXXID]是该视图的唯一约束。现在的要求是根据条件查询库存异常变更的物品信息,即要求KCYD左联ITEM再左联SPKC。KCYD和ITEM的公共字段是物品ID,KCYD和SPKC的公共字段是仓库ID和物品ID。

    我原先想到的写法如下:

     var query = from k in DBContext.KCYD
                 join i in DBContext.ITEM
                 on k.SPXXID equals i.ITEM_ID into g
                 from gc in g.DefaultIfEmpty()
                 join s in DBContext.SPKC
                 on k.SpxxId equals s.SPXXID into g1
                 from gc1 in g1.DefaultIfEmpty()
                 where k.Ckid == gc1.CKID
                 select new
                 {
                     ... ...                            
                 };

    但是生成的SQL语句,KCYD和ITEM表是LEFT OUTER JOIN的,但是联SPKC表却变成了INNER JOIN,这是为啥呢,经过一番折腾下来,发现问题出在where k.Ckid == gc1.CKID,如果把这个条件去掉的话,那就成了LEFT OUTER JOIN了,然后我就在想这个条件应该放在哪呢,LINQ里面到底支不支持联合主键的问题呢,在网上搜了半天,发现可以用 on new {字段1,字段2} equals new {字段1,字段2} into g的方法,于是修改代码如下:

     var query = from k in DBContext.KCYD
                 join i in DBContext.ITEM
                 on k.SPXXID equals i.ITEM_ID into g
                 from gc in g.DefaultIfEmpty()
                 join s in DBContext.SPKC
                 on new {k.SpxxId,k.Ckid} equals new {s.SPXXID,s.CKID} into g1
                 from gc1 in g1.DefaultIfEmpty()
                 select new
                 {
                     ... ...                            
                 };

    但是很不给力的是这样居然提示错误:The type arguments cannot be inferred from the query.
    简直就是杯具,难道LINQ不支持这样搞?唉,在我绝望的时候同事为我看出了端倪,原来equals两边的参数字段名的大小写必须完全匹配。即完整代码如下:

     var query = from k in DBContext.KCYD
                 join i in DBContext.ITEM
                 on k.SPXXID equals i.ITEM_ID into g
                 from gc in g.DefaultIfEmpty()
                 join s in DBContext.SPKC
                 on new {SPXXID=k.SpxxId,CKID=k.Ckid} equals new {s.SPXXID,s.CKID} into g1
                 from gc1 in g1.DefaultIfEmpty()
                 select new
                 {
                     ... ...                            
                 };

    大功告成!

    转载:

    http://www.cnblogs.com/guyun/archive/2012/09/14/2684529.html

  • 相关阅读:
    Codeforces Round #598 (Div. 3)(全)
    Codeforces Round #597 (Div. 2) F
    Codeforces Round #597 (Div. 2) D Shichikuji and Power Grid (MST)
    ACM bitset
    Codeforces Round #592 (Div. 2) E. Minimizing Difference
    Educational Codeforces Round 74 (Rated for Div. 2)D. AB-string
    Educational Codeforces Round 74 (Rated for Div. 2) tandard Free2play
    2018南昌邀请赛网络赛 单调栈 I
    rmq问题
    poj 3259Wormholes
  • 原文地址:https://www.cnblogs.com/sunice/p/6884010.html
Copyright © 2020-2023  润新知