• Spring的数据库开发


    Spring的数据库开发

    步骤

    1.创建User类

    import lombok.AllArgsConstructor;
    import lombok.Data;
    import lombok.NoArgsConstructor;

    @Data
    @AllArgsConstructor //有参
    @NoArgsConstructor //无参
    public class User {
        private int id;
        private String username;
        private String password;
    }

    2.UserDao和UserImpl

    mport com.sty.pojo.User;

    import java.util.List;

    public interface UserDao {
       void addUser(User user);
       void deleteUser(int id);
       int updateUser(User user);
       User queryUserByID(int id);
       List<User> queryUser();
    }
    import com.sty.pojo.User;
    import org.springframework.jdbc.core.BeanPropertyRowMapper;
    import org.springframework.jdbc.core.JdbcTemplate;
    import org.springframework.jdbc.core.RowMapper;

    import java.util.List;

    public class UserDaoImpl implements UserDao {
       private JdbcTemplate jdbcTemplate;

       //为了Spring 注入
       public void setJdbcTemplate(JdbcTemplate jdbcTemplate) {
           this.jdbcTemplate = jdbcTemplate;
      }

       //添加用户
       public void addUser(User user) {

           String sql = "insert into user(username,password) values (?,?)";

          Object[] obj= new Object[]{
                   user.getUsername(),
                  user.getPassword()
          };
              jdbcTemplate.update(sql,obj);

      }

       //删除用户信息
       public void deleteUser(int id) {
           String sql ="delete from user where id=?";
           jdbcTemplate.update(sql,id);
      }


       //修改用户信息
       public  int updateUser(User user) {
           String sql ="update user set username=?,password=? where id=?";

           Object[] obj =new Object[]{
                 user.getUsername(),
                   user.getPassword(),
                   user.getId()
          };

           int num = jdbcTemplate.update(sql, obj);
           return num;
      }


       //查询用户
       public User queryUserByID(int id) {
           String sql="select * from day10.user where id=?";

          RowMapper<User> RowMapper = new BeanPropertyRowMapper<User>(User.class);

           User user = jdbcTemplate.queryForObject(sql, RowMapper,id);
           return user;
      }

       public List<User> queryUser() {

           String sql = "select * from user";
           RowMapper<User> mapper = new BeanPropertyRowMapper<User>(User.class);

           List<User> list = jdbcTemplate.query(sql,mapper);
           return list;
      }
    }

    3.applicationContext.xml

    <?xml version="1.0" encoding="UTF8"?>
    <!--suppress ALL -->
    <beans xmlns="http://www.springframework.org/schema/beans"
          xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
          xsi:schemaLocation="http://www.springframework.org/schema/beans
           https://www.springframework.org/schema/beans/spring-beans.xsd">

       <!--1.配置数据源-->
       <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
           <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
           <property name="url" value="jdbc:mysql://localhost:3306/day10"/>
           <property name="username" value="root"/>
           <property name="password" value="root"/>
       </bean>

       <!--2.配置JDBC模板-->
       <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate">
           <property name="dataSource" ref="dataSource"/>
       </bean>

       <!--将jdbcTemplate注入userDao实例中-->

     <bean id="userDao" class="com.sty.dao.UserDaoImpl">
         <property name="jdbcTemplate" ref="jdbcTemplate"/>
     </bean>
    </beans>

    4.测试

    mport com.sty.dao.UserDao;
    import com.sty.pojo.User;
    import org.junit.Test;
    import org.springframework.context.support.ClassPathXmlApplicationContext;

    import java.util.List;

    public class TestUSer {
      @Test
       public  void QueryTest(){

          ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
          UserDao userDao = (UserDao) context.getBean("userDao");

          User user = userDao.queryUserByID(1);
          System.out.println(user);
      }


      @Test
      public void addTest(){

         ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

       UserDao user = (UserDao) context.getBean("userDao");

         User user1 = new User();
         user1.setUsername("麻子");
         user1.setPassword("123546");

         user.addUser(user1);
      }


      @Test
       public void updateTest(){

          ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

          UserDao user = (UserDao) context.getBean("userDao");


          User user1 = new User();
          user1.setUsername("李四喜");
          user1.setPassword("123546456");
          user1.setId(1);

          int i = user.updateUser(user1);
          if(i>0){
              System.out.println("修改成功");
          }else{
              System.out.println("修改失败");
          }

      }


      @Test
       public void queryTest(){

          ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

          UserDao user = (UserDao) context.getBean("userDao");
          List<User> list = user.queryUser();
          for (User user1 : list) {
              System.out.println(user1);
          }

      }


    }

    5.注意出现下面的错误信息,可以把applicationContext.xml中的UTF-8,改为UTF8

    org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 8 in XML document from class path resource [applicationContext.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 8; columnNumber: 11; 2 字节的 UTF-8 序列的字节 2 无效。

    6.依赖

     

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  • 原文地址:https://www.cnblogs.com/stydejava/p/14072515.html
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