• [Swift]LeetCode104. 二叉树的最大深度 | Maximum Depth of Binary Tree


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    Given a binary tree, find its maximum depth.

    The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

    Note: A leaf is a node with no children.

    Example:

    Given binary tree [3,9,20,null,null,15,7],

        3
       / 
      9  20
        /  
       15   7

    return its depth = 3.


     给定一个二叉树,找出其最大深度。

    二叉树的深度为根节点到最远叶子节点的最长路径上的节点数。

    说明: 叶子节点是指没有子节点的节点。

    示例:
    给定二叉树 [3,9,20,null,null,15,7]

        3
       / 
      9  20
        /  
       15   7

    返回它的最大深度 3 。


     32ms

     1 /**
     2  * Definition for a binary tree node.
     3  * public class TreeNode {
     4  *     public var val: Int
     5  *     public var left: TreeNode?
     6  *     public var right: TreeNode?
     7  *     public init(_ val: Int) {
     8  *         self.val = val
     9  *         self.left = nil
    10  *         self.right = nil
    11  *     }
    12  * }
    13  */
    14 class Solution {
    15     func maxDepth(_ root: TreeNode?) -> Int {
    16         //将树分为左子树和右子树两部分,左右子树中深度最大的即为该树结构的深度。
    17         var max:Int = 0
    18         if root != nil
    19         {
    20             max += 1
    21             var maxLeft:Int = maxDepth(root!.left)
    22             var maxRight:Int = maxDepth(root!.right)
    23             max += (maxLeft > maxRight ? maxLeft : maxRight)
    24         }
    25         return max   
    26     }
    27 }

     24ms

     1 /**
     2  * Definition for a binary tree node.
     3  * public class TreeNode {
     4  *     public var val: Int
     5  *     public var left: TreeNode?
     6  *     public var right: TreeNode?
     7  *     public init(_ val: Int) {
     8  *         self.val = val
     9  *         self.left = nil
    10  *         self.right = nil
    11  *     }
    12  * }
    13  */
    14 class Solution {
    15     
    16     func maxDepth(_ root: TreeNode?) -> Int {
    17         
    18         guard let node = root else {
    19             return 0
    20         }
    21         
    22         return 1 + max(maxDepth(node.left), maxDepth(node.right))
    23         
    24     }
    25 }

    28ms

     1 /**
     2  * Definition for a binary tree node.
     3  * public class TreeNode {
     4  *     public var val: Int
     5  *     public var left: TreeNode?
     6  *     public var right: TreeNode?
     7  *     public init(_ val: Int) {
     8  *         self.val = val
     9  *         self.left = nil
    10  *         self.right = nil
    11  *     }
    12  * }
    13  */
    14 class Solution {
    15     
    16     func maxDepth(_ root: TreeNode?) -> Int {
    17         
    18         guard let node = root else {
    19             return 0
    20         }
    21         
    22         var depth: Int = 0
    23         var stack: [TreeNode] = [node]
    24         
    25         while !stack.isEmpty {
    26             
    27             var currentStackSize = stack.count
    28             
    29             while currentStackSize > 0 {
    30                 
    31                 let lastNode = stack.popLast()!
    32                 
    33                 if let last = lastNode.left {
    34                     stack.insert(last, at: 0)
    35                 }
    36                 
    37                 if let right = lastNode.right {
    38                     stack.insert(right, at: 0)
    39                 }
    40                 
    41                 currentStackSize -= 1
    42             }
    43             
    44             depth += 1
    45         }
    46         
    47         return depth
    48     }
    49 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/9701156.html
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