• [Swift]LeetCode1239. 串联字符串的最大长度 | Maximum Length of a Concatenated String with Unique Characters


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    Given an array of strings arr. String s is a concatenation of a sub-sequence of arr which have unique characters.

    Return the maximum possible length of s.

    Example 1:

    Input: arr = ["un","iq","ue"]
    Output: 4
    Explanation: All possible concatenations are "","un","iq","ue","uniq" and "ique".
    Maximum length is 4.
    Example 2:

    Input: arr = ["cha","r","act","ers"]
    Output: 6
    Explanation: Possible solutions are "chaers" and "acters".
    Example 3:

    Input: arr = ["abcdefghijklmnopqrstuvwxyz"]
    Output: 26

    Constraints:

    1 <= arr.length <= 16
    1 <= arr[i].length <= 26
    arr[i] contains only lower case English letters.


    给定一个字符串数组 arr,字符串 s 是将 arr 某一子序列字符串连接所得的字符串,如果 s 中的每一个字符都只出现过一次,那么它就是一个可行解。

    请返回所有可行解 s 中最长长度。

    示例 1:

    输入:arr = ["un","iq","ue"]
    输出:4
    解释:所有可能的串联组合是 "","un","iq","ue","uniq" 和 "ique",最大长度为 4。
    示例 2:

    输入:arr = ["cha","r","act","ers"]
    输出:6
    解释:可能的解答有 "chaers" 和 "acters"。
    示例 3:

    输入:arr = ["abcdefghijklmnopqrstuvwxyz"]
    输出:26

    提示:

    1 <= arr.length <= 16
    1 <= arr[i].length <= 26
    arr[i] 中只含有小写英文字母

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  • 原文地址:https://www.cnblogs.com/strengthen/p/11831445.html
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