• [Swift]LeetCode1200. 最小绝对差 | Minimum Absolute Difference


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    Given an array of distinct integers arr, find all pairs of elements in ascending order with the minimum absolute difference of any two elements.

    Example 1:

    Input: arr = [4,2,1,3]
    Output: [[1,2],[2,3],[3,4]]
    

    Example 2:

    Input: arr = [1,3,6,10,15]
    Output: [[1,3]]
    

    Example 3:

    Input: arr = [3,8,-10,23,19,-4,-14,27]
    Output: [[-14,-10],[19,23],[23,27]]
    

    Constraints:

    • 2 <= arr.length <= 10^5
    • -10^6 <= arr[i] <= 10^6

    给你个整数数组 arr,其中每个元素都 不相同。

    请你找到所有具有最小绝对差的元素对,并且按升序的顺序返回。

    示例 1:

    输入:arr = [4,2,1,3]
    输出:[[1,2],[2,3],[3,4]]
    

    示例 2:

    输入:arr = [1,3,6,10,15]
    输出:[[1,3]]
    

    示例 3:

    输入:arr = [3,8,-10,23,19,-4,-14,27]
    输出:[[-14,-10],[19,23],[23,27]]
    

    提示:

    • 2 <= arr.length <= 10^5
    • -10^6 <= arr[i] <= 10^6

    740ms
     1 class Solution {
     2     func minimumAbsDifference(_ arr: [Int]) -> [[Int]] {
     3         let sortArr = arr.sorted()
     4         var minDifference = Int.max;
     5         var last = 0;
     6         var res = [[Int]]()
     7         for i in 0..<sortArr.count {
     8             if i == 0 {
     9                 last = sortArr[0]
    10                 continue
    11             }
    12             
    13             let difference = sortArr[i] - last
    14             if difference == minDifference {
    15                 res.append([last, sortArr[i]])
    16             } else if difference < minDifference {
    17                 res.removeAll()
    18                 minDifference = sortArr[i] - last;
    19                 res.append([last, sortArr[i]])
    20             } else {
    21                 
    22             }
    23             last = sortArr[i]
    24         }
    25         return res
    26     }
    27 }

    744ms

     1 class Solution {
     2     func minimumAbsDifference(_ arr: [Int]) -> [[Int]] {
     3         let sArr = arr.sorted()
     4         
     5         var minDiff = Int.max
     6         var ans: [[Int]] = []
     7         for i in 1 ..< sArr.count {
     8             let aDiff = abs(sArr[i] - sArr[i-1])
     9             if aDiff <= minDiff {
    10                 if aDiff < minDiff {
    11                     minDiff = aDiff
    12                     ans.removeAll()
    13                 }
    14                 ans.append([sArr[i-1], sArr[i]])
    15             }
    16         }
    17         
    18         return ans
    19     }
    20 }

    Runtime: 764 ms

    Memory Usage: 25.1 MB
     1 class Solution {
     2     func minimumAbsDifference(_ arr: [Int]) -> [[Int]] {
     3         var arr = arr
     4         arr.sort()
     5         let n:Int = arr.count
     6         var min_diff:Int = 1_000_000_000
     7         var ans:[[Int]] = [[Int]]()
     8         for i in 0..<(n-1)
     9         {
    10             min_diff = min(min_diff, arr[i + 1] - arr[i])
    11         }
    12         for i in 0..<(n-1)
    13         {
    14             if arr[i + 1] - arr[i] == min_diff
    15             {
    16                 ans.append([arr[i], arr[i + 1]])
    17             }
    18         }
    19         return ans
    20     }
    21 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/11565805.html
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