• [Swift]LeetCode733. 图像渲染 | Flood Fill


    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
    ➤微信公众号:山青咏芝(shanqingyongzhi)
    ➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/
    ➤GitHub地址:https://github.com/strengthen/LeetCode
    ➤原文地址: https://www.cnblogs.com/strengthen/p/10519427.html 
    ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
    ➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
    ★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

    An image is represented by a 2-D array of integers, each integer representing the pixel value of the image (from 0 to 65535).

    Given a coordinate (sr, sc) representing the starting pixel (row and column) of the flood fill, and a pixel value newColor, "flood fill" the image.

    To perform a "flood fill", consider the starting pixel, plus any pixels connected 4-directionally to the starting pixel of the same color as the starting pixel, plus any pixels connected 4-directionally to those pixels (also with the same color as the starting pixel), and so on. Replace the color of all of the aforementioned pixels with the newColor.

    At the end, return the modified image.

    Example 1:

    Input: 
    image = [[1,1,1],[1,1,0],[1,0,1]]
    sr = 1, sc = 1, newColor = 2
    Output: [[2,2,2],[2,2,0],[2,0,1]]
    Explanation: 
    From the center of the image (with position (sr, sc) = (1, 1)), all pixels connected 
    by a path of the same color as the starting pixel are colored with the new color.
    Note the bottom corner is not colored 2, because it is not 4-directionally connected
    to the starting pixel. 

    Note:

    • The length of image and image[0] will be in the range [1, 50].
    • The given starting pixel will satisfy 0 <= sr < image.length and 0 <= sc < image[0].length.
    • The value of each color in image[i][j] and newColor will be an integer in [0, 65535].

    有一幅以二维整数数组表示的图画,每一个整数表示该图画的像素值大小,数值在 0 到 65535 之间。

    给你一个坐标 (sr, sc) 表示图像渲染开始的像素值(行 ,列)和一个新的颜色值 newColor,让你重新上色这幅图像。

    为了完成上色工作,从初始坐标开始,记录初始坐标的上下左右四个方向上像素值与初始坐标相同的相连像素点,接着再记录这四个方向上符合条件的像素点与他们对应四个方向上像素值与初始坐标相同的相连像素点,……,重复该过程。将所有有记录的像素点的颜色值改为新的颜色值。

    最后返回经过上色渲染后的图像。

    示例 1:

    输入: 
    image = [[1,1,1],[1,1,0],[1,0,1]]
    sr = 1, sc = 1, newColor = 2
    输出: [[2,2,2],[2,2,0],[2,0,1]]
    解析: 
    在图像的正中间,(坐标(sr,sc)=(1,1)),
    在路径上所有符合条件的像素点的颜色都被更改成2。
    注意,右下角的像素没有更改为2,
    因为它不是在上下左右四个方向上与初始点相连的像素点。
    

    注意:

    • image 和 image[0] 的长度在范围 [1, 50] 内。
    • 给出的初始点将满足 0 <= sr < image.length和 0 <= sc < image[0].length
    • image[i][j] 和 newColor 表示的颜色值在范围 [0, 65535]内。

    Runtime: 64 ms
    Memory Usage: 19.2 MB
     1 class Solution {
     2     
     3     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {
     4         if image.count == 0 || image[0].count == 0 { return [] }
     5         var image = image
     6         
     7         let curColor = image[sr][sc]
     8         floodFillHelper(&image, sr, sc, curColor, newColor)
     9         
    10         return image
    11     }
    12     
    13     func floodFillHelper(_ image: inout [[Int]], _ sr: Int, _ sc: Int, _ curColor: Int, _ newColor: Int) {
    14         if sr < 0 || sr >= image.count || 
    15         sc < 0 || sc >= image[0].count || 
    16         image[sr][sc] != curColor || image[sr][sc] == newColor{ return }
    17 
    18         image[sr][sc] = newColor
    19 
    20         floodFillHelper(&image, sr-1, sc, curColor, newColor)   
    21         floodFillHelper(&image, sr+1, sc, curColor, newColor)           
    22         floodFillHelper(&image, sr, sc-1, curColor, newColor)   
    23         floodFillHelper(&image, sr, sc+1, curColor, newColor)       
    24     }    
    25 }

    80ms

     1 class Solution {
     2     
     3     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {
     4         if image.count == 0 || image[0].count == 0 { return [] }
     5         var image = image
     6         
     7         let curColor = image[sr][sc]
     8         floodFillHelper(&image, sr, sc, curColor, newColor)
     9         
    10         return image
    11     }
    12     
    13     func floodFillHelper(_ image: inout [[Int]], _ sr: Int, _ sc: Int, _ curColor: Int, _ newColor: Int) {
    14         if sr < 0 || sr >= image.count || sc < 0 || sc >= image[0].count { return }
    15         if image[sr][sc] != curColor || image[sr][sc] == newColor { return }
    16 
    17 
    18         image[sr][sc] = newColor
    19 
    20         for i in -1...1 {
    21             floodFillHelper(&image, sr+i, sc, curColor, newColor)       
    22             floodFillHelper(&image, sr, sc+i, curColor, newColor)       
    23         }    
    24     }    
    25 }

    84ms

     1 class Solution {
     2     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {
     3         let m = image.count
     4         let n = image.first?.count ?? 0
     5         
     6         var image = image
     7         var stack = [[Int]]()
     8         var visited = Set<[Int]>()
     9         stack.append([sr,sc])
    10         let startColor = image[sr][sc]
    11         
    12         while !stack.isEmpty {
    13             let pos = stack.removeLast()
    14             visited.insert(pos)
    15             let vr = pos[0]
    16             let vc = pos[1]
    17             image[vr][vc] = newColor
    18             
    19             let directions = [
    20                 [1, 0],
    21                 [-1, 0],
    22                 [0, 1],
    23                 [0, -1]
    24             ]
    25             
    26             for d in directions {
    27                 let r = vr + d[0]
    28                 let c = vc + d[1]
    29 
    30                 if r < 0 || c < 0 || r >= m || c >= n || image[r][c] != startColor || visited.contains([r,c]) {
    31                     continue
    32                 }
    33                 stack.append([r,c])
    34             }
    35         }
    36         
    37         return image
    38     }
    39 }

    88ms

     1 class Solution {
     2     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {
     3         guard image.count > 0 else { return [] }
     4         var res = image
     5         var queue = [[sr, sc]]
     6         var j = 0
     7         let color = image[sr][sc]
     8         var visited = Set<[Int]>()
     9         while j != queue.count {
    10             let current = queue[j]
    11             j += 1
    12             visited.insert(current)
    13             res[current[0]][current[1]] = newColor
    14             queue += neighbours(image, current, color, visited)
    15         }
    16         return res
    17     }
    18     
    19     func neighbours(_ image: [[Int]], _ p: [Int], _ color: Int, _ visited: Set<[Int]>) -> [[Int]] {
    20         let rows = image.count, cols = image[0].count
    21         let x = p[0], y = p[1]
    22         return [[x-1, y], [x+1, y], [x, y-1], [x, y+1]].filter { !visited.contains($0) && $0[0] >= 0 && $0[0] < rows && $0[1] >= 0 && $0[1] < cols && image[$0[0]][$0[1]] == color }
    23     }
    24 }

    100ms

     1 class Solution {   
     2     func emptyImageGrid(_ image: [[Int]]) -> [[Int]] {
     3         var grid = [[Int]]()
     4         for i in 0..<image.count {
     5             var row = [Int]()
     6             for _ in 0..<image[i].count {
     7                 row.append(0)
     8             }
     9             grid.append(row)
    10         }
    11         return grid
    12     }
    13     func shouldAdd(_ image: [[Int]], _ visited: Set<MAPoint>, _ sr: Int, _ sc: Int, _ desiredColor: Int) -> Bool {
    14         if sr >= 0 && sr < image.count && sc >= 0 && sc < image[sr].count {
    15             // this is a valid point in the graph
    16             if image[sr][sc] == desiredColor && visited.contains(MAPoint(row: sr, col: sc)) == false {
    17                 // this point is the right color and hasn't been visited yet
    18                 return true
    19             }
    20         }
    21         return false
    22     }
    23     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {
    24         let originalColor = image[sr][sc]
    25         var imageGrid = image
    26         var points = [Int]()
    27         var queue = [MAPoint]()
    28         var visited = Set<MAPoint>()
    29         queue.append(MAPoint(row: sr, col: sc))
    30         while let firstPoint = queue.first {
    31             imageGrid[firstPoint.row][firstPoint.col] = newColor
    32             visited.insert(firstPoint)
    33             queue.removeFirst()
    34             // check surroundings
    35             if shouldAdd(image, visited, firstPoint.row, firstPoint.col-1, originalColor) == true {
    36                 // left
    37                 queue.append(MAPoint(row: firstPoint.row, col: firstPoint.col-1))
    38             }
    39             if shouldAdd(image, visited, firstPoint.row, firstPoint.col+1, originalColor) == true {
    40                 // right
    41                 queue.append(MAPoint(row: firstPoint.row, col: firstPoint.col+1))
    42             }
    43             if shouldAdd(image, visited, firstPoint.row-1, firstPoint.col, originalColor) == true {
    44                 // up
    45                 queue.append(MAPoint(row: firstPoint.row-1, col: firstPoint.col))
    46             }
    47             if shouldAdd(image, visited, firstPoint.row+1, firstPoint.col, originalColor) == true {
    48                 // down
    49                 queue.append(MAPoint(row: firstPoint.row+1, col: firstPoint.col))
    50             }
    51         }
    52         return imageGrid
    53     }
    54 }
    55 
    56 struct MAPoint {
    57     let row: Int
    58     let col: Int
    59 }
    60 
    61 extension MAPoint: Hashable {
    62     static func == (lhs: MAPoint, rhs: MAPoint) -> Bool {
    63         return lhs.row == rhs.row && lhs.col == rhs.col
    64     }
    65     func hash(into hasher: inout Hasher) {
    66         hasher.combine(row)
    67         hasher.combine(col)
    68     }
    69 }

    100ms

     1 class Solution {
     2     func floodFill(_ image: [[Int]], _ sr: Int, _ sc: Int, _ newColor: Int) -> [[Int]] {    
     3         var resImage: [[Int]] = image
     4         var oldColor: Int = image[sr][sc]
     5         
     6         guard oldColor != newColor else {
     7             return image
     8         }   
     9         func setNewColor(_ sr: Int, _ sc: Int) {
    10             resImage[sr][sc] = newColor
    11             if sr > 0 && resImage[sr - 1][sc] == oldColor {
    12                 setNewColor(sr - 1, sc)
    13             }
    14             if sr < image.count - 1 && resImage[sr + 1][sc] == oldColor {
    15                 setNewColor(sr + 1, sc)
    16             }
    17             if sc > 0 && resImage[sr][sc - 1] == oldColor {
    18                 setNewColor(sr, sc - 1)
    19             }
    20             if sc < image[0].count - 1 && resImage[sr][sc + 1] == oldColor {
    21                 setNewColor(sr, sc + 1)
    22             }
    23         }       
    24         setNewColor(sr, sc)  
    25         return resImage
    26     }
    27 }
  • 相关阅读:
    各种不同的mq
    24. Swap Nodes in Pairs
    应用中有使用到集群么?多大规模?
    曹工杂谈:用好verbose,Jar包冲突不再难
    曹工杂谈:Java 类加载还会死锁?这是什么情况?
    Linux下使用docker 拉取 vsftpd 镜像搭建 Ftp 服务器,连接 Ftp 时遇到的错误(425 Failed to establish connection)
    曹工杂谈:Linux服务器上,Spring Boot 原地修改 jar 包配置文件/替换class文件,免去重复上传的麻烦
    曹工杂谈:手把手带你读懂 JVM 的 gc 日志
    曹工杂谈:一道阿里面试题,两个线程交替打印奇偶数
    曹工说Tomcat4:利用 Digester 手撸一个轻量的 Spring IOC容器
  • 原文地址:https://www.cnblogs.com/strengthen/p/10519427.html
Copyright © 2020-2023  润新知